ALGEBRAIC FRACTIONS
Not an
equation
Only cancel full terms (can't cancel part of term)
can cancel between top+ bottom
onlyfacto
Always rise fully before cancelling
If + and -
→ USE LCD
If ✗ - >
NO LCD
If ÷ → Flip 2nd fraction and ✗
To switch around
'
take out
'
numbers that are
being subtracted ,
a -
1 .
4×3+16×2 z .
3 .
7 -3C •
Facto rise
8×4 (22-4342-2×+4) 3C-7 •
Cancel like
4×2 (2+4) txt 2) (x2 -
2×+4) = -1 terms
= =
8×4 tctz>to -2×22-2×+5
2+4 I
= =
2×2 a-2
9- → s.sc? -7×2-4×+28 2
4. 6×3-2×2 ✗
✗
-3×+9 3×2+8×-3 14+5×-22 I4-2OC
22<(3×-1) ( 3>c) (3+2) =L c- 73-44-7 ) z
= ✗ ×
+34-3) (3×-1×2+3) -
(x 7)(2+2)
-
217 -
=
2×2 =
(22-4×5-7) I
✗
3 -
Ex -
7)(x + 2) 7- I
=
# +22×-2×2-7) i
✗
-
(x 7) bet 2)
-
7-2
2-2
=
a-7
6. 4- 80C 2×-2 7 I4-7SC 6 -30C
÷
.
÷
4×2-4×-1 -1+22-22 ✗2+2-2 ✗ +2
=Z↳( I -
2x) -
(x -
I )Z > (2-2) ✗ +2
✗
= ✗
-
(2×-132 ZC2 1) -
(2+2×2-1) 3(2-2)
ZC2 -
1) 7
=
2×-1 =3 (x -
1)
Don't have to show
distribution into
8 23C I 9 5 3 4 numerator
+ + +
. .
3 6 72-2-6 3 -0C 2+2
4×+1 5 3 4
= = -
+
6 (2-3%+2) I-3 2+2
=
5-(2+2) (3) + (x 3)(4) -
Ex 3)(2+2) -
5 -3×-6+4×-12
=
(2-3×2+2)
I -13
=
(x 3>(2+2) -
Not an
equation
Only cancel full terms (can't cancel part of term)
can cancel between top+ bottom
onlyfacto
Always rise fully before cancelling
If + and -
→ USE LCD
If ✗ - >
NO LCD
If ÷ → Flip 2nd fraction and ✗
To switch around
'
take out
'
numbers that are
being subtracted ,
a -
1 .
4×3+16×2 z .
3 .
7 -3C •
Facto rise
8×4 (22-4342-2×+4) 3C-7 •
Cancel like
4×2 (2+4) txt 2) (x2 -
2×+4) = -1 terms
= =
8×4 tctz>to -2×22-2×+5
2+4 I
= =
2×2 a-2
9- → s.sc? -7×2-4×+28 2
4. 6×3-2×2 ✗
✗
-3×+9 3×2+8×-3 14+5×-22 I4-2OC
22<(3×-1) ( 3>c) (3+2) =L c- 73-44-7 ) z
= ✗ ×
+34-3) (3×-1×2+3) -
(x 7)(2+2)
-
217 -
=
2×2 =
(22-4×5-7) I
✗
3 -
Ex -
7)(x + 2) 7- I
=
# +22×-2×2-7) i
✗
-
(x 7) bet 2)
-
7-2
2-2
=
a-7
6. 4- 80C 2×-2 7 I4-7SC 6 -30C
÷
.
÷
4×2-4×-1 -1+22-22 ✗2+2-2 ✗ +2
=Z↳( I -
2x) -
(x -
I )Z > (2-2) ✗ +2
✗
= ✗
-
(2×-132 ZC2 1) -
(2+2×2-1) 3(2-2)
ZC2 -
1) 7
=
2×-1 =3 (x -
1)
Don't have to show
distribution into
8 23C I 9 5 3 4 numerator
+ + +
. .
3 6 72-2-6 3 -0C 2+2
4×+1 5 3 4
= = -
+
6 (2-3%+2) I-3 2+2
=
5-(2+2) (3) + (x 3)(4) -
Ex 3)(2+2) -
5 -3×-6+4×-12
=
(2-3×2+2)
I -13
=
(x 3>(2+2) -