Solution Manual For Intro to Chemical Processes Principles, Analysis, Synthesis 2e Regina Murphy

Solution Manual For
Intro to Chemical Processes Principles, Analysis, Synthesis 2e Regina Murphy
Chapters 1-9

Chapter 1 Solutions


Warm-ups
P1.1 Paper bag — agricultural materials
Plastic soda bottle — fossil fuels
Wine glass — minerals


P1.2 minerals, fossil fuels, air, water, agricultural materials
N2 - air
Fe - minerals
C - fossil fuels or agricultural materials
H - water, fossil fuels, or agricultural materials


P1.3 1C3H6 2NH3 3O2 4C3H3N 5H2O

Set 1 = 1
C balance: 4 1 0 4 1
N balance: 2 4 0 2 1
H balance: 6 1 2 2 3 4 2 5 0 5 3
O balance: 2 3 5 0 3 1.5

C3H6 NH3 1.5 O2 C3H3N 3H2O


P1.4 1(NH2)2CO 2O2 3H2O 4NH3 5CO2

let 1 1
N balance: 21   4  0 4  2
C balance: 1   5  0 5  1
H balance: 41  23  3 4  0  3  1
O balance: 1  22  3  25  0 2  0

(NH2)2 CO H2O 2NH3 CO2

P1.5 1NH2CONH2 2C2H6O2 3C3H4O3 4NH3

, let 1 1
N balance: 2 1 4 0 4 2
C balance: 1 2 2 3 3 0 2 2 3 3 1


H balance: 4 1 6 2 4 3 3 4 0 6 2 4 3 2
Solve C H simultaneously 3 1, 2 1
O balance: 1 2 2 3 3 0
1 2( 1) 3(1) 0  check

NH2CONH2 C2H6O2 C3H4O3
2NH3


P1.6 1SiO2 2C 3SiC 4CO

let 1 1
Si balance: 1 3 0 3 1
O balance: 2 1 4 0 4 2
C balance: 2 3 4 0 2 3

SiO2 3C SiC 2 CO


P1.7 Use C, H, O balances to get

25
C8H18  O2  8CO2  9H2O
2


P1.8 1(CH3)3Ga 2NH3 3GaN 4CH4

choose 3 1
Ga: 1 3 0 1 1
C: 3 1 4 0 4 3
H: 9 1 3 2 4 4 0 2 1
N: 2 3 0 check

(CH3)3Ga NH3 GaN 3 CH4


P1.9 1Ca(OH)2 2NH4Cl 3CaCl2 4NH3 5H2O

Ca: 1 3 0
Cl: 2 2 3 0

, N: 2 4 0
O: 2 1 5 0
H: 2 1 4 2 3 4 2 5 0
choose 1 1, solve Ca, Cl, N, O balances:
3 1, 2 2, 4 2, 5 2
check H balance

Ca(OH)2 2 NH4Cl CaCl2 2 NH3 2 H2O

P1.10 1C3H6 2NH3 3O2 4C3H3N 5H2O
choose 1 2
C balance: 3 1 3 4 0 4 2
N balance: 2 4 0 2 2
H balance: 6 1 3 2 3 4 2 5 0 5 6
O balance: 2 3 5 0 3 3

2 C3H6 2 NH3 3 O2 2 C3H3N 6 H2O

P1.11 1C3H5(NO3)3 2CO2 3H2O 4N2 5O2
choose 1 1
C: 3 1 2 0 2 3
H: 5 1 2 3 0 3  5 2
N: 3 1 2 4 0 4  3 2
O: 9 1 2 2 3 2 5 0 5  1 4

5 3 1
C3H5(NO3 )3  3CO2  H2O  N2  O2
2 2 4

P1.12 1(NH4)2PtCl6 2Pt 3NH4Cl 4N2 N5HCl
N balance: 2 1 3 2 4 0
H balance: 8 1 4 3 5 0
Pt balance: 1 2 0
Cl balance: 6 1 3 5 0
Lots of choices for basis: I’ll choose 5 6
solve H and Cl balance simultaneously
1   9 8