JERSEY COLLEGE ANATOMY &
PHYSIOLOGY FINAL EXAM
ACTUAL 2026/2027 - COMPLETE
LATEST MOCK PRACTICE SET
180 Questions with Answers and Detailed Rationales
100 PERCENT GUARANTEED PASS
INSTANT DOWNLOAD ANSWERS INCLUDED
IMPORTANCE OF THIS DOCUMENT
This comprehensive examination preparation guide has been meticulously developed to help you succeed in the
JERSEY COLLEGE ANATOMY & PHYSIOLOGY FINAL EXAM ACTUAL 2026/2027 - COMPLETE EXAM-STYLE
QUESTIONS | 100% VERIFIED - PASS GUARANTEED - A+ GRADED. It contains 180 carefully selected
questions that reflect the most current exam content and testing strategies. Each question is accompanied by a
correct answer and a detailed rationale that explains the underlying pathophysiology, pharmacology, or clinical
reasoning.
Self-Assessment – Test your knowledge and Exam Preparation – Familiarize yourself with the
identify areas requiring further question format and content
study areas
Concept Reinforcement – Deepen your Confidence Building – Develop test-taking
understanding through strategies and reduce
evidence-based exam anxiety
rationales
Time Management – Practice answering
questions under simulated
exam conditions
Review Summary 180 Questions
Foundations - Application - Jersey College Anatomy & Physiology Actual 2026/2027 Complete -style 100
PASS Guaranteed A Anatomy & Physiology Undergraduate YEAR 3 / Graduate
All answers with rationales
,Table of Contents
Section A - Potential Section B - Explains
Questions 1 to 45 Questions 46 to 90
Section C - Muscle Section D - Membrane
Questions 91 to 135 Questions 136 to 180
,Section A - Potential
Q1.
During a sprint, skeletal muscle cells rely on anaerobic glycolysis for ATP. Which enzyme
is directly activated by rising AMP levels to stimulate glycolysis, and what is the primary
allosteric inhibitor of this enzyme?
A. Phosphofructokinase-1; ATP and citrate B. Hexokinase; glucose-6-phosphate
C. Pyruvate kinase; alanine D. Glycogen phosphorylase; glucose
Correct: A - Phosphofructokinase-1; ATP and citrate
Rationale:Phosphofructokinase-1 is the rate-limiting enzyme of glycolysis, activated by AMP
(and fructose-2,6-bisphosphate) and inhibited by ATP and citrate. Hexokinase is inhibited by
its product, but not the primary AMP target. Pyruvate kinase and glycogen phosphorylase are
not directly activated by AMP in this context. Thus, A is correct.
Q2.
A researcher measures the membrane potential of a neuron and finds it stabilizes at -70
mV. If the extracellular concentration of K+ is doubled while intracellular K+ is held
constant, what is the immediate effect on the resting membrane potential (assuming only
K+ permeability changes) as predicted by the Nernst equation?
A. It becomes less negative (depolarizes) by B. It becomes more negative
approximately 18 mV (hyperpolarizes) by approximately 18 mV
C. It becomes less negative by D. It remains unchanged because the
approximately 6 mV membrane potential is dominated by Na+
Correct: A - It becomes less negative (depolarizes) by approximately 18 mV
Rationale:The Nernst potential for K+ is E_K = 61 log([K+]o/[K+]i). Doubling [K+]o increases
the ratio by a factor of 2, so E_K shifts by +61 log(2) +18 mV (less negative). Since resting
potential is largely determined by K+ permeability, the membrane depolarizes by ~18 mV. B
and C are numerically incorrect; D ignores K+ dominance at rest.
Q3.
In a patient with chronic heart failure, which compensatory neurohormonal mechanism is
initially beneficial but ultimately leads to adverse cardiac remodeling and worsening of the
condition?
A. Activation of the B. Increased release of atrial natriuretic
renin-angiotensin-aldosterone system peptide (ANP)
(RAAS)
Page 3
, Section A - Potential
C. Downregulation of beta-adrenergic D. Enhanced parasympathetic tone to the
receptors heart
Correct: A - Activation of the renin-angiotensin-aldosterone system (RAAS)
Rationale:Chronic heart failure triggers RAAS activation, increasing preload and afterload via
angiotensin II and aldosterone, which initially supports cardiac output but causes fibrosis and
remodeling. ANP is compensatory but not harmful. Beta-receptor downregulation is a
consequence, not a beneficial mechanism. Parasympathetic tone is not a primary
compensatory response.
Q4.
Which of the following best explains why the partial pressure of oxygen (PO2) in the
alveoli is lower than the PO2 in the atmosphere, even in a healthy individual at sea level?
A. Oxygen is continuously removed by B. Inspired air is humidified, diluting oxygen
pulmonary capillary blood
C. Dead space ventilation mixes expired air D. Alveolar ventilation is not sufficient to
with inspired air replace oxygen
Correct: B - Inspired air is humidified, diluting oxygen
Rationale:Inspired air is humidified in the respiratory tract; water vapor exerts a partial
pressure of 47 mmHg at 37°C, diluting oxygen. The alveolar PO2 is ~100 mmHg vs. inspired
160 mmHg. Oxygen removal and dead space contribute to the difference but the primary
reason is humidification. Therefore, B is correct.
Q5.
Which of the following best explains why the partial pressure of oxygen (PO2) in the
alveoli is lower than the PO2 in the atmosphere, even in a healthy individual at sea level?
A. Oxygen is continuously removed by B. Inspired air is humidified, diluting oxygen
pulmonary capillary blood
C. Dead space ventilation mixes expired air D. Alveolar ventilation is not sufficient to
with inspired air replace oxygen
Correct: B - Inspired air is humidified, diluting oxygen
Rationale:Inspired air is humidified in the respiratory tract; water vapor exerts a partial
pressure of 47 mmHg at 37°C, diluting oxygen. The alveolar PO2 is ~100 mmHg vs. inspired
160 mmHg. Oxygen removal and dead space contribute to the difference but the primary
reason is humidification. Therefore, B is correct.
Page 4
PHYSIOLOGY FINAL EXAM
ACTUAL 2026/2027 - COMPLETE
LATEST MOCK PRACTICE SET
180 Questions with Answers and Detailed Rationales
100 PERCENT GUARANTEED PASS
INSTANT DOWNLOAD ANSWERS INCLUDED
IMPORTANCE OF THIS DOCUMENT
This comprehensive examination preparation guide has been meticulously developed to help you succeed in the
JERSEY COLLEGE ANATOMY & PHYSIOLOGY FINAL EXAM ACTUAL 2026/2027 - COMPLETE EXAM-STYLE
QUESTIONS | 100% VERIFIED - PASS GUARANTEED - A+ GRADED. It contains 180 carefully selected
questions that reflect the most current exam content and testing strategies. Each question is accompanied by a
correct answer and a detailed rationale that explains the underlying pathophysiology, pharmacology, or clinical
reasoning.
Self-Assessment – Test your knowledge and Exam Preparation – Familiarize yourself with the
identify areas requiring further question format and content
study areas
Concept Reinforcement – Deepen your Confidence Building – Develop test-taking
understanding through strategies and reduce
evidence-based exam anxiety
rationales
Time Management – Practice answering
questions under simulated
exam conditions
Review Summary 180 Questions
Foundations - Application - Jersey College Anatomy & Physiology Actual 2026/2027 Complete -style 100
PASS Guaranteed A Anatomy & Physiology Undergraduate YEAR 3 / Graduate
All answers with rationales
,Table of Contents
Section A - Potential Section B - Explains
Questions 1 to 45 Questions 46 to 90
Section C - Muscle Section D - Membrane
Questions 91 to 135 Questions 136 to 180
,Section A - Potential
Q1.
During a sprint, skeletal muscle cells rely on anaerobic glycolysis for ATP. Which enzyme
is directly activated by rising AMP levels to stimulate glycolysis, and what is the primary
allosteric inhibitor of this enzyme?
A. Phosphofructokinase-1; ATP and citrate B. Hexokinase; glucose-6-phosphate
C. Pyruvate kinase; alanine D. Glycogen phosphorylase; glucose
Correct: A - Phosphofructokinase-1; ATP and citrate
Rationale:Phosphofructokinase-1 is the rate-limiting enzyme of glycolysis, activated by AMP
(and fructose-2,6-bisphosphate) and inhibited by ATP and citrate. Hexokinase is inhibited by
its product, but not the primary AMP target. Pyruvate kinase and glycogen phosphorylase are
not directly activated by AMP in this context. Thus, A is correct.
Q2.
A researcher measures the membrane potential of a neuron and finds it stabilizes at -70
mV. If the extracellular concentration of K+ is doubled while intracellular K+ is held
constant, what is the immediate effect on the resting membrane potential (assuming only
K+ permeability changes) as predicted by the Nernst equation?
A. It becomes less negative (depolarizes) by B. It becomes more negative
approximately 18 mV (hyperpolarizes) by approximately 18 mV
C. It becomes less negative by D. It remains unchanged because the
approximately 6 mV membrane potential is dominated by Na+
Correct: A - It becomes less negative (depolarizes) by approximately 18 mV
Rationale:The Nernst potential for K+ is E_K = 61 log([K+]o/[K+]i). Doubling [K+]o increases
the ratio by a factor of 2, so E_K shifts by +61 log(2) +18 mV (less negative). Since resting
potential is largely determined by K+ permeability, the membrane depolarizes by ~18 mV. B
and C are numerically incorrect; D ignores K+ dominance at rest.
Q3.
In a patient with chronic heart failure, which compensatory neurohormonal mechanism is
initially beneficial but ultimately leads to adverse cardiac remodeling and worsening of the
condition?
A. Activation of the B. Increased release of atrial natriuretic
renin-angiotensin-aldosterone system peptide (ANP)
(RAAS)
Page 3
, Section A - Potential
C. Downregulation of beta-adrenergic D. Enhanced parasympathetic tone to the
receptors heart
Correct: A - Activation of the renin-angiotensin-aldosterone system (RAAS)
Rationale:Chronic heart failure triggers RAAS activation, increasing preload and afterload via
angiotensin II and aldosterone, which initially supports cardiac output but causes fibrosis and
remodeling. ANP is compensatory but not harmful. Beta-receptor downregulation is a
consequence, not a beneficial mechanism. Parasympathetic tone is not a primary
compensatory response.
Q4.
Which of the following best explains why the partial pressure of oxygen (PO2) in the
alveoli is lower than the PO2 in the atmosphere, even in a healthy individual at sea level?
A. Oxygen is continuously removed by B. Inspired air is humidified, diluting oxygen
pulmonary capillary blood
C. Dead space ventilation mixes expired air D. Alveolar ventilation is not sufficient to
with inspired air replace oxygen
Correct: B - Inspired air is humidified, diluting oxygen
Rationale:Inspired air is humidified in the respiratory tract; water vapor exerts a partial
pressure of 47 mmHg at 37°C, diluting oxygen. The alveolar PO2 is ~100 mmHg vs. inspired
160 mmHg. Oxygen removal and dead space contribute to the difference but the primary
reason is humidification. Therefore, B is correct.
Q5.
Which of the following best explains why the partial pressure of oxygen (PO2) in the
alveoli is lower than the PO2 in the atmosphere, even in a healthy individual at sea level?
A. Oxygen is continuously removed by B. Inspired air is humidified, diluting oxygen
pulmonary capillary blood
C. Dead space ventilation mixes expired air D. Alveolar ventilation is not sufficient to
with inspired air replace oxygen
Correct: B - Inspired air is humidified, diluting oxygen
Rationale:Inspired air is humidified in the respiratory tract; water vapor exerts a partial
pressure of 47 mmHg at 37°C, diluting oxygen. The alveolar PO2 is ~100 mmHg vs. inspired
160 mmHg. Oxygen removal and dead space contribute to the difference but the primary
reason is humidification. Therefore, B is correct.
Page 4
