,
,Study Guide & Uniform
Motion
↑
① Given
info and Diagram
B A
① Given info and
diagram
10 km
⑧ ⑧
Displacement
b) Average Velocity =
=T
Ok Total time
·
in
Okm
I Time
13 km
8 km
②
Convert Units =
OmIs
= (10km)(1000m) = (1Smins))in) ↳
10 km
·
=
900
=
10000m sec
a) Displacement straight
: line distance from
Distance initial position to final position
⑤ Average Speed =
Time
=
10000m/900s :
Okm
=
11 Im/S
.
1 Cyclist Cyclist
2nd
Q
T Vill =
10m/s
·
Vial =
12 m/s
&
Delay =
10 sec
Other way of
solving
I both going constant speed
Constant Speed of Motion Only (Relative
②
Caculate distance of lead ⑦ Determine't' needed to ↳
Xf =
Xi + Vt
cover relative speed
Aug . Speed = "It ①
Equation for both objects
110)
(10mis) = Plios Speed
= "It 1st Cyclist : (100m) + 110m/s)t
100m = D
(t)
(2m/s) = (100m)/(t) and Cyclist (0m) + (12m/s)t
:
② set equal
= I
③ Find Relative Speed (100m) + 110m/s)t =
10m) + (12m/s)t
t = So seconds l o t 10t
Vrelative =
(vi) (Va) -
100 + 10t = 12t
(10m/s) (12m/s)
=
= -
=
- 2m/s
50 = t
↳
speed at which cyclist must close
, Non-Uniform
Motion
change in velocity (DV)
O
Acceleration =
(DE)
change in time
-
AV =
(vz) -
(vi) A = iSm/s)/issed
DV =
(10m/s) -
(Sm/s) =
1m/s
?
AV
=
Sm/s
Dt = 5 see
① (0 , 0)
Zo
② (2 4) ,
(x2
- Xi)
speed =-Y1)
. .
14m
4m)/145
-
A Displacement
a) b) = 2s)
Speed
-
=
Atime
(4m
Om)/(2s
-
=
= -
Os) OmIs
=
2m/s el
speed is
↳
:
constant
DV = 0
C a= BY at d) =
0 mls/14-2 sees)
= Omis/as =
OmIs2 · concave up =
(t) acceleration
= ?
OmIs
- To find't' when police catches up
Vm =
25m/s ② Equations of Motions ③ Set X ,= X
car ast ast
Q Policemis
-
speed /no acceleration
2
10
Up =
10m/s a) Motorist -P
constant 2St =
10t + St
⑳
:
10ms Ut
Lazomis Ap =
Xf =
Xi + 0= 1St + Sta
motors
-
·
o +
= (2S)(t) 0 =
St(t 3) -
=
25t .. 3 seconds
6) Police car - -
not constant speed/accelerates
:
+ at
2
x = vt
=
(10m1s)(t) + 12 /10 m/s2) (t)2
=
10t ((2)10
+
+
2
2
=
10t + 5t
,Study Guide & Uniform
Motion
↑
① Given
info and Diagram
B A
① Given info and
diagram
10 km
⑧ ⑧
Displacement
b) Average Velocity =
=T
Ok Total time
·
in
Okm
I Time
13 km
8 km
②
Convert Units =
OmIs
= (10km)(1000m) = (1Smins))in) ↳
10 km
·
=
900
=
10000m sec
a) Displacement straight
: line distance from
Distance initial position to final position
⑤ Average Speed =
Time
=
10000m/900s :
Okm
=
11 Im/S
.
1 Cyclist Cyclist
2nd
Q
T Vill =
10m/s
·
Vial =
12 m/s
&
Delay =
10 sec
Other way of
solving
I both going constant speed
Constant Speed of Motion Only (Relative
②
Caculate distance of lead ⑦ Determine't' needed to ↳
Xf =
Xi + Vt
cover relative speed
Aug . Speed = "It ①
Equation for both objects
110)
(10mis) = Plios Speed
= "It 1st Cyclist : (100m) + 110m/s)t
100m = D
(t)
(2m/s) = (100m)/(t) and Cyclist (0m) + (12m/s)t
:
② set equal
= I
③ Find Relative Speed (100m) + 110m/s)t =
10m) + (12m/s)t
t = So seconds l o t 10t
Vrelative =
(vi) (Va) -
100 + 10t = 12t
(10m/s) (12m/s)
=
= -
=
- 2m/s
50 = t
↳
speed at which cyclist must close
, Non-Uniform
Motion
change in velocity (DV)
O
Acceleration =
(DE)
change in time
-
AV =
(vz) -
(vi) A = iSm/s)/issed
DV =
(10m/s) -
(Sm/s) =
1m/s
?
AV
=
Sm/s
Dt = 5 see
① (0 , 0)
Zo
② (2 4) ,
(x2
- Xi)
speed =-Y1)
. .
14m
4m)/145
-
A Displacement
a) b) = 2s)
Speed
-
=
Atime
(4m
Om)/(2s
-
=
= -
Os) OmIs
=
2m/s el
speed is
↳
:
constant
DV = 0
C a= BY at d) =
0 mls/14-2 sees)
= Omis/as =
OmIs2 · concave up =
(t) acceleration
= ?
OmIs
- To find't' when police catches up
Vm =
25m/s ② Equations of Motions ③ Set X ,= X
car ast ast
Q Policemis
-
speed /no acceleration
2
10
Up =
10m/s a) Motorist -P
constant 2St =
10t + St
⑳
:
10ms Ut
Lazomis Ap =
Xf =
Xi + 0= 1St + Sta
motors
-
·
o +
= (2S)(t) 0 =
St(t 3) -
=
25t .. 3 seconds
6) Police car - -
not constant speed/accelerates
:
+ at
2
x = vt
=
(10m1s)(t) + 12 /10 m/s2) (t)2
=
10t ((2)10
+
+
2
2
=
10t + 5t
