Portage Learning CHEM 103 chemistry EXAM A+ GRADE ASSURED COMPLETE SOLUTIONS AND VERIFIED ANSWERS

PORTAGE LEARNING EXAM ms ms




Exam Solution ms




Portage Chemistry 103 Module 1 Exam Study Cartes 20ms ms ms ms ms ms ms ms




26 A+ GRADE ASSURED COMPLETE SOLUTIONS AND VE
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RIFIED ANSWERS (09C21) ms ms




QUESTION 1 ms




Terme
ANSWER

Définition



QUESTION 2 ms




1.2: METRIC SYSTEM - UNIT CONVERSIONS
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ANSWER

1 foot (ft)=12 inches (in) 1 kilogram (kg)=1000 grams (g) 1 pound (lb)=16 ounces (oz) 1 gallon (gal
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)=4 quarts (qt) 1000 milliliters (ml)=1 liter (L) 100 centigrams (cg)=1 gram (g) 10 decimeters (dm)
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=1 meter (m)
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QUESTION 3 ms




The prefixes kilo (= 1000), milli (= 1/1000), centi (= 1/100), and deci (= 1/10)
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ANSWER

are used with any metric unit, such as grams (weight), liters (volume), and meters (distance).
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QUESTION 4 ms




The original quantity and unit (to be converted) are multiplied by a conversion factor
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(which is a fraction made up as follows): New unit (on top) / Old unit (on bottom)
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ANSWER

,48 ounces = ? pounds 48 o z × 1 p o u n d / 16 o z = 3 p o u n d s 4 kilograms = ? grams 4 Kg X
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1000 grams/1kg = 4000 grams 1.) 656 cm x 1 m / 100 cm = 6.56 m 2.) 20 gal x 4 qt / 1 gal = 8
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0 qts 3.) 7820 ml x 1 liter / 1000 ml = 7.82 liters 4.) 36 g x 1000 mg / 1 g = 36000 mg 5.) 25.3 g
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x 10 dc / 1 g = 253 dg 6.) 6.2 m x 1000 mm / 1 m = 6200 mm 7.) 725 l x 1000 ml / 1 liter = 72
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5,000 ml 8.) 56 ft x 12 in / 1 ft = 672 in
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QUESTION 5 ms




1.3: TEMPERATURE CONVERSIONS
ms ms




ANSWER

1.) 132 oC + 273 = 405 oK 2.) 132 oF - 32 x 1.8 = 55.6 oC + 273 = 328.6 oK 3.) 285 oK -
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273 = 12 oC 4.) 60 oC x 1.8 + 32 = 140 oF 5.) 85 oF -
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32 x 1.8 = 29.4 oC 6.) 52 oC + 273 = 325 oK 7.) 32 oC x 1.8 + 32 = 89.6 oF 8.) 412 oK -
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273 = 139 oC x 1.8 + 32 = 282.2 oF
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QUESTION 6 ms




K to °C(°C and K differ by 273)
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ANSWER

K (larger) - 273 = °C (smaller)
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QUESTION 7 ms




°C to K(°C and K differ by 273)
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ANSWER

°C (smaller) + 273 = K (larger)
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QUESTION 8 ms




°F to °C(Subtract 32, and divide by 1.8)
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ANSWER

°F - .8 = °C
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QUESTION 9 ms




°C to °F(Multiply by 1.8, and add 32)
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ANSWER

°C X 1.8 + 32 = °F
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, QUESTION 10 ms




1.4: DENSITY ms




ANSWER

Density represents the mass of a substance in a unit volume of that substance. The density of most
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solids or liquids is expressed in the unit grams per milliliter (or g/ml).
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QUESTION 11 ms




The following equation is used to calculate density if you know the mass (in grams) a
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nd the volume (in milliliters).
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ANSWER

D (g/ml) = M(g) / V(ml) 1.) 35.6 ml = V 1.86 g/ml = D find M = D x V = 1.86 x 35.6 = 66.2 grams
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2.) 13.6 g/ml = D 1000 g = M find V = M / D = .6 = 73.5 ml 3.) 200 ml = V 620 g = M fi
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nd D = M / V = 620 g / 200 ml = 3.10 g/ml
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QUESTION 12 ms




1.5: SIGNIFICANT FIGURES
ms ms




ANSWER

Rules for determining significant figures in a number: All non-
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zero digits are significant. All zeros between or following non-
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zero numbers are significant. Zeros to the left of a decimal or preceding other non-
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zero numbers are not significant. 4326.7 -
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This number contains 5 significant figures (in bold). 400.70 -
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This number contains 5 significant figures (in bold). 0.3267 -
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This number contains 4 significant figures (in bold). 0.0070 -
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This number contains 2 significant figures (in bold). 0.5070 -
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This number contains 4 significant figures (in bold).
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QUESTION 13 ms




In multiplication or division calculations, the result should be rounded off so as to co
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ntain the same number of significant figures as the measurement with the least numb
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er of significant figures.
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ANSWER

Examples: 128..20 = 2.51191 = 2.512 (round off to 4 significant figures because of 51.20) 54.
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06 x 17.0 = 919.02 = 919 (round off to 3 significant figures because of 17.0)
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