100% tevredenheidsgarantie Direct beschikbaar na je betaling Lees online óf als PDF Geen vaste maandelijkse kosten 4,6 TrustPilot
logo-home
Tentamen (uitwerkingen)

Chapter 9 Inferences based on two samples - Devore Test Bank

Beoordeling
-
Verkocht
-
Pagina's
32
Cijfer
A+
Geüpload op
08-11-2025
Geschreven in
2025/2026

Chapter 9 Inferences based on two samples - Devore Test Bank

Instelling
Vak

Voorbeeld van de inhoud

Chapter 9 Inferences based on two samples



COMPLETION

1. Let be a random sample from a population with mean
be a random sample with mean and that the X and Y samples are independent of one another.
The expected value of is and the standard deviation of = .


ANS:
PTS: 1

2. Let be a random sample from a normal population with mean
be a random sample from a normal population with mean
be a random sample from a normal population with mean
=16, and that X and Y samples are independent of one another. If the sample mean values are
then the value of the test statistic to test is z =
and that will be rejected at .01 significance level if

ANS: -1.45, 2.58, -2.58

PTS: 1

3. In testing the computed value of the test statistic is z = 2.25. The P-value for
this two-tailed test is then .

ANS: .0244

PTS: 1

4. Investigators are often interested in comparing the effects of two different treatments on a response. If the individuals
or subjects to be used in the comparison are not assigned by the investigators to the two treatments, the study is said
to be . If the investigators assign individuals or subjects to the two treatments in a random fashion, this
is referred to as .

ANS: observational, randomized controlled experiment.

PTS: 1

5. Provided that the sample sizes m and n of two independent samples X and Y are both large (i.e., m> 40 and n> 40),
then a confidence interval for the difference between the two population means, with a confidence level of
approximately is , where the values of the population variances are unknown.


ANS:
PTS: 1

,6. Provided that at least one of the sample sizes m and n of two independent samples X and Y is small, and that the
corresponding populations are both normally distributed with unknown values of the population variances, then a
confidence interval for the difference between the two population means, with a confidence level of
is .

, ANS:

PTS: 1

7. The pooled t procedures are alternatives to the two-sample t procedures for situations in which not only the two
population distributions are assumed to be but also they have equal .

ANS: normal, variances

PTS: 1

8. The degrees of freedom associated with the pooled t test, based on sample sizes m and n, is given by .

ANS:

PTS: 1

9. The pooled t confidence interval for estimating with confidence level using two independent
samples X and Y with sizes m and n is given by .


ANS:
PTS: 1

10. The weighted average of the variances of two independent samples is referred to as the of
(the common variance of the two population variances), and is denoted by .

ANS: pooled estimator,

PTS: 1

11. The number of degrees of freedom for a paired t test, where the data consists of n independently pairs
is .

ANS: n-1

PTS: 1

12. The rejection region for level .025 paired t test in testing is , where the
data consists of 12 independent pairs.

ANS:

PTS: 1

13. A 90% confidence interval for the true mean difference in paired data consisting of n independent pairs, is
determined by the formula .

, ANS:

PTS: 1

14. In testing where is the true mean difference in paired data consisting of 16
independent pairs, the value of the test statistic is found to be 2.8. Then the P-value is approximately .

ANS: .014

PTS: 1

15. Let with X and Y independent variables, and let
is an estimator of

ANS: unbiased

PTS: 1

16. In testing denote the two population properties, the P-
value is found to be .0715. Then at .05 level, should .

ANS: not be rejected

PTS: 1

17. In testing denote the two population proportions, the
following summary statistics are given: m = 400, x = 140, n = 500 and y = 160. Then the value of the test statistic is z
= .

ANS: .949

PTS: 1

18. In testing where denote the two population
proportions, the standardized variable is an estimate of the common value of

and m and n are the two sample sizes, has approximately a standard normal distribution when .

ANS: is true

PTS: 1

19. If are independent random variables with degrees of freedom respectively, then
the random variable has an F distribution.

ANS: chi-squared

PTS: 1

Geschreven voor

Instelling
Vak

Documentinformatie

Geüpload op
8 november 2025
Aantal pagina's
32
Geschreven in
2025/2026
Type
Tentamen (uitwerkingen)
Bevat
Vragen en antwoorden

Onderwerpen

€7,18
Krijg toegang tot het volledige document:

100% tevredenheidsgarantie
Direct beschikbaar na je betaling
Lees online óf als PDF
Geen vaste maandelijkse kosten


Ook beschikbaar in voordeelbundel

Maak kennis met de verkoper

Seller avatar
De reputatie van een verkoper is gebaseerd op het aantal documenten dat iemand tegen betaling verkocht heeft en de beoordelingen die voor die items ontvangen zijn. Er zijn drie niveau’s te onderscheiden: brons, zilver en goud. Hoe beter de reputatie, hoe meer de kwaliteit van zijn of haar werk te vertrouwen is.
Stuviaaa Grand Canyon University
Volgen Je moet ingelogd zijn om studenten of vakken te kunnen volgen
Verkocht
808
Lid sinds
4 jaar
Aantal volgers
521
Documenten
1504
Laatst verkocht
4 dagen geleden

4,2

176 beoordelingen

5
113
4
27
3
13
2
5
1
18

Populaire documenten

Recent door jou bekeken

Waarom studenten kiezen voor Stuvia

Gemaakt door medestudenten, geverifieerd door reviews

Kwaliteit die je kunt vertrouwen: geschreven door studenten die slaagden en beoordeeld door anderen die dit document gebruikten.

Niet tevreden? Kies een ander document

Geen zorgen! Je kunt voor hetzelfde geld direct een ander document kiezen dat beter past bij wat je zoekt.

Betaal zoals je wilt, start meteen met leren

Geen abonnement, geen verplichtingen. Betaal zoals je gewend bent via iDeal of creditcard en download je PDF-document meteen.

Student with book image

“Gekocht, gedownload en geslaagd. Zo makkelijk kan het dus zijn.”

Alisha Student

Veelgestelde vragen