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Summary Momentum and Impulse

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2022/2023 Written for academic year
Institution 12th Grade
Course Physical Sciences
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A summary on momentum and impulse in physical science that is suitable for both IEB and CAPS learners in grade 12. It includes theory, definitions and revision questions.

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, MOMENTUM AND IMPULSE
• NB STUDY ALL DEFINITONS
• ALL FORMULAE


P=mv

P= mvf – mvi

P= m(vf-vi)

M1Vi + M2Vi = M1Vf + M2Vf

M1Vi + M2Vi = (M1 + M2) Vf

Fnet t= p

Ek before = Ek after

[Ep + Ek] top = [Ep + Ek] bottom

, MOMENTUM (Kg.m.s^-1)
1. A motorcycle with a mass of 200kg moves at 12m.s-1 in a direction NW. Calcula
momentum of the motorcycle.
P=mv
P= 200 x 2
P= 200 x 12
p= 2400 kg.m.s6-1 NW


2. The momentum of an object is 350kg.m.s-1 in the direction 90 degrees. If the o
has a mass of 30 kg. Calculate the velocity of the object.
P=mv
350= 30v
V= 11,67 m.s^-1 in the direction 90 degrees

, MOMENTUM AND IMPULSE

3. A rubber ball with a mass of 0.8kg is dropped and hits the floor with an initial
downward velocity of 6m.s^-1. The ball bounces with a final upward velocity of 4
1. Calculate:
a) initial momentum
b) final momentum
c) change in momentum of the rubber ball

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