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APM1514 Assignment 3 (COMPLETE ANSWERS) 2024 - DUE 24 May 2024

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APM1514 Assignment 3 (COMPLETE ANSWERS) 2024 - DUE 24 May 2024 ;100 % TRUSTED workings, explanations and solutions. For assistance call or W.h.a.t.s.a.p.p us on ...(.+.2.5.4.7.7.9.5.4.0.1.3.2)........... ASSIGNMENT 03 Due date: Friday, 24 May 2024 Total Marks: 100 ONLY FOR YEAR MODULE This assignment covers study unit 4 in the study guide. Question 1: 12 Marks Which of the following differential equations are separable or inseparable? Justify your answer algebraically (hint: demonstrate manipulation up until the form (... )dy = (... )dt or (... )dy = (... )dx, if separable). (1.1) e t = − ln(t )dy dt + y t 8 . (1.2) x 5 y dy dx = sin(x + y ) + sin(x− y ) 2 . (1.3) (y 7 − 1)dy dx = cos(x − y )− cos(x + y ) 2 . Question 2: 40 Marks Find the general solutions to the following differential equations: (2.1) dx dt + 4x − 1 = 0. (2.2) x dy dx = 2(y − 4). (2.3) dy dt = ty + 3t − 3 − y 4y + ty − 8 − 2t . 28 APM1514/101/0/2024 (2.4) dN dt = 2tN2 − N 2 . (2.5) 1 2t + 1 dN dt = eN+t 2+t . Question 3: 48 Marks Solve the following initial value problems. (3.1) dy dx = (e x 2 + 2) 6x − 1y 2 , y (0) = 1. (3.2) dy dt = 2(y − 5), y (0) = 1. (3.3) dy dt = 36y (t 3 − t 2 ), y (1) =− e. (3.4) ty + t2 dy dt = y , y (− 1) = − 1.

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APM1514
ASSIGNMENT 3 2024

, APM1514/101/0/2024




Tutorial Letter 101/0/2024


Mathematical Modelling

APM1514

Year module

Department of Mathematical Sciences


Problems: Assignment 3




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Open Rubric of south africa

, ASSIGNMENT 03
Due date: Friday, 24 May 2024
Total Marks: 100


ONLY FOR YEAR MODULE

This assignment covers study unit 4 in the study guide.



Question 1: 12 Marks

Which of the following differential equations are separable or inseparable? Justify your answer algebraically
(hint: demonstrate manipulation up until the form (... )dy = (... )dt or (... )dy = (... )dx, if separable).

(1.1)
dy y
et = − ln(t ) + 8 .
dt t

(1.2)
x 5 dy sin(x + y ) + sin(x− y )
= .
y dx 2

(1.3)
dy cos(x − y ) − cos(x + y )
(y 7 − 1) = .
dx 2



Question 2: 40 Marks

Find the general solutions to the following differential equations:

(2.1)
dx
+ 4x − 1 = 0.
dt

(2.2)
dy
x = 2(y − 4).
dx

(2.3)
dy ty + 3t − 3 − y
= .
dt 4y + ty − 8 − 2t




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