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OCR A-Level Math (PURE MATH). All Exam Questions and Correct Answers | Graded A+ | 2025/2026 Update|

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OCR A-Level Math (PURE MATH). All Exam Questions and Correct Answers | Graded A+ | 2025/2026 Update|

Institution
ACT Math
Module
ACT Math

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OCR A-Level Math (PURE MATH). All Exam Questions and Correct
Answers | Graded A+ | 2025/2026 Update|


- Sn = n/2 (2a + (n-1)d)

- Sn = n/2 (a + l) where a is the first term and l is the last term - formula of an arithmetic
series


the sum of the terms of an arithmetic sequence - what is an arithmetic series


- Un = a + (n-1)d
- a = the first term

- d = the common difference - nth term of an arithmetic sequence


- Un = ar^(n-1)
- a = first term

- r = common ratio - nth term of a geometric sequence


- Sn = a(1-r^n) / 1-r
- Sn = a(r^n - 1) / r-1

where r does not equal 1 - formula of first n terms of a geometric sequence



the sum of the values tend towards infinity - divergent sequence


- the sum of the values tend towards a specific number

- it is only convergent if |r|<1 - convergent sequence



a / 1-r - sum to infinity of a geometric series

,- series can be shown using sigma notation


- defines each term of a sequence as a function of the previous term
- to find the members of the sequence substitute in n=1, n=2 ... using the previous terms given -
recurrence relation of form Un+1 = f(Un)



it is decreasing - if Un+1 < Un for all n ∈ ℕ, what is true of the sequence


- it is periodic
- means that the terms repeat in a cycle

- k = the order of the sequence (how often the terms repeat) - if Un+k = Un for all n ∈ ℕ,
what is true of the sequence


(x+y)(x-y) - x^2-y^2



* (a-sqrt(b) / a-sqrt(b)) - rationalising the denominator of e.g. 1/sqrt(b)+a


b^2 - 4ac > 0 has 2 distant real roots
B^2 -4ac = 0 has on real repeated root

b^2 - 4ac < 0 has no real roots - using the discriminant to find number of roots



if f(x) = a(x+p)^2 + q, then the turning point is (-p,q) - completing the square to find the
turning point


< is dotted line

≤ is solid line - using lines to represent < and ≤



x=0 and y=0 - where are the asymptotes of y = k/x

, translation up by a units - y = f(x) + a



translation left by a units - y = f(x+a)



stretch vertically by scale factor a - y = af(x)



stretch by scale factor 1/a horizontally - y = f(ax)



reflection in x-axis - y = -f(x)



reflection in y-axis - y = f(-x)



m = (y2 - y1)/(x2 - x1) - calculating the gradient with 2 points



y-y1=m(x-x1) - another way to calculate equation of a line



y= -(1/m)x - equation of line perpendicular to y = mx



Sqrt ((x2 - x1)^2 + (y2 - y1)^2 ) - distance between (x1,y1) and (x2,y2)



x^2 + y^2 = r^2 - equation of circle centre (0,0)



(x-a)^2 + (y-b)^2 = r^2 - equation of circle centre (a,b)


centre: (-f,-g)

radius: sqrt (f^2 + g^2 -c) - centre and radius of x^2 + y^2 + 2fx + 2gy + c = 0

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Institution
ACT Math
Module
ACT Math

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