UNE General Chemistry II Midterm
Actual Exam 2026/2027 | Verified
Questions
University of New England (UNE) | Verified Q&A |
Undergraduate Chemistry and Pre-Health Students
Comprehensive 50-Question Original Actual Exam Set | 2026/2027
Introduction
This 2026/2027 comprehensive 50-question actual exam set provides original questions covering Kinetics and
Reaction Rates, Chemical Equilibrium and Le Chatelier's Principle, Acids, Bases, and Aqueous Equilibria, and
Thermodynamics and Thermochemistry. The content is designed to reinforce official UNE General Chemistry II
course objectives for actual exam readiness and academic success by strengthening quantitative problem solving,
conceptual reasoning, equilibrium prediction, acid-base calculations, and thermodynamic interpretation. Each
item includes Verified Answers and concise rationales grounded in general chemistry principles, standard kinetic
models, and current chemical thermodynamics standards.
Domain: Kinetics and Reaction Rates
1. Initial-rate data show that doubling [A] while holding [B] constant doubles the rate, and
doubling [B] while holding [A] constant quadruples the rate. What is the rate law?
A. rate = k[A][B]^2
B. rate = k[A]^2[B]
C. rate = k[A][B]
D. rate = k[A]^2[B]^2
Correct Answer: A
Rationale: The reaction is first order in A because doubling A doubles rate, and second order in B because
doubling B quadruples rate.
2. For a first-order reaction, the half-life is 35.0 s. What is the rate constant?
A. 24.3 s^-1
B. 0.0198 s^-1
C. 0.693 s^-1
D. 50.5 s^-1
Correct Answer: B
Rationale: For a first-order process, t1/2 = 0.693/k, so k = 0.693/35.0 s = 0.0198 s^-1.
3. A plot of ln[A] versus time gives a straight line with slope -0.045 s^-1. What is the reaction
order with respect to A?
A. Zero order
B. Second order
C. First order
D. Third order
Correct Answer: C
Rationale: A linear ln[A] versus time plot is characteristic of first-order kinetics, and the slope equals -k.
4. For a zero-order reaction with k = 0.020 M/s and initial concentration 0.100 M, how long is
required for [A] to reach 0.040 M?
UNE General Chemistry II Midterm Actual Exam 2026/2027 | Verified Questions
, A. 0.30 s
B. 7.0 s
C. 5.0 s
D. 3.0 s
Correct Answer: D
Rationale: For zero order, [A]t = [A]0 - kt; time = (0.100 - 0.040)/0.020 = 3.0 s.
5. What are the units of k for an overall second-order rate law?
A. M^-1 s^-1
B. s^-1
C. M s^-1
D. M^2 s^-1
Correct Answer: A
Rationale: For rate units M/s and concentration term M^2, k must have units M^-1 s^-1.
6. Which statement correctly describes activation energy?
A. It is the heat released after equilibrium is reached
B. It is the minimum energy barrier that reacting particles must overcome to form products
C. It is the concentration of catalyst at the end of reaction
D. It is the final kinetic energy of solvent molecules only
Correct Answer: B
Rationale: Activation energy is the energy barrier between reactants and the transition state on a reaction
energy diagram.
7. According to collision theory, why does increasing temperature usually increase reaction rate?
A. The equilibrium constant must become zero
B. All collisions become perfectly oriented
C. A larger fraction of collisions have energy equal to or greater than activation energy
D. Reactants stop colliding with each other
Correct Answer: C
Rationale: Higher temperature increases molecular kinetic energy, increasing the fraction of effective
energetic collisions.
8. A catalyst increases reaction rate primarily by doing what?
A. Increasing the equilibrium constant for every reaction
B. Changing products into reactants permanently
C. Increasing the mass of each reactant molecule
D. Providing a lower activation-energy pathway
Correct Answer: D
Rationale: Catalysts speed reactions by lowering activation energy without being consumed or changing
the equilibrium position.
9. If the rate law for a reaction is rate = k[NO2]^2, what happens to the rate when [NO2] is
tripled?
A. The rate becomes nine times larger
B. The rate becomes three times larger
C. The rate becomes one third as large
D. The rate is unchanged
Correct Answer: A
Rationale: A second-order dependence means rate changes with the square of concentration, so tripling
gives 3^2 = 9 times the rate.
10. Which step determines the rate law in a multistep mechanism when one step is much slower
than the others?
A. The final product isolation step
B. The slow elementary step
C. The fastest elementary step
D. The written overall reaction only
UNE General Chemistry II Midterm Actual Exam 2026/2027 | Verified Questions
Actual Exam 2026/2027 | Verified
Questions
University of New England (UNE) | Verified Q&A |
Undergraduate Chemistry and Pre-Health Students
Comprehensive 50-Question Original Actual Exam Set | 2026/2027
Introduction
This 2026/2027 comprehensive 50-question actual exam set provides original questions covering Kinetics and
Reaction Rates, Chemical Equilibrium and Le Chatelier's Principle, Acids, Bases, and Aqueous Equilibria, and
Thermodynamics and Thermochemistry. The content is designed to reinforce official UNE General Chemistry II
course objectives for actual exam readiness and academic success by strengthening quantitative problem solving,
conceptual reasoning, equilibrium prediction, acid-base calculations, and thermodynamic interpretation. Each
item includes Verified Answers and concise rationales grounded in general chemistry principles, standard kinetic
models, and current chemical thermodynamics standards.
Domain: Kinetics and Reaction Rates
1. Initial-rate data show that doubling [A] while holding [B] constant doubles the rate, and
doubling [B] while holding [A] constant quadruples the rate. What is the rate law?
A. rate = k[A][B]^2
B. rate = k[A]^2[B]
C. rate = k[A][B]
D. rate = k[A]^2[B]^2
Correct Answer: A
Rationale: The reaction is first order in A because doubling A doubles rate, and second order in B because
doubling B quadruples rate.
2. For a first-order reaction, the half-life is 35.0 s. What is the rate constant?
A. 24.3 s^-1
B. 0.0198 s^-1
C. 0.693 s^-1
D. 50.5 s^-1
Correct Answer: B
Rationale: For a first-order process, t1/2 = 0.693/k, so k = 0.693/35.0 s = 0.0198 s^-1.
3. A plot of ln[A] versus time gives a straight line with slope -0.045 s^-1. What is the reaction
order with respect to A?
A. Zero order
B. Second order
C. First order
D. Third order
Correct Answer: C
Rationale: A linear ln[A] versus time plot is characteristic of first-order kinetics, and the slope equals -k.
4. For a zero-order reaction with k = 0.020 M/s and initial concentration 0.100 M, how long is
required for [A] to reach 0.040 M?
UNE General Chemistry II Midterm Actual Exam 2026/2027 | Verified Questions
, A. 0.30 s
B. 7.0 s
C. 5.0 s
D. 3.0 s
Correct Answer: D
Rationale: For zero order, [A]t = [A]0 - kt; time = (0.100 - 0.040)/0.020 = 3.0 s.
5. What are the units of k for an overall second-order rate law?
A. M^-1 s^-1
B. s^-1
C. M s^-1
D. M^2 s^-1
Correct Answer: A
Rationale: For rate units M/s and concentration term M^2, k must have units M^-1 s^-1.
6. Which statement correctly describes activation energy?
A. It is the heat released after equilibrium is reached
B. It is the minimum energy barrier that reacting particles must overcome to form products
C. It is the concentration of catalyst at the end of reaction
D. It is the final kinetic energy of solvent molecules only
Correct Answer: B
Rationale: Activation energy is the energy barrier between reactants and the transition state on a reaction
energy diagram.
7. According to collision theory, why does increasing temperature usually increase reaction rate?
A. The equilibrium constant must become zero
B. All collisions become perfectly oriented
C. A larger fraction of collisions have energy equal to or greater than activation energy
D. Reactants stop colliding with each other
Correct Answer: C
Rationale: Higher temperature increases molecular kinetic energy, increasing the fraction of effective
energetic collisions.
8. A catalyst increases reaction rate primarily by doing what?
A. Increasing the equilibrium constant for every reaction
B. Changing products into reactants permanently
C. Increasing the mass of each reactant molecule
D. Providing a lower activation-energy pathway
Correct Answer: D
Rationale: Catalysts speed reactions by lowering activation energy without being consumed or changing
the equilibrium position.
9. If the rate law for a reaction is rate = k[NO2]^2, what happens to the rate when [NO2] is
tripled?
A. The rate becomes nine times larger
B. The rate becomes three times larger
C. The rate becomes one third as large
D. The rate is unchanged
Correct Answer: A
Rationale: A second-order dependence means rate changes with the square of concentration, so tripling
gives 3^2 = 9 times the rate.
10. Which step determines the rate law in a multistep mechanism when one step is much slower
than the others?
A. The final product isolation step
B. The slow elementary step
C. The fastest elementary step
D. The written overall reaction only
UNE General Chemistry II Midterm Actual Exam 2026/2027 | Verified Questions
