Titurus balanced lethal system SNP practicum
1.
1A 1B
1A 1A1A 1A1B (viable)
1B 1B1A (viable) 1B1B
2. 1A1B and 1B1A
3. The heterozygotes, so 1A1B and 1B1A
4. One copy of 1A and one copy of 1B, otherwise they are non-viable
5. 1A1A and 1B1B
6. Two or zero copies of 1A and also two or zero copies of 1B
7. P=0.5 and q=0.5
8. 1A1A(P2)= 0.25, 1A1B(2pq)= 0.5 and 1B1B(q2)= 0.25
9. P= 0.5 and q=0.5
10. P2= 0 2pq= 1 and q2= 0
11. It breaks the rules of Hardy-Weinberg. Titurus is under selection and there is random
mating.
12. No, they are pure bred.
13.
One orange and one blue
14.
One orange and one blue
15. Yes
16. No. Individuals with 1A1A or 1B1B die during embryonic development, therefore
crossing-over cannot occur.
17.
18.
1.
1A 1B
1A 1A1A 1A1B (viable)
1B 1B1A (viable) 1B1B
2. 1A1B and 1B1A
3. The heterozygotes, so 1A1B and 1B1A
4. One copy of 1A and one copy of 1B, otherwise they are non-viable
5. 1A1A and 1B1B
6. Two or zero copies of 1A and also two or zero copies of 1B
7. P=0.5 and q=0.5
8. 1A1A(P2)= 0.25, 1A1B(2pq)= 0.5 and 1B1B(q2)= 0.25
9. P= 0.5 and q=0.5
10. P2= 0 2pq= 1 and q2= 0
11. It breaks the rules of Hardy-Weinberg. Titurus is under selection and there is random
mating.
12. No, they are pure bred.
13.
One orange and one blue
14.
One orange and one blue
15. Yes
16. No. Individuals with 1A1A or 1B1B die during embryonic development, therefore
crossing-over cannot occur.
17.
18.