Tutorial questions 2

St.

1) yz
e)
=
y y y
=
- -




Initial condition y(0) =
-



5
what is
* C?
the value of




y"
=
y
-
yz 3
-
e xc,e x)
=




-




getthe
y.(x)
-
=

5
-




3
I
=




y 2xy2 0y c
+ = =




y( z) E
- =




What is value C?
of




=l
=
3=
=




=


x

y" - y y c,e
=
0 = cze
+




condition:0 y(0) 0
=

what are the values at a and C2?
8 y'(-1)
=
- S


-

by
ceX
=
+
cze

0
y 0soy c, cz
+ =




3
= =




xe
2c
② y'( -

1) = - S y =
-

Ge
0
=

bc 0
=
= D
=




0 C- 22 SO 22 0
=

=




21 22 0
= =