COMPLETE TEST BANK FOR EVIDENCE-BASED
PHYSICAL EXAMINATION 2ND EDITION
VERIFIED ANSWERS 2026
◉ Which letter correctly labels the amplitude of the wave? Answer:
D
◉ Interval PQ represents: Answer: period/2
◉ Let f be the frequency, v the speed, and T the period, relationship?
Answer: f=1/T
◉ Let f be the frequency, v the speed, and T the period of a
sinusoidal traveling wave. The angular frequency Answer: 2 /T
◉ y(x, t) = ym sin(kx + t) . The wavelength of the wave is? Answer: 2
/k
◉ The mathematical forms of the waves are y1(x, t) = ym sin(3x −
6t), y2(x, t) = ym sin(4x − 8t), and y3(x, t) = ym sin(6x − 12t)
Answer: y1: i, y2: ii, y3: iii
◉ y(x, t) = ym sin(kx + t) . The speed of the wave is: Answer: w/k
,◉ y(x, t) = 0.1 sin(3x + 10t). The angular wave number is: Answer:
3.0 rad/cm
◉ y(x, t) = 0.1 sin(3x − 10t). The angular frequency is: Answer: 10
rad/s
◉ Water waves in the sea are observed to have a wavelength of 300
m and a frequency of 0.07 Hz. The speed of these waves is: Answer:
21 m/s
◉ The waves travel at 20cm/s and their adjacent crests are 5.0 cm
apart. The time required for each new whole cycle to be generated
is: Answer: 0.25 s
◉ At which point is the motion 180 out of phase with the motion at
point P? Answer: C
◉ y(x, t) = ym sin(kx − t − ) . Time t = 0 the point at x = 0 has a
displacement of 0 and is moving in the positive y
direction. The phase constant is: Answer: 180
, ◉ y(x, t) = ym sin(kx − t − ) . Time t = 0 the point at x = 0 has a
velocity of 0 and a positive displacement. The phase constant is:
Answer: 270
◉ y(x, t) = ym sin(kx − t − ) . At time t = 0 the point at x = 0 has
velocity v0 and displacement y0. The phase constant is
given by tan =: Answer: wy0/v0
◉ A sinusoidal transverse wave is traveling on a string. Any point on
the string: Answer: moves in simple harmonic motion with the same
angular frequency as the wave
◉ Wave 1 y(x, t) = (2.0 mm) sin[(4.0 m−1 )x − (3.0 s−1 )t]
Wave 2 y(x, t) = (1.0 mm) sin[(8.0 m−1 )x − (4.0 s−1 )t]
Wave 3 y(x, t) = (1.0 mm) sin[(4.0 m−1 )x − (8.0 s−1 )t] Answer:
2,1,3
◉ Sinusoidal waves travel on five different strings, all with the same
tension. Four of the strings have the same linear mass density, but
the fifth has a different linear mass density. Answer: y(x, t) = (2 cm)
sin(4x − 10t)
◉ sinusoidal wave is moving with its maximum speed when:
Answer: displacement is a minimum
PHYSICAL EXAMINATION 2ND EDITION
VERIFIED ANSWERS 2026
◉ Which letter correctly labels the amplitude of the wave? Answer:
D
◉ Interval PQ represents: Answer: period/2
◉ Let f be the frequency, v the speed, and T the period, relationship?
Answer: f=1/T
◉ Let f be the frequency, v the speed, and T the period of a
sinusoidal traveling wave. The angular frequency Answer: 2 /T
◉ y(x, t) = ym sin(kx + t) . The wavelength of the wave is? Answer: 2
/k
◉ The mathematical forms of the waves are y1(x, t) = ym sin(3x −
6t), y2(x, t) = ym sin(4x − 8t), and y3(x, t) = ym sin(6x − 12t)
Answer: y1: i, y2: ii, y3: iii
◉ y(x, t) = ym sin(kx + t) . The speed of the wave is: Answer: w/k
,◉ y(x, t) = 0.1 sin(3x + 10t). The angular wave number is: Answer:
3.0 rad/cm
◉ y(x, t) = 0.1 sin(3x − 10t). The angular frequency is: Answer: 10
rad/s
◉ Water waves in the sea are observed to have a wavelength of 300
m and a frequency of 0.07 Hz. The speed of these waves is: Answer:
21 m/s
◉ The waves travel at 20cm/s and their adjacent crests are 5.0 cm
apart. The time required for each new whole cycle to be generated
is: Answer: 0.25 s
◉ At which point is the motion 180 out of phase with the motion at
point P? Answer: C
◉ y(x, t) = ym sin(kx − t − ) . Time t = 0 the point at x = 0 has a
displacement of 0 and is moving in the positive y
direction. The phase constant is: Answer: 180
, ◉ y(x, t) = ym sin(kx − t − ) . Time t = 0 the point at x = 0 has a
velocity of 0 and a positive displacement. The phase constant is:
Answer: 270
◉ y(x, t) = ym sin(kx − t − ) . At time t = 0 the point at x = 0 has
velocity v0 and displacement y0. The phase constant is
given by tan =: Answer: wy0/v0
◉ A sinusoidal transverse wave is traveling on a string. Any point on
the string: Answer: moves in simple harmonic motion with the same
angular frequency as the wave
◉ Wave 1 y(x, t) = (2.0 mm) sin[(4.0 m−1 )x − (3.0 s−1 )t]
Wave 2 y(x, t) = (1.0 mm) sin[(8.0 m−1 )x − (4.0 s−1 )t]
Wave 3 y(x, t) = (1.0 mm) sin[(4.0 m−1 )x − (8.0 s−1 )t] Answer:
2,1,3
◉ Sinusoidal waves travel on five different strings, all with the same
tension. Four of the strings have the same linear mass density, but
the fifth has a different linear mass density. Answer: y(x, t) = (2 cm)
sin(4x − 10t)
◉ sinusoidal wave is moving with its maximum speed when:
Answer: displacement is a minimum
