Calculation Type I: Specific Heat Capacity - (𝑄 = 𝑚𝑐∆𝑇)
1. Level 1: Basic Energy Calculation: Calculate the heat (Q) absorbed by 15.0 g of liquid water
(c=4.18 J/gºC) to raise its temperature from 20.0ºC to 50.0ºC.
2. Level 2: Temperature Change Calculation: A 5.00 g piece of iron metal (c=0.449 J/gºC) just
transferred 180 J of heat. Calculate the total change in temperature (ΔT).
3. Level 3: Specific Heat Identification: A 121.6 g sample of an unknown metal was heated, causing
its temperature to rise from 20.4ºC to 35.5ºC. If 235 J of heat were added, calculate the specific
heat capacity (c) and identify if it matches Lead (c=0.128 J/gºC).
4. Level 4: Mass Determination: How many grams of water are present if 15048 J of energy are
required to increase the temperature from 25.0ºC to 55.0ºC?
5. Level 5: Multi-Step Temperature Finality: A 121.6 g sample of Lead (c=0.128 J/gºC) at an initial
temperature of 20.4ºC absorbs 450. J of energy. Calculate the final temperature (T final).
6. Level 6: Unit Conversion Challenge: Calculate the energy change in kilojoules (kJ) when 1.20 kg of
water is heated from 25.0ºC to 55.0ºC.