LADWP ELECTRICAL CRAFT HELPER EXAM COMPLETE
EXAM QUESTIONS AND VERIFIED ANSWERS | 2026–2027
LATEST UPDATE | DETAILED RATIONALES | FULL STUDY
GUIDE | EXAM PREP | PRACTICE TEST | CERTIFICATION
PREPARATION
Section One — Questions 1–100
1. Before inspecting an electrical enclosure, what is the safest first step?
A) Follow the authorized de-energization and lockout/tagout procedure
B) Ask a coworker to stand nearby while opening it
C) Touch the enclosure to check whether it is warm
D) Assume the switch is off because the indicator is dark
Correct Answer: A) Follow the authorized de-energization and lockout/tagout procedure
Rationale: An indicator or switch position does not establish an electrically safe work condition.
Authorized personnel must isolate energy sources, apply the required lockout/tagout controls,
and verify absence of voltage with an appropriately rated tester. Touching equipment or relying
on another person does not replace the formal process.
2. A training circuit has 24 V across a 6 Ω resistor. What current flows?
A) 6 A
B) 2 A
C) 5 A
D) 4 A
Correct Answer: D) 4 A
Rationale: Ohm’s law gives current as voltage divided by resistance. Here 24 ÷ 6 = 4 amperes.
Multiplying voltage by resistance or adding the two quantities does not calculate current. Check
the units: volts divided by ohms yields amperes.
3. A resistive test load draws 2 A through 5 Ω. What is the voltage across it?
A) 11 V
B) 15 V
C) 8 V
D) 10 V
Correct Answer: D) 10 V
Rationale: Use Ohm’s law V = IR for a resistive load. Multiplying 2 amperes by 5 ohms gives 10
volts. Dividing these quantities would not give the required voltage. This relation applies when
the stated resistance and current refer to the same element.
,4. A DC training load operates at 12 V and draws 2 A. What is its electrical power?
A) 25 W
B) 36 W
C) 24 W
D) 22 W
Correct Answer: C) 24 W
Rationale: For this DC load, power equals voltage multiplied by current. The calculation 12 × 2
gives 24 watts. Current alone or resistance alone cannot determine the answer. The power
equation is a foundational check when evaluating loads and nameplate information.
5. Why is an equipment grounding conductor provided?
A) To eliminate the need for circuit breakers
B) To carry normal load current in place of the neutral
C) To create a low-impedance fault-current path for protective-device operation
D) To increase the operating voltage of the circuit
Correct Answer: C) To create a low-impedance fault-current path for protective-device
operation
Rationale: Equipment grounding conductors bond exposed conductive parts and support rapid
operation of protective devices when a fault occurs. They are not intended to carry normal
neutral current, raise voltage, or replace overcurrent protection. Grounding and bonding are
complementary parts of an electrical safety system.
6. Two resistors of 4 Ω and 6 Ω are connected in series. What is their combined resistance?
A) 15 Ω
B) 10 Ω
C) 11 Ω
D) 8 Ω
Correct Answer: B) 10 Ω
Rationale: Resistances in series add because the same current travels through each element.
Adding 4 and 6 gives 10 ohms. The reciprocal formula belongs to parallel networks, not this
single current path. The result should exceed either individual resistance.
7. Two identical 4 Ω resistors are connected in parallel. What is their equivalent
resistance?
A) 3 Ω
B) 2 Ω
C) 4 Ω
D) 0 Ω
Correct Answer: B) 2 Ω
Rationale: Two identical resistances in parallel have an equivalent resistance equal to half
either branch value. Thus 4 ÷ 2 = 2 ohms. Parallel paths provide additional routes for current, so
the equivalent resistance is less than either branch. Adding them would describe a series
connection.
,8. A conduit support span is 6 feet long. How many inches is that?
A) 108 in
B) 72 in
C) 73 in
D) 70 in
Correct Answer: B) 72 in
Rationale: Each foot contains 12 inches, so 6 feet corresponds to 6 × 12 = 72 inches. This is a
unit conversion rather than an electrical calculation. Keeping units explicit helps prevent layout
and fabrication errors when plans use different measurement systems.
9. A damaged extension cord has exposed conductors. What should a helper do?
A) Remove it from service and report it under site procedures
B) Wrap it with ordinary paper and continue working
C) Use it only for small loads
D) Move it out of sight until the shift ends
Correct Answer: A) Remove it from service and report it under site procedures
Rationale: Exposed conductors present shock, arc, and fire hazards regardless of the size of the
connected load. Removing defective equipment from service prevents accidental reuse until
qualified repair or replacement. Temporary concealment and improvised insulation are not safe
substitutes for an approved inspection process.
10. A storeroom has 20 identical connectors. How many connectors represent 20% of the
stock?
A) 4 connectors
B) 2 connectors
C) 5 connectors
D) 6 connectors
Correct Answer: A) 4 connectors
Rationale: Twenty percent is one fifth of a quantity. Dividing 20 by five gives 4 connectors.
Percentage problems require converting the percentage to a fraction or decimal before
multiplying. The same reasoning is useful when estimating inventory use and reorder quantities.
11. A rectangular equipment pad is 6 ft long and 6 ft wide. What is its area?
A) 34 ft²
B) 54 ft²
C) 37 ft²
D) 36 ft²
Correct Answer: D) 36 ft²
Rationale: Rectangular area is length multiplied by width. Multiplying 6 feet by 6 feet gives 36
square feet. Adding the dimensions would contribute to perimeter, not area. Distinguishing
linear from square units matters for materials and workspace estimates.
, 12. A rectangular fenced work area measures 8 ft by 6 ft. What is its perimeter?
A) 29 ft
B) 26 ft
C) 28 ft
D) 42 ft
Correct Answer: C) 28 ft
Rationale: The perimeter is the distance around all four sides of a rectangle. Compute 2 × (8 + 6)
= 28 feet. Multiplying the dimensions would produce area instead. Perimeter is useful for
estimating barrier lengths and edge marking.
13. Which tool is most suitable for checking whether a circuit is energized?
A) A tape measure held near the conductor
B) An appropriately rated voltage tester used according to procedure
C) A non-rated household lamp connected to unknown terminals
D) An ordinary screwdriver touched to the terminal
Correct Answer: B) An appropriately rated voltage tester used according to procedure
Rationale: Voltage testing requires equipment with the appropriate category and voltage rating,
suitable condition, and a verified operating procedure. Improvised indicators can fail
dangerously or expose the worker to live parts. The correct test method also includes proving
the tester functions before and after use when required.
14. A crew installs 30 feet of raceway in 6 equal hours. What is the average installation
rate?
A) 7 ft/hour
B) 6 ft/hour
C) 3 ft/hour
D) 5 ft/hour
Correct Answer: D) 5 ft/hour
Rationale: Average rate equals total quantity divided by elapsed time. Dividing 30 feet by 6 hours
gives 5 feet per hour. Multiplying would not produce a rate. An average describes the full interval
and does not imply that progress was identical in every hour.
15. A training circuit has 36 V across a 9 Ω resistor. What current flows?
A) 4 A
B) 5 A
C) 2 A
D) 6 A
Correct Answer: A) 4 A
Rationale: Ohm’s law gives current as voltage divided by resistance. Here 36 ÷ 9 = 4 amperes.
Multiplying voltage by resistance or adding the two quantities does not calculate current. Check
the units: volts divided by ohms yields amperes.
EXAM QUESTIONS AND VERIFIED ANSWERS | 2026–2027
LATEST UPDATE | DETAILED RATIONALES | FULL STUDY
GUIDE | EXAM PREP | PRACTICE TEST | CERTIFICATION
PREPARATION
Section One — Questions 1–100
1. Before inspecting an electrical enclosure, what is the safest first step?
A) Follow the authorized de-energization and lockout/tagout procedure
B) Ask a coworker to stand nearby while opening it
C) Touch the enclosure to check whether it is warm
D) Assume the switch is off because the indicator is dark
Correct Answer: A) Follow the authorized de-energization and lockout/tagout procedure
Rationale: An indicator or switch position does not establish an electrically safe work condition.
Authorized personnel must isolate energy sources, apply the required lockout/tagout controls,
and verify absence of voltage with an appropriately rated tester. Touching equipment or relying
on another person does not replace the formal process.
2. A training circuit has 24 V across a 6 Ω resistor. What current flows?
A) 6 A
B) 2 A
C) 5 A
D) 4 A
Correct Answer: D) 4 A
Rationale: Ohm’s law gives current as voltage divided by resistance. Here 24 ÷ 6 = 4 amperes.
Multiplying voltage by resistance or adding the two quantities does not calculate current. Check
the units: volts divided by ohms yields amperes.
3. A resistive test load draws 2 A through 5 Ω. What is the voltage across it?
A) 11 V
B) 15 V
C) 8 V
D) 10 V
Correct Answer: D) 10 V
Rationale: Use Ohm’s law V = IR for a resistive load. Multiplying 2 amperes by 5 ohms gives 10
volts. Dividing these quantities would not give the required voltage. This relation applies when
the stated resistance and current refer to the same element.
,4. A DC training load operates at 12 V and draws 2 A. What is its electrical power?
A) 25 W
B) 36 W
C) 24 W
D) 22 W
Correct Answer: C) 24 W
Rationale: For this DC load, power equals voltage multiplied by current. The calculation 12 × 2
gives 24 watts. Current alone or resistance alone cannot determine the answer. The power
equation is a foundational check when evaluating loads and nameplate information.
5. Why is an equipment grounding conductor provided?
A) To eliminate the need for circuit breakers
B) To carry normal load current in place of the neutral
C) To create a low-impedance fault-current path for protective-device operation
D) To increase the operating voltage of the circuit
Correct Answer: C) To create a low-impedance fault-current path for protective-device
operation
Rationale: Equipment grounding conductors bond exposed conductive parts and support rapid
operation of protective devices when a fault occurs. They are not intended to carry normal
neutral current, raise voltage, or replace overcurrent protection. Grounding and bonding are
complementary parts of an electrical safety system.
6. Two resistors of 4 Ω and 6 Ω are connected in series. What is their combined resistance?
A) 15 Ω
B) 10 Ω
C) 11 Ω
D) 8 Ω
Correct Answer: B) 10 Ω
Rationale: Resistances in series add because the same current travels through each element.
Adding 4 and 6 gives 10 ohms. The reciprocal formula belongs to parallel networks, not this
single current path. The result should exceed either individual resistance.
7. Two identical 4 Ω resistors are connected in parallel. What is their equivalent
resistance?
A) 3 Ω
B) 2 Ω
C) 4 Ω
D) 0 Ω
Correct Answer: B) 2 Ω
Rationale: Two identical resistances in parallel have an equivalent resistance equal to half
either branch value. Thus 4 ÷ 2 = 2 ohms. Parallel paths provide additional routes for current, so
the equivalent resistance is less than either branch. Adding them would describe a series
connection.
,8. A conduit support span is 6 feet long. How many inches is that?
A) 108 in
B) 72 in
C) 73 in
D) 70 in
Correct Answer: B) 72 in
Rationale: Each foot contains 12 inches, so 6 feet corresponds to 6 × 12 = 72 inches. This is a
unit conversion rather than an electrical calculation. Keeping units explicit helps prevent layout
and fabrication errors when plans use different measurement systems.
9. A damaged extension cord has exposed conductors. What should a helper do?
A) Remove it from service and report it under site procedures
B) Wrap it with ordinary paper and continue working
C) Use it only for small loads
D) Move it out of sight until the shift ends
Correct Answer: A) Remove it from service and report it under site procedures
Rationale: Exposed conductors present shock, arc, and fire hazards regardless of the size of the
connected load. Removing defective equipment from service prevents accidental reuse until
qualified repair or replacement. Temporary concealment and improvised insulation are not safe
substitutes for an approved inspection process.
10. A storeroom has 20 identical connectors. How many connectors represent 20% of the
stock?
A) 4 connectors
B) 2 connectors
C) 5 connectors
D) 6 connectors
Correct Answer: A) 4 connectors
Rationale: Twenty percent is one fifth of a quantity. Dividing 20 by five gives 4 connectors.
Percentage problems require converting the percentage to a fraction or decimal before
multiplying. The same reasoning is useful when estimating inventory use and reorder quantities.
11. A rectangular equipment pad is 6 ft long and 6 ft wide. What is its area?
A) 34 ft²
B) 54 ft²
C) 37 ft²
D) 36 ft²
Correct Answer: D) 36 ft²
Rationale: Rectangular area is length multiplied by width. Multiplying 6 feet by 6 feet gives 36
square feet. Adding the dimensions would contribute to perimeter, not area. Distinguishing
linear from square units matters for materials and workspace estimates.
, 12. A rectangular fenced work area measures 8 ft by 6 ft. What is its perimeter?
A) 29 ft
B) 26 ft
C) 28 ft
D) 42 ft
Correct Answer: C) 28 ft
Rationale: The perimeter is the distance around all four sides of a rectangle. Compute 2 × (8 + 6)
= 28 feet. Multiplying the dimensions would produce area instead. Perimeter is useful for
estimating barrier lengths and edge marking.
13. Which tool is most suitable for checking whether a circuit is energized?
A) A tape measure held near the conductor
B) An appropriately rated voltage tester used according to procedure
C) A non-rated household lamp connected to unknown terminals
D) An ordinary screwdriver touched to the terminal
Correct Answer: B) An appropriately rated voltage tester used according to procedure
Rationale: Voltage testing requires equipment with the appropriate category and voltage rating,
suitable condition, and a verified operating procedure. Improvised indicators can fail
dangerously or expose the worker to live parts. The correct test method also includes proving
the tester functions before and after use when required.
14. A crew installs 30 feet of raceway in 6 equal hours. What is the average installation
rate?
A) 7 ft/hour
B) 6 ft/hour
C) 3 ft/hour
D) 5 ft/hour
Correct Answer: D) 5 ft/hour
Rationale: Average rate equals total quantity divided by elapsed time. Dividing 30 feet by 6 hours
gives 5 feet per hour. Multiplying would not produce a rate. An average describes the full interval
and does not imply that progress was identical in every hour.
15. A training circuit has 36 V across a 9 Ω resistor. What current flows?
A) 4 A
B) 5 A
C) 2 A
D) 6 A
Correct Answer: A) 4 A
Rationale: Ohm’s law gives current as voltage divided by resistance. Here 36 ÷ 9 = 4 amperes.
Multiplying voltage by resistance or adding the two quantities does not calculate current. Check
the units: volts divided by ohms yields amperes.
