,
,Chapter 1: Arithmetic Needed for Dosage
||! ||! ||! ||! ||!
MULTIPLE CHOICE ||!
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to drink 15
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
oz. What portion of the water remained?
||! ||! ||! ||! ||! ||! ||!
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A | | !
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available quantity
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
(25 oz): 10 oz remain. To determine the portion of the water that remains, create a fraction by
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
dividing 10 oz (remaining portion) by 25 oz (total portion). Therefore, 10 divided by 25 = 10/25.
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
To reduce fractions, find the largest number that can be divided evenly into the numerator and
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
the denominator
||! ||!
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms of
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
2/5.
||!
Format: Multiple Choice |! |!
Chapter: 1
||! ||!
Client Needs: Physiological Integrity: Basic Care and Comfort
||! ||! ||! ||! ||! ||! ||!
Cognitive Level: Apply
||! ||! ||!
Difficulty: Moderate ||!
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
||! ||! ||! ||! ||! ||! ||! ||!
Integrated Process: Teaching/Learning
||! ||! ||!
Objective: 1, 2 ||! ||!
2. A patient/client was prescribed 240 W
||! mWLWo.
f ETnB
suSreMb.yWmSouth as a supplement but consumed only ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
100 mL. What portion of the Ensure remained?
||! ||! ||! ||! ||! ||! ||! ||!
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B | | !
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total available
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
quantity (240 mL): 140 mL remain. To determine the portion of the Ensure that remains, create a
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
fraction by dividing 140 mL (remaining portion) by 240 mL (total portion). Therefore, 140 divided
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
by 240 = 7/12. To reduce fractions, find the largest number that can be divided evenly into the
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
numerator and the denominator (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. The fraction
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
140/240 can be reduced to its lowest terms of 7/12.
||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
Format: Multiple Choice |! |!
Chapter: 1
||! ||!
Client Needs: Physiological Integrity: Basic Care and Comfort
||! ||! ||! ||! ||! ||! ||!
Cognitive Level: Apply
||! ||! ||!
Difficulty: Moderate ||!
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
||! ||! ||! ||! ||! ||! ||! ||!
Integrated Process: Teaching/Learning
||! ||! ||!
Objective: 1, 2 ||! ||!
1 ||!| ||!P ||!a ||!g ||!e
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, 3. A patient/client consumed
||! oz. of coffee, 2/3 oz. of ice cream, and oz. of beef broth. ||! | | ! | | ! ||! ||! ||! ||! ||! ||! ||! ||! | | ! | | ! ||! ||! ||!
What is the total number of ounces consumed that should be documented for the patient/client?
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
a. 3 3/4 ||!
b. 4 5/12 ||!
c. 4 2/3 ||!
d. 4 4/9 ||!
ANS: B | | !
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
multiplying the whole number by the denominator and then adding that total to the numerator. For
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
the coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators,
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
find the least common denominator (LCD). For 2, 3, and 4, the LCD =
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
then multiply that result by the numerator of the fraction. The new fractions to be added are 27/12
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
(coffee), 8/12 (ice cream), and 18/12 (beef broth). After conversion of the fractions, the numerators
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
are added together and the fraction is reduced to the lowest terms.
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
Format: Multiple Choice |! |!
Chapter: 1
||! ||!
Client Needs: Physiological Integrity: Basic Care and Comfort
||! ||! ||! ||! ||! ||! ||!
Cognitive Level: Analyze
||! ||! ||!
Difficulty: Difficult ||!
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
||! ||! ||! ||! ||! ||! ||! ||!
Integrated Process: Communication and Documentation
||! ||! ||! ||! ||!
Objective: 1, 2
||! ||! ||!
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
the nurse document as
||! ||! ||!
WWW.TBSM.WS
consumed?
||!
a. 360
b. 420
c. 510
d. 600
ANS: | | ! B
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total number of
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
milliliters consumed, multiply 180 7/3 (
||! ). When a mixed number is present, change it to an
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
improper fraction by multiplying the whole number by the denominator and then adding that total to
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 = 420).
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
Format: Multiple Choice |! |!
Chapter: 1
||! ||!
Client Needs: Physiological Integrity: Basic Care and Comfort
||! ||! ||! ||! ||! ||! ||!
Cognitive Level: Analyze
||! ||! ||!
Difficulty: Difficult ||!
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
||! ||! ||! ||! ||! ||! ||! ||!
Integrated Process: Communication and Documentation
||! ||! ||! ||! ||!
Objective: 1, 2
||! ||! ||!
5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
were gained since admission?
||! ||! ||! ||!
a. 0.78
b. 0.88
2 ||!| ||!P ||!a ||!g ||!e
www.PlusBay.Plus
,Chapter 1: Arithmetic Needed for Dosage
||! ||! ||! ||! ||!
MULTIPLE CHOICE ||!
1. A patient/client was instructed to drink 25 oz of water within 2 hours but was only able to drink 15
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
oz. What portion of the water remained?
||! ||! ||! ||! ||! ||! ||!
a. 2/5
b. 3/5
c. 2/25
d. 25/25
ANS: A | | !
Feedback: Subtract the quantity of water the client drank (15 oz) from the total available quantity
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
(25 oz): 10 oz remain. To determine the portion of the water that remains, create a fraction by
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
dividing 10 oz (remaining portion) by 25 oz (total portion). Therefore, 10 divided by 25 = 10/25.
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
To reduce fractions, find the largest number that can be divided evenly into the numerator and
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
the denominator
||! ||!
(5). Ten divided by 5 (10/5) = 2; 25/5 = 5. The fraction 10/25 can be reduced to its lowest terms of
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
2/5.
||!
Format: Multiple Choice |! |!
Chapter: 1
||! ||!
Client Needs: Physiological Integrity: Basic Care and Comfort
||! ||! ||! ||! ||! ||! ||!
Cognitive Level: Apply
||! ||! ||!
Difficulty: Moderate ||!
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
||! ||! ||! ||! ||! ||! ||! ||!
Integrated Process: Teaching/Learning
||! ||! ||!
Objective: 1, 2 ||! ||!
2. A patient/client was prescribed 240 W
||! mWLWo.
f ETnB
suSreMb.yWmSouth as a supplement but consumed only ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
100 mL. What portion of the Ensure remained?
||! ||! ||! ||! ||! ||! ||! ||!
a. 5/12
b. 7/12
c. 100/240
d. 240/240
ANS: B | | !
Feedback: Subtract the quantity of Ensure the client consumed (100 mL) from the total available
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
quantity (240 mL): 140 mL remain. To determine the portion of the Ensure that remains, create a
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
fraction by dividing 140 mL (remaining portion) by 240 mL (total portion). Therefore, 140 divided
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
by 240 = 7/12. To reduce fractions, find the largest number that can be divided evenly into the
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
numerator and the denominator (20); 140 divided by 20 (140/20) = 7; 240/20 = 12. The fraction
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
140/240 can be reduced to its lowest terms of 7/12.
||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
Format: Multiple Choice |! |!
Chapter: 1
||! ||!
Client Needs: Physiological Integrity: Basic Care and Comfort
||! ||! ||! ||! ||! ||! ||!
Cognitive Level: Apply
||! ||! ||!
Difficulty: Moderate ||!
Page and Header: 2, Dividing Whole Numbers; 3, Fractions
||! ||! ||! ||! ||! ||! ||! ||!
Integrated Process: Teaching/Learning
||! ||! ||!
Objective: 1, 2 ||! ||!
1 ||!| ||!P ||!a ||!g ||!e
www.PlusBay.Plus
, 3. A patient/client consumed
||! oz. of coffee, 2/3 oz. of ice cream, and oz. of beef broth. ||! | | ! | | ! ||! ||! ||! ||! ||! ||! ||! ||! | | ! | | ! ||! ||! ||!
What is the total number of ounces consumed that should be documented for the patient/client?
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
a. 3 3/4 ||!
b. 4 5/12 ||!
c. 4 2/3 ||!
d. 4 4/9 ||!
ANS: B | | !
Feedback: Add the amount of ounces consumed. First, change any mixed number to a fraction by
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
multiplying the whole number by the denominator and then adding that total to the numerator. For
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
the coffee, 4 2 = 8 + 1 = 9/4; for the beef broth, 2 1
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
= 2 + 1 = 3/2. Then add: 9/4 + 2/3 (ice cream) + 3/2. When fractions have different denominators,
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
find the least common denominator (LCD). For 2, 3, and 4, the LCD =
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
12. Rewrite each fraction using the LCD; divide the LCD by the denominator of each fraction and
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
then multiply that result by the numerator of the fraction. The new fractions to be added are 27/12
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
(coffee), 8/12 (ice cream), and 18/12 (beef broth). After conversion of the fractions, the numerators
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
are added together and the fraction is reduced to the lowest terms.
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
Format: Multiple Choice |! |!
Chapter: 1
||! ||!
Client Needs: Physiological Integrity: Basic Care and Comfort
||! ||! ||! ||! ||! ||! ||!
Cognitive Level: Analyze
||! ||! ||!
Difficulty: Difficult ||!
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
||! ||! ||! ||! ||! ||! ||! ||!
Integrated Process: Communication and Documentation
||! ||! ||! ||! ||!
Objective: 1, 2
||! ||! ||!
4. A coffee cup holds 180 mL. The patient/client drank 2? cups of coffee. How many milliliters would
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
the nurse document as
||! ||! ||!
WWW.TBSM.WS
consumed?
||!
a. 360
b. 420
c. 510
d. 600
ANS: | | ! B
Feedback: The coffee cup holds 180 mL. The client drank 2? cups. To estimate the total number of
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
milliliters consumed, multiply 180 7/3 (
||! ). When a mixed number is present, change it to an
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
improper fraction by multiplying the whole number by the denominator and then adding that total to
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
the numerator: 2 3 = 6 + 1 = 7/3. Therefore, 180 mL × 7/3 = 420 mL (180 ÷ 3 = 60 × 7 = 420).
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
Format: Multiple Choice |! |!
Chapter: 1
||! ||!
Client Needs: Physiological Integrity: Basic Care and Comfort
||! ||! ||! ||! ||! ||! ||!
Cognitive Level: Analyze
||! ||! ||!
Difficulty: Difficult ||!
Page and Header: 2, Multiplying Whole Numbers; 3, Fractions
||! ||! ||! ||! ||! ||! ||! ||!
Integrated Process: Communication and Documentation
||! ||! ||! ||! ||!
Objective: 1, 2
||! ||! ||!
5. A patient/client weighed 48.52 kg on admission and now weighs 50.4 kg. How many kilograms
||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||! ||!
were gained since admission?
||! ||! ||! ||!
a. 0.78
b. 0.88
2 ||!| ||!P ||!a ||!g ||!e
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