ASCP Lab math
Chamberlain College Of Nursing
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Examen
ASCP Lab math
The weight of NaCl present in 650 ml of a 0.85% NaCl solution is: 
Weight (in grams) of substance in a quantity of solution = (total ml volume / 100 mL) x (percent 
concentration) So: 
Weight = (650 mL / 100 mL) x (0.85%) = 5.525 grams 
Proficiency Testing Service (e.g., CAP) reported the following results for a Cholesterol test (unknown 
Control) reported by your laboratory. Your results were compared with 648 other labs using the same 
type instrumentation and methodology: 
Your Result = 168 m...