5/y-3 = y+7/2y - 6 + 1
Solution
move the fraction on the right side to the left side to get 5/(y-3) -(y+7)/(2y-6) = 1
if you notice the denominator of the 2nd fraction can be reducedto (y+7)/(2(y-3)) so to get a
common denominator for the 2 fractions you shouldmultiply the first fraction top and bottom by
2 to get 10/(2(y-3)) add the two fractions together to get [10 - (y + 7)]/(2y - 6) = 1 Cross
multiply to get 10 - (y+7) = 2y - 6 distribute the negative 10 - y - 7 = 2y - 6 solve for y 3 = y
but since y cannot = 3 because you cant divide by zero there is noanswer
Solution
move the fraction on the right side to the left side to get 5/(y-3) -(y+7)/(2y-6) = 1
if you notice the denominator of the 2nd fraction can be reducedto (y+7)/(2(y-3)) so to get a
common denominator for the 2 fractions you shouldmultiply the first fraction top and bottom by
2 to get 10/(2(y-3)) add the two fractions together to get [10 - (y + 7)]/(2y - 6) = 1 Cross
multiply to get 10 - (y+7) = 2y - 6 distribute the negative 10 - y - 7 = 2y - 6 solve for y 3 = y
but since y cannot = 3 because you cant divide by zero there is noanswer
