AQA A-LEVEL PHYSICS Paper 3 Section B Engineering physics QP JUNE 2025
Please write clearly in block capitals.
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Surname
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I declare this is my own work.
A-level
PHYSICS
Paper 3
Section B Engineering physics
Tuesday 17 June 2025 Morning Time allowed: The total time
for both sections of this paper
Materials
is
For this paper you must have:
2 hours. You are advised to
a pencil and a ruler
spend approximately
a scientific calculator
a Data and Formulae Booklet 50 minutes on this section.
a protractor.
Instructions
For Examiner’s Use
Use black ink or black ball-point pen.
Fill in the boxes at the top of this page. Question Mark
Answer all questions. 1
You must answer the questions in the spaces provided. Do 2
IB/M/Jun25/G4006/E7
not write outside the box around each page or on blank
pages. 3
If you need extra space for your answer(s), use the lined pages at 4
the end of this book. Write the question number against your
TOTAL
answer(s).
Do all rough work in this book. Cross through any work you do
not want to be marked.
Show all your working.
Information
The marks for questions are shown in brackets.
The maximum mark for this paper is 35.
You are expected to use a scientific calculator where appropriate.
A Data and Formulae Booklet is provided as a loose insert.
, more : ty rion pa per s. com
for 7 4 0 BC
, 2
Do not
write
Section B outside
box the
Answer all questions in this
section.
0 1 The rotating part of an electric motor is called the rotor.
Figure 1 shows an end view of a rotor turning clockwise due to a driving
torque from the motor. In this question, the clockwise direction is treated
as positive.
Figure 1 Figure 2
The rotor can be brought to rest rapidly by reversing the electrical supply
connections to the motor. Figure 2 shows the rotor at time t = 0 when the
supply connections are reversed.
The rotor then slows down due to a constant anticlockwise retarding
torque so that it stops at time t = t1.
The angular velocity of the rotor at t = 0 is 98.0 rad s−1
clockwise. The applied torque on the rotor at t = 0 is
anticlockwise.
The applied torque produces a constant angular acceleration of −303 rad
s−2. Friction torque is negligible.
0 1 .1 Determine
t1. [2 marks]
t1 = s
for more: tyrionpapers.com
IB/M/
Jun25/7408/3BC
Please write clearly in block capitals.
Centre number Candidate number
Surname
Forename(s)
Candidate signature
I declare this is my own work.
A-level
PHYSICS
Paper 3
Section B Engineering physics
Tuesday 17 June 2025 Morning Time allowed: The total time
for both sections of this paper
Materials
is
For this paper you must have:
2 hours. You are advised to
a pencil and a ruler
spend approximately
a scientific calculator
a Data and Formulae Booklet 50 minutes on this section.
a protractor.
Instructions
For Examiner’s Use
Use black ink or black ball-point pen.
Fill in the boxes at the top of this page. Question Mark
Answer all questions. 1
You must answer the questions in the spaces provided. Do 2
IB/M/Jun25/G4006/E7
not write outside the box around each page or on blank
pages. 3
If you need extra space for your answer(s), use the lined pages at 4
the end of this book. Write the question number against your
TOTAL
answer(s).
Do all rough work in this book. Cross through any work you do
not want to be marked.
Show all your working.
Information
The marks for questions are shown in brackets.
The maximum mark for this paper is 35.
You are expected to use a scientific calculator where appropriate.
A Data and Formulae Booklet is provided as a loose insert.
, more : ty rion pa per s. com
for 7 4 0 BC
, 2
Do not
write
Section B outside
box the
Answer all questions in this
section.
0 1 The rotating part of an electric motor is called the rotor.
Figure 1 shows an end view of a rotor turning clockwise due to a driving
torque from the motor. In this question, the clockwise direction is treated
as positive.
Figure 1 Figure 2
The rotor can be brought to rest rapidly by reversing the electrical supply
connections to the motor. Figure 2 shows the rotor at time t = 0 when the
supply connections are reversed.
The rotor then slows down due to a constant anticlockwise retarding
torque so that it stops at time t = t1.
The angular velocity of the rotor at t = 0 is 98.0 rad s−1
clockwise. The applied torque on the rotor at t = 0 is
anticlockwise.
The applied torque produces a constant angular acceleration of −303 rad
s−2. Friction torque is negligible.
0 1 .1 Determine
t1. [2 marks]
t1 = s
for more: tyrionpapers.com
IB/M/
Jun25/7408/3BC
