The Lewis Dot Structure for SBr2, following the above steps, would look like this

The Lewis Dot Structure for sulfur dibromide (SBr2) can be drawn as follows:


Steps to Draw the Lewis Dot Structure for SBr2

( i)Count the total number of valence electrons.

Sulfur (S) has 6 valence electrons.

Bromine (Br) has 7 valence electrons, but there are two Bromine atoms, so multiply by 2.

Total valence electrons = 6 + (7*2) = 20 electrons.

(ii)Draw the skeleton structure of the molecule.

Sulfur is the central atom, and the two Bromine atoms are bonded to it.

(iii)Distribute the electrons among the atoms.

Start by placing two electrons (one bond) between each pair of bonded atoms.

Then, fill the octets of the outer atoms (Bromine in this case).

If there are any remaining electrons, place them on the central atom.

Check if all atoms have full octets.

If the central atom does not have a full octet, form double or triple bonds as necessary.

Lewis Dot Structure for SBr2

The Lewis Dot Structure for SBr2, following the above steps, would look like this:



Br

..

: :

S - Br

....

In this structure:



Each line (-) represents a pair of bonded electrons.

Each colon (:) represents a pair of non-bonded electrons, also known as lone pairs.

The dots (..) represent the remaining valence electrons.