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Answers
Law of Definite Proportions - ✔✔all samples of a given compound have the
same proportions of their constituent element
Mass Number - ✔✔A: protons + neutrons
Atomic Number - ✔✔Z: Number of Protons
Density= - ✔✔Mass/Volume
Frequency (v)= - ✔✔Speed of light (c)/wavelength
Electron Groups= 2
Bonding Groups= 2
Lone Pairs= 0 - ✔✔EG= linear
MG= linear
Bond Angle= 180
Electron Groups= 3
Bonding Groups= 3
Lone Pairs= 0 - ✔✔EG= trigonal planar
MG= trigonal planar
Page 1 of 16
COPYRIGHT©JOSHCLAY 2025/2026. YEAR PUBLISHED 2025. COMPANY REGISTRATION NUMBER:
619652435. TERMS OF USE. PRIVACY STATEMENT
,Bond Angle= 120
Electron Groups= 3
Bonding Groups= 2
Lone Pairs= 1 - ✔✔EG= trigonal planar
MG= bent
Bond Angle= <120
Electron Groups= 4
Bonding Groups= 4
Lone Pairs= 0 - ✔✔EG= tetrahedral
MG= tetrahedral
Bond Angle= 109.5
Electron Groups= 4
Bonding Groups= 3
Lone Pairs=1 - ✔✔EG= tetrahedral
MG=trigonal planar
Bond Angle= <109.5
Electron Groups= 4
Bonding Groups= 2
Page 2 of 16
COPYRIGHT©JOSHCLAY 2025/2026. YEAR PUBLISHED 2025. COMPANY REGISTRATION NUMBER:
619652435. TERMS OF USE. PRIVACY STATEMENT
, Lone Pairs= 2 - ✔✔EG= tetrahedral
MG= Bent
Bond Angle= <109.5
Electron Groups= 5
Bonding Groups= 5
Lone Pairs= 0 - ✔✔EG= trigonal bipyramidal
MG= trigonal bipyramidal
Bond Angle= 120 (equatorial) 90 (axial)
Electron Groups= 5
Bonding Groups= 4
Lone Pairs= 1 - ✔✔EG= trigonal bipyramidal
MG= seesaw
Bond Angle= <120 (equatorial) <90 (axial)
Electron Groups= 5
Bonding Grops= 3
Lone Pairs= 2 - ✔✔EG= trigonal bipyramidal
MG= t-shaped
Bond Angle= <90
Page 3 of 16
COPYRIGHT©JOSHCLAY 2025/2026. YEAR PUBLISHED 2025. COMPANY REGISTRATION NUMBER:
619652435. TERMS OF USE. PRIVACY STATEMENT