CHEM 103 Module 6 Exam Portage Learning
Questions and Verified Answers,100% Guaranteed Pass
CHEM 103
MODULE 6 2025/2026
Question 1
Not yet graded / 10 pts
Click this link to access the Periodic Table. This may be helpful throughout the
exam.
List and explain if each of the following solutions conducts an electric current:
sodium chloride (NaCl), hydrochloric acid (HCl) and sugar (C6H12O6).
Sodium chloride (NaCl) is an ionic compound and conducts since it forms ions in
solution. Hydrochloric acid (HCl) is a polar compound and conducts since it
forms ions in solution. Sugar (C6H12O6) is a molecular compound but does not form
ions in solution so it does not conduct.
Question 2
Not yet graded / 10 pts
Explain how and why the presence of a solute affects the boiling point of a solvent.
The presence of a solute raises the boiling point of a solvent by lowering the vapor
pressure of the solvent. With this lower vapor pressure, more heat (a higher
boiling point) is required to raise the vapor pressure to atmospheric pressure.
Question 3
Not yet graded / 10 pts
Click this link to access the Periodic Table. This may be helpful throughout the
exam.
, Rank and explain how the freezing point of 0.100 m solutions of the following ionic
electrolytes compare, List from lowest freezing point to highest freezing point.
GaCl3, Al2(SO4)3, NaI, MgCl2
Your Answer:
Al2(SO4)3 -> 2Al3+, 3SO4 -2 = = 5 ions -> most ions = lowest freezing point
GaCl2 -> Ga3+, Cl- = 4 ions
MgCl2 = 3 ions
NaI = 2 ions - > least ions = highest freezing point
GaCl3 → Ga+3 + 3 Cl
-
∆tf = 1.86 x 0.1 x 4 =
3rd lowest FP
3 SO4
Al2(SO4)3 → 2 Al+3 + -3
∆tf = 1.86 x 0.1 x 5 =
lowest FP
NaI → Na+ + I- ∆tf = 1.86 x 0.1 x 2
= highest FP
MgCl2 → Mg+2 + 2 Cl- ∆tf = 1.86 x 0.1 x 3
= 2nd lowest FP
FP: Al2(SO4)3 < GaCl3 < MgCl2 < NaI
Question 4
Not yet graded / 10 pts
Click this link to access the Periodic Table. This may be helpful throughout the
exam.
Show the calculation of the mass percent solute in a solution of 20.8 grams of
Ba(NO3)2 in 400 grams of water. Report your answer to 3 significant figures.
Questions and Verified Answers,100% Guaranteed Pass
CHEM 103
MODULE 6 2025/2026
Question 1
Not yet graded / 10 pts
Click this link to access the Periodic Table. This may be helpful throughout the
exam.
List and explain if each of the following solutions conducts an electric current:
sodium chloride (NaCl), hydrochloric acid (HCl) and sugar (C6H12O6).
Sodium chloride (NaCl) is an ionic compound and conducts since it forms ions in
solution. Hydrochloric acid (HCl) is a polar compound and conducts since it
forms ions in solution. Sugar (C6H12O6) is a molecular compound but does not form
ions in solution so it does not conduct.
Question 2
Not yet graded / 10 pts
Explain how and why the presence of a solute affects the boiling point of a solvent.
The presence of a solute raises the boiling point of a solvent by lowering the vapor
pressure of the solvent. With this lower vapor pressure, more heat (a higher
boiling point) is required to raise the vapor pressure to atmospheric pressure.
Question 3
Not yet graded / 10 pts
Click this link to access the Periodic Table. This may be helpful throughout the
exam.
, Rank and explain how the freezing point of 0.100 m solutions of the following ionic
electrolytes compare, List from lowest freezing point to highest freezing point.
GaCl3, Al2(SO4)3, NaI, MgCl2
Your Answer:
Al2(SO4)3 -> 2Al3+, 3SO4 -2 = = 5 ions -> most ions = lowest freezing point
GaCl2 -> Ga3+, Cl- = 4 ions
MgCl2 = 3 ions
NaI = 2 ions - > least ions = highest freezing point
GaCl3 → Ga+3 + 3 Cl
-
∆tf = 1.86 x 0.1 x 4 =
3rd lowest FP
3 SO4
Al2(SO4)3 → 2 Al+3 + -3
∆tf = 1.86 x 0.1 x 5 =
lowest FP
NaI → Na+ + I- ∆tf = 1.86 x 0.1 x 2
= highest FP
MgCl2 → Mg+2 + 2 Cl- ∆tf = 1.86 x 0.1 x 3
= 2nd lowest FP
FP: Al2(SO4)3 < GaCl3 < MgCl2 < NaI
Question 4
Not yet graded / 10 pts
Click this link to access the Periodic Table. This may be helpful throughout the
exam.
Show the calculation of the mass percent solute in a solution of 20.8 grams of
Ba(NO3)2 in 400 grams of water. Report your answer to 3 significant figures.
