CHEM 103
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Latest content CHEM 103
CHEM 103 
MODULE 5 EXAM 2022 
Question 1 
Click this link to access the Periodic Table. This may be helpful throughout the exam. 
Show the determination of the charge on the ion formed by the Se34 atom. Se34 
(nonmetal = gain electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p4 gain 2e 
→ Se-2 
Question 2 
Click this link to access the Periodic Table. This may be helpful throughout the exam. 
H = 2.1 
Li = 1.0 Be = 1.5 B = 2.0 C = 2.5 N = 
3.0 O= 3.5 F = 4.03 
3 
Na = 1.0 
2.1 
Mg = 1.2 
S = 2.5 
Al = ...
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CHEM 103•CHEM 103
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CHEM 103 2022 EXAM• By ExceLgrades
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CHEM 103 
MODULE 5 EXAM 2022 
Question 1 
Click this link to access the Periodic Table. This may be helpful throughout the exam. 
Show the determination of the charge on the ion formed by the Se34 atom. Se34 
(nonmetal = gain electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p4 gain 2e 
→ Se-2 
Question 2 
Click this link to access the Periodic Table. This may be helpful throughout the exam. 
H = 2.1 
Li = 1.0 Be = 1.5 B = 2.0 C = 2.5 N = 
3.0 O= 3.5 F = 4.03 
3 
Na = 1.0 
2.1 
Mg = 1.2 
S = 2.5 
Al = ...
CHEM 103 
MODULE 4 EXAM 2022 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
Write the subshell electron configuration (i.e.1s2 2s2, etc.) for the Fe26 atom. Fe26 = 26 
electrons = 1s2 2s2 2p6 3s2 3p6 4s2 3d6 
Click this link to access the Periodic Table.This may be helpful throughout 
the exam. 
Write the subshell electron configuration (i.e.1s2 2s2, etc.) for the S16 atom. S16 = 16 
electrons = 1s2 2s2 2p6 3s2 3p4 
Click this link to access the Periodi...
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CHEM 103•CHEM 103
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CHEM 103 2022 EXAM• By ExceLgrades
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CHEM 103 
MODULE 4 EXAM 2022 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
Write the subshell electron configuration (i.e.1s2 2s2, etc.) for the Fe26 atom. Fe26 = 26 
electrons = 1s2 2s2 2p6 3s2 3p6 4s2 3d6 
Click this link to access the Periodic Table.This may be helpful throughout 
the exam. 
Write the subshell electron configuration (i.e.1s2 2s2, etc.) for the S16 atom. S16 = 16 
electrons = 1s2 2s2 2p6 3s2 3p4 
Click this link to access the Periodi...
CHEM 103 
MODULE 3 EXAM 2022 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
A reaction between HCl and NaOH is being studied in a styrofoam coffee cup 
with NO lid and the heat given off is measured by means of a thermometer 
immersed in the reaction mixture. Enter the correct thermochemistry term 
to describe the item listed. 
1. The type of thermochemical process 
2. The amount of heat released in the reaction of HCl with NaOH 
1. Heat given off = Exo...
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CHEM 103•CHEM 103
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CHEM 103 2022 EXAM• By ExceLgrades
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CHEM 103 
MODULE 3 EXAM 2022 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
A reaction between HCl and NaOH is being studied in a styrofoam coffee cup 
with NO lid and the heat given off is measured by means of a thermometer 
immersed in the reaction mixture. Enter the correct thermochemistry term 
to describe the item listed. 
1. The type of thermochemical process 
2. The amount of heat released in the reaction of HCl with NaOH 
1. Heat given off = Exo...
CHEM 103 
MODULE 2 EXAM 2022 
Question 1 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
Show the calculation of the molecular weight for the following 
compounds, reporting your answer to 2 places after the decimal. 
1. Al2(CO3)3 
2. C8H6NO4Cl 
1. 2Al + 3C + 9O = 233.992. 8C + 6H + N + 4O + Cl = 215.59 
Question 2 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
Show the calculation of the number of moles in the ...
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CHEM 103•CHEM 103
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CHEM 103 2022 EXAM• By ExceLgrades
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CHEM 103 
MODULE 2 EXAM 2022 
Question 1 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
Show the calculation of the molecular weight for the following 
compounds, reporting your answer to 2 places after the decimal. 
1. Al2(CO3)3 
2. C8H6NO4Cl 
1. 2Al + 3C + 9O = 233.992. 8C + 6H + N + 4O + Cl = 215.59 
Question 2 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
Show the calculation of the number of moles in the ...
Portage Chemistry 103 Module 2 Exam Study 
 
2.1: MOLECULAR WEIGHT Correct Answer: A compound is made up of two or more elements combined in a definite ratio that is represented by a molecular formula. Each of these elements has a certain atomic weight, which can be found in the periodic table. The sum of the atomic weights of the atoms in the molecular formula is called the formula weight or molecular weight or formula mass. 
 
Ca3(PO4)2 Correct Answer: calcium phosphate 
Molecular Weight = 
...
- Exam (elaborations)
- • 12 pages's •
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CHEM 103•CHEM 103
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Portage Chemistry 103 Module 2 Exam Study 
 
2.1: MOLECULAR WEIGHT Correct Answer: A compound is made up of two or more elements combined in a definite ratio that is represented by a molecular formula. Each of these elements has a certain atomic weight, which can be found in the periodic table. The sum of the atomic weights of the atoms in the molecular formula is called the formula weight or molecular weight or formula mass. 
 
Ca3(PO4)2 Correct Answer: calcium phosphate 
Molecular Weight = 
...
CHEM 103 
FINAL EXAM 
Question 1 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
1. Convert 845.3 to exponential form and explain your answer. 
2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 
1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places 
= 8.453 x 102 
2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 
places = 0. 
Question 2Click this link to access the Periodic Table. This may b...
- Exam (elaborations)
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CHEM 103•CHEM 103
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CHEM 103 
FINAL EXAM 
Question 1 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
1. Convert 845.3 to exponential form and explain your answer. 
2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 
1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places 
= 8.453 x 102 
2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 
places = 0. 
Question 2Click this link to access the Periodic Table. This may b...
Question 1 
Not yet graded / 10 pts 
Question 2 
Not yet graded / 10 pts 
Question 3 
Not yet graded / 10 pts 
CHEM 103 
MODULE 6 2022 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
List and explain if each of the following solutions conducts an electric 
current: sodium chloride (NaCl), hydrochloric acid (HCl) and sugar (C6H12O6). 
Sodium chloride (NaCl) is an ionic compound and conducts since it forms ions 
in solution. Hydrochloric acid (HCl) is a po...
- Exam (elaborations)
- • 6 pages's •
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CHEM 103•CHEM 103
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Question 1 
Not yet graded / 10 pts 
Question 2 
Not yet graded / 10 pts 
Question 3 
Not yet graded / 10 pts 
CHEM 103 
MODULE 6 2022 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
List and explain if each of the following solutions conducts an electric 
current: sodium chloride (NaCl), hydrochloric acid (HCl) and sugar (C6H12O6). 
Sodium chloride (NaCl) is an ionic compound and conducts since it forms ions 
in solution. Hydrochloric acid (HCl) is a po...
CHEM 103 
MODULE 5 EXAM 2022 
Question 1 
Click this link to access the Periodic Table. This may be helpful throughout the exam. 
Show the determination of the charge on the ion formed by the Se34 atom. Se34 
(nonmetal = gain electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p4 gain 2e 
→ Se-2 
Question 2 
Click this link to access the Periodic Table. This may be helpful throughout the exam. 
H = 2.1 
Li = 1.0 Be = 1.5 B = 2.0 C = 2.5 N = 
3.0 O= 3.5 F = 4.03 
3 
Na = 1.0 
2.1 
Mg = 1.2 
S = 2.5 
Al = ...
- Exam (elaborations)
- • 5 pages's •
-
CHEM 103•CHEM 103
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CHEM 103 
MODULE 5 EXAM 2022 
Question 1 
Click this link to access the Periodic Table. This may be helpful throughout the exam. 
Show the determination of the charge on the ion formed by the Se34 atom. Se34 
(nonmetal = gain electrons) 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p4 gain 2e 
→ Se-2 
Question 2 
Click this link to access the Periodic Table. This may be helpful throughout the exam. 
H = 2.1 
Li = 1.0 Be = 1.5 B = 2.0 C = 2.5 N = 
3.0 O= 3.5 F = 4.03 
3 
Na = 1.0 
2.1 
Mg = 1.2 
S = 2.5 
Al = ...
CHEM 103 
MODULE 4 EXAM 2022 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
Write the subshell electron configuration (i.e.1s2 2s2, etc.) for the Fe26 atom. Fe26 = 26 
electrons = 1s2 2s2 2p6 3s2 3p6 4s2 3d6 
Click this link to access the Periodic Table.This may be helpful throughout 
the exam. 
Write the subshell electron configuration (i.e.1s2 2s2, etc.) for the S16 atom. S16 = 16 
electrons = 1s2 2s2 2p6 3s2 3p4 
Click this link to access the Periodi...
- Exam (elaborations)
- • 5 pages's •
-
CHEM 103•CHEM 103
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CHEM 103 
MODULE 4 EXAM 2022 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
Write the subshell electron configuration (i.e.1s2 2s2, etc.) for the Fe26 atom. Fe26 = 26 
electrons = 1s2 2s2 2p6 3s2 3p6 4s2 3d6 
Click this link to access the Periodic Table.This may be helpful throughout 
the exam. 
Write the subshell electron configuration (i.e.1s2 2s2, etc.) for the S16 atom. S16 = 16 
electrons = 1s2 2s2 2p6 3s2 3p4 
Click this link to access the Periodi...
CHEM 103 
MODULE 1 EXAM 2022 
Question 1 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
1. Convert 845.3 to exponential form and explain your answer. 
2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 
1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places 
= 8.453 x 102 
2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 
places = 0. 
Question 2 
Click this link to access the Periodic Table. ...
- Package deal
- Exam (elaborations)
- • 5 pages's •
-
CHEM 103•CHEM 103
-
CHEM 103 2022 EXAM• By ExceLgrades
Preview 2 out of 5 pages
Getting your document ready...
CHEM 103 
MODULE 1 EXAM 2022 
Question 1 
Click this link to access the Periodic Table. This may be helpful throughout 
the exam. 
1. Convert 845.3 to exponential form and explain your answer. 
2. Convert 3.21 x 10-5 to ordinary form and explain your answer. 
1. Convert 845.3 = larger than 1 = positive exponent, move decimal 2 places 
= 8.453 x 102 
2. Convert 3.21 x 10-5 = negative exponent = smaller than 1, move decimal 5 
places = 0. 
Question 2 
Click this link to access the Periodic Table. ...