MIP2601
ASSIGNMENT 3 2025
UNIQUE NO. 818210
DUE DATE: 14 JULY 2025
, Mathematics for Intermediate Phase teachers III
Question 1: Inductive Reasoning [25 Marks]
1.1 Angle Construction and Reasoning (10 marks)
Using only a straightedge (ruler) and without a protractor:
a. 30°:
Construct an equilateral triangle (60° at each angle). Then bisect one angle to get 30°.
Reasoning: Equilateral triangle angles = 60°, bisect = 30°.
b. 45°:
Construct a square; each corner is 90°, bisect it to get 45°.
Reasoning: Right angle bisected gives 45°.
% Error: Calculate as above.
c. 100°:
Draw 90° and then estimate 10° more, using knowledge that 10° is about 1/9 of 90°.
Reasoning: Estimation from a right angle.
d. 300°:
Since 360° − 60° = 300°, construct 60° and go in the opposite direction from the full
circle.
Reasoning: Full turn minus 60° = 300°.
e. 67°:
Estimate between 60° and 70°, using a 60° triangle and adjusting.
Reasoning: Approximation based on familiar angles.
1.2 Perpendicular Lines Diagram (8 marks)
ASSIGNMENT 3 2025
UNIQUE NO. 818210
DUE DATE: 14 JULY 2025
, Mathematics for Intermediate Phase teachers III
Question 1: Inductive Reasoning [25 Marks]
1.1 Angle Construction and Reasoning (10 marks)
Using only a straightedge (ruler) and without a protractor:
a. 30°:
Construct an equilateral triangle (60° at each angle). Then bisect one angle to get 30°.
Reasoning: Equilateral triangle angles = 60°, bisect = 30°.
b. 45°:
Construct a square; each corner is 90°, bisect it to get 45°.
Reasoning: Right angle bisected gives 45°.
% Error: Calculate as above.
c. 100°:
Draw 90° and then estimate 10° more, using knowledge that 10° is about 1/9 of 90°.
Reasoning: Estimation from a right angle.
d. 300°:
Since 360° − 60° = 300°, construct 60° and go in the opposite direction from the full
circle.
Reasoning: Full turn minus 60° = 300°.
e. 67°:
Estimate between 60° and 70°, using a 60° triangle and adjusting.
Reasoning: Approximation based on familiar angles.
1.2 Perpendicular Lines Diagram (8 marks)
