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Chem 103 Module 1 to 6 Exam & Final Exam Portage learning

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Master the fundamentals of general chemistry with this comprehensive study and revision guide for Portage Learning CHEM 103. Covering Modules 1–6 and the final exam, it features practice questions, verified answers, and detailed rationales on atomic structure, chemical bonding, stoichiometry, chemical reactions, gases, solutions, acids and bases, thermochemistry, and laboratory concepts. An excellent resource for reinforcing foundational chemistry principles, improving problem-solving skills, and preparing confidently for module assessments and the comprehensive final examination.

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Institution
Chem 103 Module 1 To 6
Module
Chem 103 Module 1 to 6

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1|Page SUCCESS!!!

,MODULE 1 PRACTICE QUESTIONS
Q1. Convert 845.3 to exponential form and explain your answer.
Answer: 8.453 × 10²
845.3 is larger than 1, so the exponent is positive. Move the decimal 2 places to the left: 8.453 × 10²


Q2. Convert 3.21 × 10⁻⁵ to ordinary form and explain your answer.
Answer: 0.0000321
The exponent is negative, so the number is smaller than 1. Move the decimal 5 places to the left:
0.0000321


Q3. 24.6 grams = ? kilograms. Show your work.
Answer: 0.0246 kg
24.6 g × (1 kg / 1000 g) = 0.0246 kg


Q4. 6.3 ft = ? inches. Show your work.
Answer: 75.6 inches
6.3 ft × (12 in / 1 ft) = 75.6 inches


Q5. Convert 28°C to Kelvin.
Answer: 301 K
°C → K: add 273. 28 + 273 = 301 K


Q6. Convert 158°F to Celsius.
Answer: 70°C
°F → °C: (°F - 32) ÷ 1.8. (158 - 32) ÷ 1.8 = 126 ÷ 1.8 = 70°C


Q7. Convert 343 K to Fahrenheit.
Answer: 158°F
K → °C → °F. 343 - 273 = 70°C. (70 × 1.8) + 32 = 126 + 32 = 158°F


Q8. Calculate the mass of an 18.6 mL sample of freon with a density of 1.49 g/mL.
Answer: 27.7 g
Mass = Density × Volume = 1.49 g/mL × 18.6 mL = 27.7 g (3 sig figs)


2|Page SUCCESS!!!

,Q9. Calculate the density of crude oil if 26.3 g occupies 30.5 mL.
Answer: 0.862 g/mL
Density = Mass / Volume = 26.3 g / 30.5 mL = 0.862 g/mL (3 sig figs)


Q10. How many significant figures are in 3.0600?
Answer: 5 significant figures
3.0600 has 5 sig figs: the 3, the zero between 3 and 6, the 6, and the two trailing zeros after the decimal


Q11. How many significant figures are in 0.0151?
Answer: 3 significant figures
0.0151 has 3 sig figs: 1, 5, and 1. The leading zeros are NOT significant


Q12. Calculate 3.0600 ÷ 0.0151 and report the answer with the correct number of significant
figures.
Answer: 203
*3.0600 ÷ 0.0151 = 202.649... The divisor (0.0151) has 3 sig figs, so the answer should have 3 sig figs:
203*


Q13. Define accuracy.
Answer: Accuracy is the nearness of the measured value to the actual value of the quantity being
measured


Q14. Define precision.
Answer: Precision is the degree of agreement between several measured values of a quantity


Q15. What is the difference between mass and weight?
Answer: Mass is a measure of the amount of matter in an object and is independent of location. Weight is
a measure of the gravitational force acting on an object and depends on location


Q16. Identify the following as a physical or chemical change: melting ice.
Answer: Physical change
Melting is a reversible change; the substance (water) changes state but its chemical composition remains
the same

3|Page SUCCESS!!!

, Q17. Identify the following as a physical or chemical change: burning wood.
Answer: Chemical change
Burning produces new substances (ash, smoke, gases) and is irreversible


Q18. What is the atomic number of an element?
Answer: The atomic number is the number of protons in the nucleus of an atom (and also the number of
electrons in a neutral atom)


Q19. What is an isotope?
Answer: Isotopes are atoms of the same element that have different numbers of neutrons, and therefore
different mass numbers


Q20. What is the charge of an ion?
Answer: Ionic charge = protons - electrons


MODULE 2: PERIODIC TABLE & ATOMIC STRUCTURE
Key Concepts
• Periodic Trends:
o Atomic Radius: Increases down a group (more electron shells) and to the left across a
period (less nuclear pull)
o Ionization Energy: Increases up a group and to the right across a period
o Electronegativity: Increases up a group and to the right across a period
• Electron Configuration: Write both full configurations and noble gas shorthand
• Quantum Theory: Wave nature of light is supported by optical phenomena
(reflection/refraction), interference patterns from light passing through narrow slits, and
Maxwell's theory of electromagnetic radiation
• Element Symbols: Know common element symbols (Sb = Antimony, Pb = Lead, As = Arsenic,
Mn = Manganese, Ba = Barium, Hg = Mercury, Be = Beryllium, Bi = Bismuth, Ni = Nickel, Sr =
Strontium, F = Fluorine, S = Sulfur, Au = Gold, Sn = Tin, Ti = Titanium, W = Tungsten, Fe =
Iron)


MODULE 2 PRACTICE QUESTIONS


4|Page SUCCESS!!!

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Institution
Chem 103 Module 1 to 6
Module
Chem 103 Module 1 to 6

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Uploaded on
July 13, 2026
Number of pages
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Written in
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