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Computer Networking: A Top-Down Approach, CH5 UPDATED ACTUAL Exam Questions and CORRECT Answers

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Computer Networking: A Top-Down Approach, CH5 UPDATED ACTUAL Exam Questions and CORRECT Answers LINK: link-layer implementation - CORRECT ANSWER - LINK: in every host in network interface card LINK: NIC - CORRECT ANSWER - LINK: network-interface card, has controller and physical transmission LINK: single bit parity - CORRECT ANSWER - LINK: detect single bit error

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Computer Networking
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Uploaded on
February 25, 2025
Number of pages
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Written in
2024/2025
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Computer Networking: A Top-Down
Approach, CH5 UPDATED ACTUAL Exam
Questions and CORRECT Answers
LINK: link-layer implementation - CORRECT ANSWER - LINK: in every host in
network interface card


LINK: NIC - CORRECT ANSWER - LINK: network-interface card, has controller and
physical transmission


LINK: single bit parity - CORRECT ANSWER - LINK: detect single bit errors



LINK: 2D bit parity - CORRECT ANSWER - LINK: detect and correct single bit errors



LINK: error checking in link layer - CORRECT ANSWER - LINK: parity checking,
checksum, CRC


LINK: CRC - CORRECT ANSWER - LINK: cyclic redundancy check
D = data bits
G = generator
R = CRC code, remainder, length is G-1


LINK: link types - CORRECT ANSWER - LINK: point-to-point (PPP)
broadcast (shared wire)


LINK: MAC protocols - CORRECT ANSWER - LINK: channel partitioning, random
access, take turns

, LINK: channel partitioning - CORRECT ANSWER - LINK: divide channel into pieces to
allocate to node for exclusive use
TDMA (time division multiple access), access in rounds
FDMA (freq. division multiple access)


LINK: random access - CORRECT ANSWER - LINK: node transmit at full channel rate
no coordination among nodes
specify collision detection and recovery


LINK: random access protocols - CORRECT ANSWER - LINK: slotted ALOHA,
ALOHA, CSMA, CSMA/CD, CSMA/CA


LINK: slotted ALOHA - CORRECT ANSWER - LINK: Pros: node transmit at full rate,
decentralized, simple
Cons: collisions, wasteful, idle slots, clock sync
Node success = p(1-p)^N-1
Any node success = Np(1-p)^N-1
max efficiency = 37%


LINK: pure ALOHA - CORRECT ANSWER - LINK: no synchronization
collision probability increases (t0 collides with t0-1,t0+1)
Node success = p * (1-p)^2(N-1)
max efficiency = 18%


LINK: CSMA - CORRECT ANSWER - LINK: carrier sense multiple access
listen before transmitting for idle channel
collisions can still occur (determined by distance,propagation) wasting entire transmit time
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