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MAT1503 Assignment 3 (ANSWERS) 2023 (692080)

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Complete solutions to MAT1503 Assignment 3 2023 with detailed explanations to each question. Achieve Academic Excellence with Our A+ Assignment Assistance! Trust our expert team to deliver top-quality assignment solutions tailored to your needs. With extensive knowledge, thorough research, attention to detail, and timely delivery, we guarantee exceptional results. Your success is our priority, ensuring confidentiality and satisfaction. Take the stress out of assignments and secure your A+ grade with our reliable service.

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MAT1503
Assignment 3
(692080)
DUE: 26 June 2023 at 2:00PM




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,Given,




If the determinant of the matrix is zero,

it implies that the three rows of the matrix are linearly dependent, meaning that one row
can be expressed as a linear combination of the other two rows

In terms of points, this means that the three points (a, b), (c, d), and (e, f) lie on the same
line.

Expand the determinant of the matrix using the first row:




Simplifying the expression



Rearrange the terms to group the variables




The equationa(d−f)+b(e−c)+c(f−d)=0 implies that the three terms are equal to zero, which
means that the three expressions (d−f),(e−c),and(f−d)are all zero

Since each of these expressions evaluates to zero, it implies that d=f,e=c,andf=d This
shows that the points (a,b),(c,d),and(e,f) lie on the same line, making them collinear.

hence, we have proved that points (a, b), (c, d), and (e, f) are collinear whenever the
determinant of the matrix is equal to zero.


Explanation:
we used the concept of linear dependence

, slope=b₂−b₁/a₂−a₁

Then, using the point-slope form of the equation of a line, we have:

y−b₁=slope×(x−a₁)
y=slope×(x−a₁)+b₁

Substituting the value of the slope, the equation becomes

y=(b₂−b₁/a₂−a₁)×(x−a₁)+b₁

This is the equation of the line passing through the distinct points (a₁, b₁) and (a₂, b₂)
Explanation:
Using the slope formula we find the slope and then putting all value in the equation
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