SAT math
reflecting across x axis—ANSWER--(x, -y)
reflecting across y axis—ANSWER--(-x, y)
roots—ANSWER--another term for a quadratic's solutions
circle equation central-radius form—ANSWER--(x-h)^2 + (y-k)^2=r^2
center is point (h, k)
circle equation general format—ANSWER--ax^2+by^2+cx+dy+e=0
a and b must be the same coefficients and you must divide/factor to make
them equal 1
-put numbers on left side
-group xs and ys together
-divide left and right side by number all xs and ys share
-take x term coefficient times by 1/2 square it then add to both side of
equation
, -take y term coefficient times by 1/2 square it then add to both side of
equation
-find solutions then done!
when give table for g(x)—ANSWER--just look for where x is in table and it
gives you the y value
when given a quadratic graph and need to find a point—ANSWER--see how
far its "partner point" is away from the axis of symmetry
graph of quadratic with no solution—ANSWER--does not cross x axis
-if can completely factor quadratic equation then has a solution
p(x) - 4—ANSWER--the graph is shifted down 4 units
-if was inside () would shift horizontally
if have 2 ratios—ANSWER--make both of them contain one number that is
of the same value
soh cah toa—ANSWER--can only be used on right triangles
Math model—ANSWER--1) read question
2)write down info given
3)look at answers to see similarities/differences
© 2026 Copyright. All Rights Reserved. This document is
protected by copyright law, Copyrighted By Brittie Donald
reflecting across x axis—ANSWER--(x, -y)
reflecting across y axis—ANSWER--(-x, y)
roots—ANSWER--another term for a quadratic's solutions
circle equation central-radius form—ANSWER--(x-h)^2 + (y-k)^2=r^2
center is point (h, k)
circle equation general format—ANSWER--ax^2+by^2+cx+dy+e=0
a and b must be the same coefficients and you must divide/factor to make
them equal 1
-put numbers on left side
-group xs and ys together
-divide left and right side by number all xs and ys share
-take x term coefficient times by 1/2 square it then add to both side of
equation
, -take y term coefficient times by 1/2 square it then add to both side of
equation
-find solutions then done!
when give table for g(x)—ANSWER--just look for where x is in table and it
gives you the y value
when given a quadratic graph and need to find a point—ANSWER--see how
far its "partner point" is away from the axis of symmetry
graph of quadratic with no solution—ANSWER--does not cross x axis
-if can completely factor quadratic equation then has a solution
p(x) - 4—ANSWER--the graph is shifted down 4 units
-if was inside () would shift horizontally
if have 2 ratios—ANSWER--make both of them contain one number that is
of the same value
soh cah toa—ANSWER--can only be used on right triangles
Math model—ANSWER--1) read question
2)write down info given
3)look at answers to see similarities/differences
© 2026 Copyright. All Rights Reserved. This document is
protected by copyright law, Copyrighted By Brittie Donald
