Solution Manual for Finite Mathematics and Its Applications (13th Edition) – Larry J. Goldstein – Full Solutions (Chapters 1–12)

SOLUTION MANUAL yu




Finite Mathematics & Its Applications
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13th Edition by Larry J. Goldstein,
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Chapters 1 - 12, Complete
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, Contents
Chapter 1: LinearEquationsandStraightLines
yu yu yu yu yu 1–1

Chapter 2: Matrices
yu 2–1

Chapter 3: Linear Programming, A Geometric Approach
yu yu yu yu yu 3–1

Chapter4: The Simplex Method
yu yu yu 4–1

Chapter 5: Sets and Counting
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Chapter 6: Probability
yu 6–1

Chapter 7: Probability and Statistics
yu yu yu 7–1

Chapter 8: Markov Processes
yu yu 8–1

Chapter9: The Theory of Games
yu yu yu yu 9–1

Chapter10: TheMathematics of Finance
yu yu yu yu 10–1

Chapter11: Logic
yu 11–1

Chapter12: DifferenceEquationsandMathematicalModels
yu yu yu yu yu 12–1

, Chapter 1 yu




Exercises1.1 5
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6. Left 1, down
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2
1. Right 2, up 3 yu yu yu

y
y



(2, 3)
x
x
( –1, – 52 )


7. Left 20, up 40
2. Left 1, up 4
y u yu yu yu




yu yu yu

y
y

(–20, 40)
(–1, 4)
x
x




8. Right 25, up 30
3. Down 2
y u yu yu yu




y u yu

y
y


(25, 30)
x
x
(0, –2)




9. Point Q is 2 units to the left and 2 units up or
4. Right 2
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yu




y (—2,2). uy




10. Point P is 3 units to the right and 2 units down or
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(3,—2).
x
(2, 0) 1
11. —2(1)+ (3) =—2+1=—1so yes the point is
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uy uy yu uy uy uy uy y u y u y u y u




3
on the line. yu yu




5. Left 2, up 1 1
12. —2(2)+ (6) =—1is false, so no the point is not
yu

yu yu yu


uy uy yu uy yu y u y u y u y u y u y u y u




y
3
on the line yu yu




(–2, 1)
x



Copyright © 2023 Pearson Education, Inc. 1-1

, Chapter 1: Linear Equations and Straight Lines ISM: Finite Math


1 24. 0 = 5
y u yu yu




—2x+ y =—1 Substitute the x and y
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13 yu uy y u uy y u y u y u y u y u


no solution
3
yu




. x-intercept: none
coordinates of the point into the equation:
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When x = 0, y = 5y-
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f 1 ıh f h
' ,3 →—2 ' 1 ı +1(3)=—1→—1+1=—1 is
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y


u
y
u
y u
y




intercept: (0, 5)
y' ı 'y ıJ
u
y u
y u
y u
y u
y u
y u
y u
y y u
u
y
yu yu




2 J 2 3 yu yu
y u u
y




a false statement. So no the point is not on
yu yu yu yu yu yu yu yu yu
25. When y = 0, x = 7 x-
yu yu yu yu yu yu yu u
y




theline.
yu u
y
intercept: (7, 0) 0 yu yu u
y




f 1h f1 h =7 yu yu




14 —2 ' ı + ' ı (—1)=—1 is true so yes the point is no solution
.
u
y u
y y u yu yu yu yu yu yu
yu




'y3 ıJ 'y3 ıJ y-intercept:none u
y




yu yuyu




on the line. yu yu


26. 0 = –8x
y u yu yu




15. m = 5, b = 8 y u yu yu yu yu yu
x=0 yu yu




x-intercept: (0, 0) yu yu




16. m = –2 and b = –6
y u yu yu yu yu yu yu
y = –8(0) yu yu




y=0 yu yu




17. y u y = 0x + 3; m = 0, b = 3
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y-intercept: (0, 0) yu yu




2 2 1
0 = x –1
y u




y = x+0; m= , b=0 27
yu u
y

yu y u yu uy




18 yu yu yu u
y y u yu yu y u yu u
y




3
3 3 .
. x =3 yu yu




19. 14x+7y =21 x-intercept: (3, 0) yu yu




1
y u yu u
y u
y yu u
y




y = (0) –1
yu




7y =—14x+21 uy yu uy yu uy
y u y u yu uy




3
y =—2x +3
y = –1
y u uy yu uy




yu yu




y-intercept: (0, –1) yu yu




20 x — y =3 yu uy y u uy
y
. —y =—x+3 y u uy yu uy




y = x— 3 yu yu yu uy




(3, 0)
21. 3x =5
yu yu y u yu u
y
x
5 (0, –1)
x= yu u
y




3
1 2
28. When x = 0, y = 0.
– x+ y =10
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22 2
yu




3
y u uy




When x = 1, y = 2.
. yu yu yu yu yu yu




2 1 y
y= x+10
y u y u




y u y u yu




3 2
3
y = x+15
y u




y u y u yu

(1, 2)
4 x
(0, 0)

23. 0 =—4x +8 yu uy yu uy




4x =8 y u uy




x =2 yu yu




x-intercept: (2, 0) yu yu




y = –4(0) + 8yu yu yu yu




y=8 yu yu




y-intercept: (0, 8) yu yu




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