ARCIAL 2021-2825
↑
*= 20ms -- 406 Pg
Mi0B = 0.92
=
=288%C
↑
↑F = 98KPa
P5 188KPa
=
T3 T2 + 388K
=
↑=287,151 Pn P3 P2
=
=
- A, SMW
↑1 = 98KPa
12= 15
1c 0,89
=
1.n gw.A PF =
=
.x+ = 98.183 Pa 20m3. s7 · = in 14,44kg/S
=
Rg. T 286.975kg 17.473,15K
-
8,3745.mp17.157
286,975kg+17
Ru
Rg =
= =
M
28.97.18-3kg/mo
↑F
4 +3,15
1 T06
-0.92 =1-
T00
-
2. 450B 1:566 554.5k
-
= -
↓-P 6 =
7
1 -
98.1637.4.
1,4
PsG 188-183
554,5k 473,75k + 484,57m/s
wh
Tx T7 =
+ = =
w
- =
2.1.885
3. Pn=P3 = Pe =
1,5. P1 = 7.5.98KPa= F35KPa
8-1 1.4 I
P2 -
40-1
=
0,89 =
7.5 5,4
-
T2 538,28K
x
- =
T2 T2
-
I -
I
↑
I 287,15
-vivneto-mcp(T2-+1) m(p(55 + -
+h) =
Tn 1,8.100
=
+ +2+1 + Ts
n <p
Balance energetical cambiador decalor: m(hc hs) + m(hs- h2) 0 -
=
im(p(T0-Ts) + m(p(13-+2) 0
=
= T5 T6 + T3- Tz
=
↑5 554,5k + 588K 854,5K
=
=
T4 1.8.106
=
538,28K 287,15 + 854+Th 1.238K
+ -
=
14,44. 1.885
854K
1
-
1
- 1.230k
4.17 =
- 47 0,92 =
88.7831,4-5
is ofre
*
1, Y
=
35.183 -
I
ii
-
5. s =
+
up
TFT
o sond=0
0-5. Chanain
Balanceenergeticalacamaradecombustion: m ci n tul O i w hunzoos(coo. 287,15 #
50O
I
-
Tt T+= +
w 554,5
=
, PARCIAL 2018-2019
A0 0.58m3
=
Po Pox
=
To3 = 1.FOOK
P03 = 0,98P32
1 TO B 6
FTCC
4 5
↑
- -
2 5
PGB
C T T2 Wh
M B
/ I
T81 249K =
7 0.88
=
s=63.4" 8 0.02Wh
=
101 52592Pa/W+1) wc+5 +45k
=
=
=
PO2 Ta
*
= 24
↑
Pos =258K
7 8,86
=
1
Poe 32.952Pa.24 =
+P02 =
= 90.848Pa
6-1
1,4 1
1081
-
24 714, 1 T02 67,33K
=
n 0,86: -
=
-
TO2 TO2
-
I -
1
To1 249
2. Pos = 0.98.P02 = = 5.031,84Pa
-
wTs wc =
-+
-m(p1T02-+xx) m(p)Ton =
- T03) Toh T01 T62+ T03
= =
-
= Ton 249k
=
-
677,33k + 1.t00K,Ton 1.271.67K
=
1.271,67
I
jobo
-
TO O
1
Pon =
238.886, 14Pa
n + 8,88 =
- ·
-
1.4 1
POU
-
O
1, Y -
I
Pos -> 5.831,84
#
s Pos 29.541,5 Pa
As-<pIntos-RgInPos
3. In 735K-28tIn
=
63.45/kgk
-
= 6.805
1.271,67K 238.806,14Pa
i36+
to5
+
1 y7 0,92
-
-
= =
29.547.51.4- 1
POG
-
I 1.4,1
238.006,14
249K-194,44"m/s
T00-wha
4. 560 = - + To =238,2K
2.1.885
⑧
1
M
P0 P0a =
↑88
6I
- 32.952 230.2 1.47;P00 P0 =
= 25.855,3Pa
T8x 24d
TO TG
1 -
105 1
-
F45 T6 11,97K
M+0B
-
1 = - =
=
25035,31.4 7
↓toa
-
1 -
1, 4
29.541,5
100w
we 25+.66m/s
3. T6 = =
+77,9+k = +451 -
+ w =
2.1.885
1.w.A 18,31k as
n = 25.035,34a. 25+,66.0,58
=
n
+
=
28+. 11,97
↑
*= 20ms -- 406 Pg
Mi0B = 0.92
=
=288%C
↑
↑F = 98KPa
P5 188KPa
=
T3 T2 + 388K
=
↑=287,151 Pn P3 P2
=
=
- A, SMW
↑1 = 98KPa
12= 15
1c 0,89
=
1.n gw.A PF =
=
.x+ = 98.183 Pa 20m3. s7 · = in 14,44kg/S
=
Rg. T 286.975kg 17.473,15K
-
8,3745.mp17.157
286,975kg+17
Ru
Rg =
= =
M
28.97.18-3kg/mo
↑F
4 +3,15
1 T06
-0.92 =1-
T00
-
2. 450B 1:566 554.5k
-
= -
↓-P 6 =
7
1 -
98.1637.4.
1,4
PsG 188-183
554,5k 473,75k + 484,57m/s
wh
Tx T7 =
+ = =
w
- =
2.1.885
3. Pn=P3 = Pe =
1,5. P1 = 7.5.98KPa= F35KPa
8-1 1.4 I
P2 -
40-1
=
0,89 =
7.5 5,4
-
T2 538,28K
x
- =
T2 T2
-
I -
I
↑
I 287,15
-vivneto-mcp(T2-+1) m(p(55 + -
+h) =
Tn 1,8.100
=
+ +2+1 + Ts
n <p
Balance energetical cambiador decalor: m(hc hs) + m(hs- h2) 0 -
=
im(p(T0-Ts) + m(p(13-+2) 0
=
= T5 T6 + T3- Tz
=
↑5 554,5k + 588K 854,5K
=
=
T4 1.8.106
=
538,28K 287,15 + 854+Th 1.238K
+ -
=
14,44. 1.885
854K
1
-
1
- 1.230k
4.17 =
- 47 0,92 =
88.7831,4-5
is ofre
*
1, Y
=
35.183 -
I
ii
-
5. s =
+
up
TFT
o sond=0
0-5. Chanain
Balanceenergeticalacamaradecombustion: m ci n tul O i w hunzoos(coo. 287,15 #
50O
I
-
Tt T+= +
w 554,5
=
, PARCIAL 2018-2019
A0 0.58m3
=
Po Pox
=
To3 = 1.FOOK
P03 = 0,98P32
1 TO B 6
FTCC
4 5
↑
- -
2 5
PGB
C T T2 Wh
M B
/ I
T81 249K =
7 0.88
=
s=63.4" 8 0.02Wh
=
101 52592Pa/W+1) wc+5 +45k
=
=
=
PO2 Ta
*
= 24
↑
Pos =258K
7 8,86
=
1
Poe 32.952Pa.24 =
+P02 =
= 90.848Pa
6-1
1,4 1
1081
-
24 714, 1 T02 67,33K
=
n 0,86: -
=
-
TO2 TO2
-
I -
1
To1 249
2. Pos = 0.98.P02 = = 5.031,84Pa
-
wTs wc =
-+
-m(p1T02-+xx) m(p)Ton =
- T03) Toh T01 T62+ T03
= =
-
= Ton 249k
=
-
677,33k + 1.t00K,Ton 1.271.67K
=
1.271,67
I
jobo
-
TO O
1
Pon =
238.886, 14Pa
n + 8,88 =
- ·
-
1.4 1
POU
-
O
1, Y -
I
Pos -> 5.831,84
#
s Pos 29.541,5 Pa
As-<pIntos-RgInPos
3. In 735K-28tIn
=
63.45/kgk
-
= 6.805
1.271,67K 238.806,14Pa
i36+
to5
+
1 y7 0,92
-
-
= =
29.547.51.4- 1
POG
-
I 1.4,1
238.006,14
249K-194,44"m/s
T00-wha
4. 560 = - + To =238,2K
2.1.885
⑧
1
M
P0 P0a =
↑88
6I
- 32.952 230.2 1.47;P00 P0 =
= 25.855,3Pa
T8x 24d
TO TG
1 -
105 1
-
F45 T6 11,97K
M+0B
-
1 = - =
=
25035,31.4 7
↓toa
-
1 -
1, 4
29.541,5
100w
we 25+.66m/s
3. T6 = =
+77,9+k = +451 -
+ w =
2.1.885
1.w.A 18,31k as
n = 25.035,34a. 25+,66.0,58
=
n
+
=
28+. 11,97
