GUIDE 2026 QUESTIONS WITH ANSWERS
GRADED A+
◉ 1) Cl-O bond electronegativity difference = 3.5 - 3.0 = 0.5
(1.6 - 0.5 bond is Polar)
H-O bond electronegativity difference = 3.5 - 2.1 = 1.4
(1.6 - 0.5 bond is Polar)
2) C≡N bond electronegativity difference = 3.0 - 2.5 = 0.5
(1.6 - 0.5 bond is Polar)
H-C bond electronegativity difference = 2.5 - 2.1 = 0.4
(< 0.5 bond is Nonpolar). Answer: Using the electronegativity values
from the equation bank, show the determination of the polarity of each
different type of bond in the following molecules:
◉ Your Answer:
NH3
N = 5, H = 3, 8 total
H
..
, H:N:H
..
SO2
S = 6, O = 12, total = 18
.. .. ..
: O : S :: O
.. ..
CH3OH
C = 4, H = 4, O = 6, total = 14
H
.. ..
H:C:O:H
.. ..
H
HNO2
H = 1, N = 5, O = 12, total = 18
.. .. ..
H:O:N::O:
..
N2
N = 10