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AQA A level Biology Revision Questions and Answers Latest (2023 / 2024) (Verified Answers)

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AQA A level Biology Revision Questions and Answers Latest (2023 / 2024) (Verified Answers)












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August 3, 2023
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AQA A level Biology Revision

1. Describe how you would use a biochemical test to show that a solution

contained a non-reducing sugar, such as sucrose. [3]: ,first reducing sugars

test; boil with dilute HCl acid then Neutralise with NaHCÑ, add benedict

and heat to 95 degrees C brick red ppt forms if reducing sugar is

present

2. Describe a chemical test you could carry out to show that a piece of

coconut contains lipids. [3]: (Crush in) ethanol / alcohol; Add (to) water

(Order of adding is critical for this point); Emulsion / white colour

3. Explain what is meant by a polymer. [1]: Molecule) made up of many

identi- cal/similar molecules/monomers/ subunits;

4. Name the reaction which occurs when starch is broken down into

maltose. [1]: Hydrolysis

5. What is the formula for lactose? [2]: C12 ; H22L1

6. Describe how ²-glucose molecule differs from a molecule of ±g-lucose.

[1]: H at top right end (instead of OH) / OH at bottom (carbon 1)

7. Show two ways in which the structure of cellulose is different from the

structure of starch. [2]: Starch 1,4 and 1,6 bonds / branching Cellulose

1,4 bonds


,/ no 1,6 bonds / straight; starch All glucoses /monomers same way up

cellulose Alternate glucoses upside down; starch Helix / coiled/compact

cellulose Straight; Starch monomer Alpha glucose Cellulose monomer

Beta glucose

8. Describe the structure of starch and explain how its structure is related to

its function. [3]: Formed from ±glucose; Joined by condensation/ by the

removal of a water molecule/ glycosidic bonds; Between (carbons) 1 and

4 (and 1 and 6); Coiled chain; compact; (Allows) storage of large

amount in a small space; Insoluble so has no effect on osmosis/water

potential; Branches; (Allows) rapid breakdown/release of glucose /

hydrolysis;

9. The structure of a phospholipid molecule is different from that of a

triglyc- eride. Describe how. [2]: triglyceride has three fatty acids and

phospholipid has two; no phosphate group present in triglyceride but

present in phospholipid.

10.What is an unsaturated fatty acid? [1]: Some / two carbons with only

one hydrogen / (double bonds) between carbon atoms / not saturated

with hydrogen;

11.Describe the structure of cellulose and explain how its structure is


,related to its function. [3]: Alternate ²-glucose rotated 180o, long straight

chains, Many hydrogen bonds join (polysaccharide) chains/molecules to

each other / makes microfibrils / gives tensile strength;

12.Which elements are found in proteins? [1]: Carbon, hydrogen, oxygen,

nitro- gen (sometimes sulphur)

13.Describe how you would use a biochemical test to show that a solution

contained protein. [2]: Biuret / alkali + copper sulphate;

Lilac/purple/mauve/violet;






, 14.Which bonds are found in a)Primary structure [1]b)Secondary structure

[1] c)Tertiary structure [2]: a)Peptide b) Hydrogen (and peptide) c)Ionic,

disulphide bridges, hydrophobic interactions (hydrogen and peptide)

15.Explain how a change in the primary structure of a globular protein may

result in a different three-dimensional structure. [3]: Sequence of amino

acids changes; tertiary structure changes/folds in a different way;

bonds form in different places (not peptide);

16.Describe how two-way chromatography is carried out. [2]: Run

chro- matogram then turn through 90/right angle; With a different

solvent;

17.Explain the advantage of using two-way chromatography to separate

short polypeptides. [2]: Spreads spots/polypeptides out more/ make sure

spot only contains one substance;

18. Explain how inhibitors affect the rate of enzyme-controlled reactions. [6]

: Statement about two types, competitive and non-competitive;

Competitive: Similar shape to substrate;Inhibitor can enter/bind with

active site (of enzyme);Non-com- petitive: Affect/bind to enzyme other

than at active site; Distorts shape of active site; Inhibitors: Prevent entry

of/binding of substrate to active site; Therefore fewer/no enzyme-

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