Solutions Manual for Engineering Mechanics: Statics (4th Edition by Pytel) – Complete Problem Solutions

All10 Chapters Covered
u u u




SOLUTIONS

, Contents

Chapter 1 .............................................................................................................................. 1
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Chapter 2 ............................................................................................................................ 23
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Chapter 3 ............................................................................................................................ 64
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Chapter 4 ............................................................................................................................ 93
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Chapter 5 .......................................................................................................................... 199
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Chapter 6 .......................................................................................................................... 237
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Chapter 7 .......................................................................................................................... 309
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Chapter 8 .......................................................................................................................... 361
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Chapter 9 .......................................................................................................................... 438
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Chapter 10 ........................................................................................................................ 486
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SeSiesim
smiciii csiosloaltaiotinon

, Chapter 1 u




1.1




1.2
u u


W = ggV = (7850)(9.81) π(0.042)(0.110) = 42.58 N
u u u u u u u u




0.2248 lb
= 9.57 lb (
u




W = 42.58 N × u u u



1.0 N
u u u u

u




1.3
4.448 N u 0.3048 m u



(a) 400 lb·ft = 400 lb·ft × = 542 N·m (
1.0 lb
u u u u u


1.0 ft
u u u

u



×
u




u




6m 0.3048 ft 1.0 mi 3600 s
× × × = 1.247 mi/h (
u u u u



(b) 6 m/s =
s 1.0 m 5280 ft
u u u u u
u u

u u u u u
1.0 h u




20 lb 4.448 N 1.0 in.2
×
u



(c) 20 lb/in.2 = = 1.379 × 105 N/m2
u u




1.0 lb
u
u u u u u u u


in.2 u
645.2 × 10—6 m2 u



= 137.9 kPa ( ×
u
u u


u u u


u




500 slug 14.593 kg 39.37 in.
(d) 500 slug/in. = × × = 2.87×105 kg/m (
u u u u u u




in. 1.0 slug 1.0 m
u u u u u u u u u u u


u u




1.4
30 mi 5280 ft 0.3048 m 1.0 gal
× × ×
u u u u



30 mi/gal = u u u


gal 1.0 mi 1.0 ft u u 3.785 L u




= 12 760 m/L = 12.76 km/L (
u u u u u u u




1.5
m 2 kg · m2 kg · m
u u u


1 u




(a) E = (1000 kg) 6 = 18 000 (m)
u u u u


= 18 000 s2
2
u u u


s s2
u u u u

u




= 18 000 N·m = 18 kN·m (
u u u u u u u




0.2248 lb 3.281 ft
×
u




(b) E = 18 000 N·m = 18 000 N·m ×
u


u u u u u u u u u u

1.0 N u
1.0 m
= 13 280 lb·ft (
u



u u u u




@@
SeSiesim iciii csiosloaltaiotinon
s m 1
© 2017 Cengage Learning®. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.
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, 1.6




1.7




1.8
8 mm 1.0 m 1.0 µs
× × = 8000 m/s (
u u u


(a) 8 mm/µs =
10—6
u u u u u



µs 1000 mm u
u
s

8000 m 3.281 ft 1.0 mi 3600 s
× × = 17 900 mi/h(
u u u u



(b) 8000 m/s =
s 1.0 m 5280 ft
u u u u u u
u u

u u u
1.0 h
×
u




1.9
u




1.10

u u u


G u u


= [A] G2 + [B][G][T]
u u




T2
u u u u u u


u


u u u u u u u


1 1
) [A] = ( [B] = 3 (
u u u




GT 2 T
u u


u u




1.11
(a) The dimensions of x = At2 — Bvt are
u u u u u u u u




[G] = [A][T2] — [B][GT—1][T]u u u u u u u u




)[A] = u u u [GT—2] ( u u [B] = [1] (dimensionless) (
u u u u




@@
SeSiesim iciii csiosloaltaiotinon
s m 2
© 2017 Cengage Learning®. May not be scanned, copied or duplicated, or posted to a publicly accessible website, in whole or in part.
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