W GU D335-Intr oduction to |! |! |!
Pr ogr am m in g in Python New est |! |! |! |!
Exam w ith pr ecise answ er s |! |! |!
Create a solution that accepts three integer inputs representing the number of
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times an employee travels to a job site. Output the total distance traveled to
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two decimal places given the following miles per employee commute to the
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job site. Output the total distance traveled to two decimal places given the
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following miles per employee commute to the job site:
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Employee A: 15.62 miles |! |! |!
Employee B: 41.85 miles |! |! |!
Employee C: 32.67 miles |! |! |!
The solution output should be in the format
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Distance: total_miles_traveled miles - Correct answer ✔travels = {
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"A": int(input()),
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"B": int(input()),
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"C": int(input())
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}
miles_per_employee = {"A": 15.62, "B":41.85, "C": 32.67} |! |! |! |! |! |!
total_miles_traveled = sum(travels[employee] * |! |! |! |!
miles_per_employee[employee] for employee in travels) |! |! |! |!
print(f"Distance: {total_miles_traveled:.2f} miles") |! |!
, Create a solution that accepts an integer input representing any number of
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ounces. Output the converted total number of tons, pounds, and remaining
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ounces based on the input ounces value. There are 16 ounces in a pound and
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2,000 pounds in a ton.
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The solution output should be in the format
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Tons: value_1 Pounds: value_2 Ounces: value_3 - Correct answer ✔ounces =
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int(input())
value_1 = ounces // (16 * 2000) |! |! |! |! |! |!
value_2 = (ounces % (16 * 2000)) // 16
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value_3 = ounces % 16 |! |! |! |!
print(f"Tons: {value_1}") |!
print(f"Pounds: {value_2}") |!
print(f"Ounces: {value_3}") |!
Create a solution that accepts an integer input representing the index value
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for any any of the five elements in the following list:
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various_data_types = [516, 112.49, True, "meow", ("Western", "Governors", |! |! |! |! |! |! |! |!
"University"), {"apple": 1, "pear": 5}] |! |! |! |!
Using the built-in function type() and getting its name by using the .name
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attribute, output data type (e.g., int", "float", "bool", "str") based on the input
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index value of the list element.
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The solution output should be in the format
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Element index_value: data_type - Correct answer ✔index_value =
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int(input())
data_type = type(various_data_types[index_value]).__name__
|! |!
Pr ogr am m in g in Python New est |! |! |! |!
Exam w ith pr ecise answ er s |! |! |!
Create a solution that accepts three integer inputs representing the number of
|! |! |! |! |! |! |! |! |! |! |!
times an employee travels to a job site. Output the total distance traveled to
|! |! |! |! |! |! |! |! |! |! |! |! |! |! |!
two decimal places given the following miles per employee commute to the
|! |! |! |! |! |! |! |! |! |! |! |!
job site. Output the total distance traveled to two decimal places given the
|! |! |! |! |! |! |! |! |! |! |! |! |!
following miles per employee commute to the job site:
|! |! |! |! |! |! |! |!
Employee A: 15.62 miles |! |! |!
Employee B: 41.85 miles |! |! |!
Employee C: 32.67 miles |! |! |!
The solution output should be in the format
|! |! |! |! |! |! |!
Distance: total_miles_traveled miles - Correct answer ✔travels = {
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"A": int(input()),
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"B": int(input()),
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"C": int(input())
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}
miles_per_employee = {"A": 15.62, "B":41.85, "C": 32.67} |! |! |! |! |! |!
total_miles_traveled = sum(travels[employee] * |! |! |! |!
miles_per_employee[employee] for employee in travels) |! |! |! |!
print(f"Distance: {total_miles_traveled:.2f} miles") |! |!
, Create a solution that accepts an integer input representing any number of
|! |! |! |! |! |! |! |! |! |! |! |!
ounces. Output the converted total number of tons, pounds, and remaining
|! |! |! |! |! |! |! |! |! |! |!
ounces based on the input ounces value. There are 16 ounces in a pound and
|! |! |! |! |! |! |! |! |! |! |! |! |! |! |!
2,000 pounds in a ton.
|! |! |! |!
The solution output should be in the format
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Tons: value_1 Pounds: value_2 Ounces: value_3 - Correct answer ✔ounces =
|! |! |! |! |! |! |! |! |! |! |!
int(input())
value_1 = ounces // (16 * 2000) |! |! |! |! |! |!
value_2 = (ounces % (16 * 2000)) // 16
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value_3 = ounces % 16 |! |! |! |!
print(f"Tons: {value_1}") |!
print(f"Pounds: {value_2}") |!
print(f"Ounces: {value_3}") |!
Create a solution that accepts an integer input representing the index value
|! |! |! |! |! |! |! |! |! |! |! |!
for any any of the five elements in the following list:
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various_data_types = [516, 112.49, True, "meow", ("Western", "Governors", |! |! |! |! |! |! |! |!
"University"), {"apple": 1, "pear": 5}] |! |! |! |!
Using the built-in function type() and getting its name by using the .name
|! |! |! |! |! |! |! |! |! |! |! |! |!
attribute, output data type (e.g., int", "float", "bool", "str") based on the input
|! |! |! |! |! |! |! |! |! |! |! |! |!
index value of the list element.
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The solution output should be in the format
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Element index_value: data_type - Correct answer ✔index_value =
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int(input())
data_type = type(various_data_types[index_value]).__name__
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