PARCIAL 2018-2019
*
Pamb 9SKPa
⑧
⑧
=
ic
.........
<50 cm Tamb = 288,15K
3
Pare
↑Scre TX 288,15k
=
Wp 3.8355
=
9 1,35g/dm3
=
*
02
k 25=
-
183Nn 7
S
I, ( ( ( )
7.Ecuacion termica de estado: P1 =707.066KPa
pX-mRgT=1RgT 1,35.259,81.288, 15 =
-
*
Pr. A
2. Equilibria mecanico del embolo: PA = PambA + meg + mE
(Ps
= -
Parebl
MMag, Pamb. A
mc 1.0.15-1107.866,74-98.0001
= + mE 22,1kg
=
9,81
*
P2. A
mecanico del embolo:
Fm
=9 +
Equilibria m F
5. 12 Pamb +
=
12 P +
=
=
MMEg /Fm>Pamb. A
P2 107.020 +
=
25.503.0,04 + P2 115.767, 11Pa
=
40,152
4. Balance
energetico: Sistema G+E +M
Eg u m(v)Tz- +y)- ug 45,6847 3835 831,3
= =
+ -
=
Ec =
mgl Ug 2.958,135
=
-M
1kx
=
W = Wp-Wamb &
-
5.2.958,13 m.653,19(42 288,75) =
-
T2 525,91
=
115.16+(V1 + +0.15.0,12) =
m.259,81.T2m 0.02kg
=
101.828x1 m.259,81.288,15 =
12 = 0.0226m3
6.
s=m<p1n/2 -
Rg(n 0.029531n525.9 259.871n175767.1 10,30+1
=
288,15
-
181.828
=
288.51.10,50517+2.969,35
-
x =
= 1 2.969,55
=
, PARCIAL 2019-2828
=(to) = 30ON
x
28cm
j
Pamb = 9SKPa put.2 ste
Tamb 293,15kT2 = 543,15K
=
j
I,((((((((IIIIIIIIII
1
15kg
=
mc
1: 18.783Nm*
3
25cm
T 293,15K
=
y 80 0.25m=
S
x Pg. A
1.Equilibria mecanico del embolo:
m59 i 98,000 + 14+.15 30
P=Pamb + + = + - p1 = 105,212KPa
0.0620,062
imag,Pamb.A.FIs)
2. Ecuacion termica de estado: pX-mRgT =
m
105.212,095.0.0154
=
= m(N2) 18,614g =
296,93.293,15
V +1.0,14.8,25
=
0.0154m3
=
3.Ecuacion termica de estado: p2V2
mRgT2
=mRgT2 =
P2 = P2 =250,946KPa
=
Pz.xy
-
= mRgiz.(20 105.212.0,01543 0,018614.296.93.343.15.V2
=
= =
v2 0.00+=
m
*
x P2.A Fre
4. Equilibria mecanico del embolo: ↑= A(Pz Pamb) mcg
-
-
-
+m 0.062/270.944,132 98.800) 15k9.9,8
=
- -
10.103.0,136
+
imag,Pamb.A.FIs)
(j -ve) y 8,1365 11.935,4N
= =
=
5ug m(v)Tz
= +1)
-
0,018614. [43,87.50
=
=
0g 697,5+5j
=
8
Nexts-atapatorde.
Next.s:-pd-JPd:/PrEd
I
-p.x.((0)
=
6. On 7.585.545+ Wext,g= 7.585.545
8,2
Aug Eg Wext,g 8g 0g 691,5+5 1383,th =
8g 692,1655
= =
= =
+ - =
8. Balance energetics: Sistema G - E + M
Eg Ug
=
697.5+55-
=
697.5755-70,07245 + 92,485 W5 =
-
692,165 -
828.6
tE =
=
16,1245 WF 635,52555
mgx
=
tM
(y3 92,48-
=
=
sim 0.028611,0481n363.15 296.931270.944
pint-Rgin
9. = - = -2,7595.17 50.2.1795.15
+
293,15
-
105.212
*
Pamb 9SKPa
⑧
⑧
=
ic
.........
<50 cm Tamb = 288,15K
3
Pare
↑Scre TX 288,15k
=
Wp 3.8355
=
9 1,35g/dm3
=
*
02
k 25=
-
183Nn 7
S
I, ( ( ( )
7.Ecuacion termica de estado: P1 =707.066KPa
pX-mRgT=1RgT 1,35.259,81.288, 15 =
-
*
Pr. A
2. Equilibria mecanico del embolo: PA = PambA + meg + mE
(Ps
= -
Parebl
MMag, Pamb. A
mc 1.0.15-1107.866,74-98.0001
= + mE 22,1kg
=
9,81
*
P2. A
mecanico del embolo:
Fm
=9 +
Equilibria m F
5. 12 Pamb +
=
12 P +
=
=
MMEg /Fm>Pamb. A
P2 107.020 +
=
25.503.0,04 + P2 115.767, 11Pa
=
40,152
4. Balance
energetico: Sistema G+E +M
Eg u m(v)Tz- +y)- ug 45,6847 3835 831,3
= =
+ -
=
Ec =
mgl Ug 2.958,135
=
-M
1kx
=
W = Wp-Wamb &
-
5.2.958,13 m.653,19(42 288,75) =
-
T2 525,91
=
115.16+(V1 + +0.15.0,12) =
m.259,81.T2m 0.02kg
=
101.828x1 m.259,81.288,15 =
12 = 0.0226m3
6.
s=m<p1n/2 -
Rg(n 0.029531n525.9 259.871n175767.1 10,30+1
=
288,15
-
181.828
=
288.51.10,50517+2.969,35
-
x =
= 1 2.969,55
=
, PARCIAL 2019-2828
=(to) = 30ON
x
28cm
j
Pamb = 9SKPa put.2 ste
Tamb 293,15kT2 = 543,15K
=
j
I,((((((((IIIIIIIIII
1
15kg
=
mc
1: 18.783Nm*
3
25cm
T 293,15K
=
y 80 0.25m=
S
x Pg. A
1.Equilibria mecanico del embolo:
m59 i 98,000 + 14+.15 30
P=Pamb + + = + - p1 = 105,212KPa
0.0620,062
imag,Pamb.A.FIs)
2. Ecuacion termica de estado: pX-mRgT =
m
105.212,095.0.0154
=
= m(N2) 18,614g =
296,93.293,15
V +1.0,14.8,25
=
0.0154m3
=
3.Ecuacion termica de estado: p2V2
mRgT2
=mRgT2 =
P2 = P2 =250,946KPa
=
Pz.xy
-
= mRgiz.(20 105.212.0,01543 0,018614.296.93.343.15.V2
=
= =
v2 0.00+=
m
*
x P2.A Fre
4. Equilibria mecanico del embolo: ↑= A(Pz Pamb) mcg
-
-
-
+m 0.062/270.944,132 98.800) 15k9.9,8
=
- -
10.103.0,136
+
imag,Pamb.A.FIs)
(j -ve) y 8,1365 11.935,4N
= =
=
5ug m(v)Tz
= +1)
-
0,018614. [43,87.50
=
=
0g 697,5+5j
=
8
Nexts-atapatorde.
Next.s:-pd-JPd:/PrEd
I
-p.x.((0)
=
6. On 7.585.545+ Wext,g= 7.585.545
8,2
Aug Eg Wext,g 8g 0g 691,5+5 1383,th =
8g 692,1655
= =
= =
+ - =
8. Balance energetics: Sistema G - E + M
Eg Ug
=
697.5+55-
=
697.5755-70,07245 + 92,485 W5 =
-
692,165 -
828.6
tE =
=
16,1245 WF 635,52555
mgx
=
tM
(y3 92,48-
=
=
sim 0.028611,0481n363.15 296.931270.944
pint-Rgin
9. = - = -2,7595.17 50.2.1795.15
+
293,15
-
105.212
