Approach, CH5 UPDATED ACTUAL Exam
Questions and CORRECT Answers
LINK: link-layer implementation - CORRECT ANSWER - LINK: in every host in
network interface card
LINK: NIC - CORRECT ANSWER - LINK: network-interface card, has controller and
physical transmission
LINK: single bit parity - CORRECT ANSWER - LINK: detect single bit errors
LINK: 2D bit parity - CORRECT ANSWER - LINK: detect and correct single bit errors
LINK: error checking in link layer - CORRECT ANSWER - LINK: parity checking,
checksum, CRC
LINK: CRC - CORRECT ANSWER - LINK: cyclic redundancy check
D = data bits
G = generator
R = CRC code, remainder, length is G-1
LINK: link types - CORRECT ANSWER - LINK: point-to-point (PPP)
broadcast (shared wire)
LINK: MAC protocols - CORRECT ANSWER - LINK: channel partitioning, random
access, take turns
, LINK: channel partitioning - CORRECT ANSWER - LINK: divide channel into pieces to
allocate to node for exclusive use
TDMA (time division multiple access), access in rounds
FDMA (freq. division multiple access)
LINK: random access - CORRECT ANSWER - LINK: node transmit at full channel rate
no coordination among nodes
specify collision detection and recovery
LINK: random access protocols - CORRECT ANSWER - LINK: slotted ALOHA,
ALOHA, CSMA, CSMA/CD, CSMA/CA
LINK: slotted ALOHA - CORRECT ANSWER - LINK: Pros: node transmit at full rate,
decentralized, simple
Cons: collisions, wasteful, idle slots, clock sync
Node success = p(1-p)^N-1
Any node success = Np(1-p)^N-1
max efficiency = 37%
LINK: pure ALOHA - CORRECT ANSWER - LINK: no synchronization
collision probability increases (t0 collides with t0-1,t0+1)
Node success = p * (1-p)^2(N-1)
max efficiency = 18%
LINK: CSMA - CORRECT ANSWER - LINK: carrier sense multiple access
listen before transmitting for idle channel
collisions can still occur (determined by distance,propagation) wasting entire transmit time