LMRT Core Review Questions and
Answers 2024 (A+ Solutions)
restrict the XR beam to the clinical area of interest - ANS-As a professional
radiographer, the practice of ALARA requires you to
prime - ANS-The factors that affect XR emission under the direct control of the
radiographer are called_ factors
beam quality - ANS-Milliamperage-second (mAs) directly affects all of the following
EXCEPT
mA & filtration - ANS-The factors that directly affect XR quantity are kVp
& beam filtration - ANS-The factors that directly affect XR quality are
6.3 x 10(18) - ANS-If 1 coulomb is equal to 6.3 x 10(18) electron charges, how many
electrons flow from cathode to anode 1 second
6.3 x 10(15) - ANS-If 1 ampere equals a flow of 6.3 x 10(18) electrons per second, how
many electrons flow from cathode to anode in 1 milliampere?
increase 2-fold - ANS-As the mA doubles, the number of electrons flowing from cathode
to anode
XR beam quantity - ANS-The product of tube current 7 exposure time is equal to
change the mAs from 15-21 mAs - ANS-In order to increase radiographic film density by
40% the radiographer would
directly proportional - ANS-The relationship between mAs & exposure is
the reciprocity law - ANS-The reaction of a photographic film to light is equal to the
product of the intensity of the light and the duration of the light exposure.
cause the electrons to travel faster from cathode to anode - ANS-Increasing the kVp for
, an exposure will
greater energy - ANS-Increasing the energy of an incident electron will result in the
production of an XR photon with
radiographic film density - ANS-Kilovoltage is the primary controlling factor of
contrast - ANS-Adjustments in kVp should be used to control radiographic
kVp - ANS-XR beam penetrability is primarily controlled by
400 mA, 200 ms, 40" SID - ANS-All factor remaining constant, which of the following set
of exposure conditions would yield an image with GREATEST radiographic film density
motion - ANS-The length of the exposure time (S) for a radiograph, is used to primarily
control
400 mA,0.110 sec, 80 kVp - ANS-A radiograph is taken 400 mA, 55 ms, 95 kVp. A
second image could be taken to improve contrast at
attenuation - ANS-When an XR photon passes through matter, it undergoes a process
called
reduce in number - ANS-During the process of attenuation, XR photons in the beam
lead (Z=82) - ANS-In which element are the inner-shell electrons more tightly bound to
the nucleus?
increase; decrease - ANS-As the electron shells move farther from the nucleus, total
electron energies_ and binding energies_.
scatter - ANS-When XR photons interacts w/matter & change direction, the process is
called
exists w/less energy - ANS-If a photon interacts w/matte & scatter, the photon inner -
ANS-During photoelectric absorption, a/an_ shell electron is ejected photoelectron -
ANS-During photoelectric absorption, the ejected electron is called a/an
Answers 2024 (A+ Solutions)
restrict the XR beam to the clinical area of interest - ANS-As a professional
radiographer, the practice of ALARA requires you to
prime - ANS-The factors that affect XR emission under the direct control of the
radiographer are called_ factors
beam quality - ANS-Milliamperage-second (mAs) directly affects all of the following
EXCEPT
mA & filtration - ANS-The factors that directly affect XR quantity are kVp
& beam filtration - ANS-The factors that directly affect XR quality are
6.3 x 10(18) - ANS-If 1 coulomb is equal to 6.3 x 10(18) electron charges, how many
electrons flow from cathode to anode 1 second
6.3 x 10(15) - ANS-If 1 ampere equals a flow of 6.3 x 10(18) electrons per second, how
many electrons flow from cathode to anode in 1 milliampere?
increase 2-fold - ANS-As the mA doubles, the number of electrons flowing from cathode
to anode
XR beam quantity - ANS-The product of tube current 7 exposure time is equal to
change the mAs from 15-21 mAs - ANS-In order to increase radiographic film density by
40% the radiographer would
directly proportional - ANS-The relationship between mAs & exposure is
the reciprocity law - ANS-The reaction of a photographic film to light is equal to the
product of the intensity of the light and the duration of the light exposure.
cause the electrons to travel faster from cathode to anode - ANS-Increasing the kVp for
, an exposure will
greater energy - ANS-Increasing the energy of an incident electron will result in the
production of an XR photon with
radiographic film density - ANS-Kilovoltage is the primary controlling factor of
contrast - ANS-Adjustments in kVp should be used to control radiographic
kVp - ANS-XR beam penetrability is primarily controlled by
400 mA, 200 ms, 40" SID - ANS-All factor remaining constant, which of the following set
of exposure conditions would yield an image with GREATEST radiographic film density
motion - ANS-The length of the exposure time (S) for a radiograph, is used to primarily
control
400 mA,0.110 sec, 80 kVp - ANS-A radiograph is taken 400 mA, 55 ms, 95 kVp. A
second image could be taken to improve contrast at
attenuation - ANS-When an XR photon passes through matter, it undergoes a process
called
reduce in number - ANS-During the process of attenuation, XR photons in the beam
lead (Z=82) - ANS-In which element are the inner-shell electrons more tightly bound to
the nucleus?
increase; decrease - ANS-As the electron shells move farther from the nucleus, total
electron energies_ and binding energies_.
scatter - ANS-When XR photons interacts w/matter & change direction, the process is
called
exists w/less energy - ANS-If a photon interacts w/matte & scatter, the photon inner -
ANS-During photoelectric absorption, a/an_ shell electron is ejected photoelectron -
ANS-During photoelectric absorption, the ejected electron is called a/an
