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GMAT MATH || with 100% Accurate Solutions.

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Is 72 divisible by 3? correct answers Yes; the sum of its digits are 9, which is divisible by 3. Is 28 divisible by 4? correct answers Yes; because you can divide it by 2 twice. Or, when the last two digits are divisible by 4. Is 48 divisible by 6? correct answers Yes; because it is divisible by 2 (it ends with an 8, which is even) AND by 3 (4+8, which is divisble by 3). Is 456 divisible by 8? correct answers Yes; because 456 is divisible by 2 three times. (456/2 = 228, 228/2 = 114; 114/2 = 57). Always check the last three digits of a larger number. Is 4,185 divisible by 9? correct answers Yes; because the sum of the digits is divisible by 9 ((4+1+8+5 = 18)/9 = 2) What is a factor? correct answers Factor is a positive integer that divides evenly into an integer (1,2,4 and 8 are all factors (also called divisors of 8). What is a multiple? correct answers A multiple of an integer is formed by multiplying that integer by any integer, so 8, 16, 24 and 32 are some of the multiples of 8. Fewer Factors, More Multiples. correct answers ... 12 is divisible by 3 can be said in many different ways... correct answers * 12 is a multiple of 3 * 12/3 is an integer *12 = 3n, where n is an integer *12 can be shared among 3 people so that each person has the same number of items *3 is a divisor of 12, or 3 is a factor of 12 *12/3 yields a remainder of 0 *3 "goes into" 12 evenly If you add or subtract two multiples N, you get another multiple of N correct answers ... Prime Factor? correct answers Any number that is divisible by 1 and itself What are the first 10 prime factors? correct answers 2, 3, 5, 7, 11, 13, 17, 19, 23 and 29 If the problem states or assumes that a number is an integer, you may need to use prime factorization to solve the problem. correct answers * determining whether one number is divisible by another number * Determining the greatest common factor of two numbers * Reducing fractions * Finding the least common multiple of two (or more) numbers * Simplifying square roots * Determining the exponent on one side of an equation with integrer constraints

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