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You have a 6-face die E[X1 + X2] = E[X1] + E[X2] = 3.5 + 5.5 = 9
and a 10-face die. What is
the expected value of
the sum of the two?
If it is a good day (G) E_{B|G} = 0.41 + 0.6(1 + E_{B|G}) which leads to
there are 60% chances E_{B|G} = 2.5.
tomorrow will be G and E_{B|B} = 0.71 + 0.3(1 + E_{B|G}) = 1 + 0.3*2.5 = 1.75
40% chances tomorrow
will be bad (B). If it is a B
day, there 30% chances
tomorrow will be G and
70% chances tomorrow
will be B. If today is B,
what is the expected
number of days before
seeing another B?
You flip a weighted coin P = (5 choose 3) 0.6^3 0.4^2 + (5 choose 4) 0.6^4
that comes up H with 0.4^1 + (5 choose 5) * 0.6^5 = 0.68256 ~= 0.68
probability 0.4 and T with
probability 0.6. If you flip
the coin 5 times, what is
the probability that you
see at least 3 tails?