core concepts
Thermodynamics
, jee mains important concept and other useful for
comprtitive exams
calorimetry:
thermal capacity=dQ/dT
sphecific heat capacity(s/p)=dQ/dT.m
m=mass
Q=msdT
water equivalent=ms(in grams)
mechanical equivalent of heat( J)
w=JQ. w= joules
Q=calories
latent heat =Q/M. ( latent heat of fusion=80cal/g)
=0.335×10⁶J/Kg
latent heat of vapourisation=540 cal/g
=2.26×10⁶J/Kg
cooling curve.
oA= solid (ICE)
slope of oA=1/s.p heat
s.p heat =1/slope of oA
AB =solid+liquid
, slope of AB=1/0 BC=liquid
=infinity
s.p heat of liquid=1/slope of BC
CD= mixture of liquid+gas
slope of CD=infinity
DE= sp.heat of gas=1/slope of DE
length of AB= latent heat of fusion
length of CD=latent heat of vapourisation
temp
O time
principle of calorie or principle of method of mixtures
Heat lost by hot bodies = heat gained by cold bodies
Thermodynamics
, jee mains important concept and other useful for
comprtitive exams
calorimetry:
thermal capacity=dQ/dT
sphecific heat capacity(s/p)=dQ/dT.m
m=mass
Q=msdT
water equivalent=ms(in grams)
mechanical equivalent of heat( J)
w=JQ. w= joules
Q=calories
latent heat =Q/M. ( latent heat of fusion=80cal/g)
=0.335×10⁶J/Kg
latent heat of vapourisation=540 cal/g
=2.26×10⁶J/Kg
cooling curve.
oA= solid (ICE)
slope of oA=1/s.p heat
s.p heat =1/slope of oA
AB =solid+liquid
, slope of AB=1/0 BC=liquid
=infinity
s.p heat of liquid=1/slope of BC
CD= mixture of liquid+gas
slope of CD=infinity
DE= sp.heat of gas=1/slope of DE
length of AB= latent heat of fusion
length of CD=latent heat of vapourisation
temp
O time
principle of calorie or principle of method of mixtures
Heat lost by hot bodies = heat gained by cold bodies
