INSTRUCTOR’S SOLUTIONS
MANUAL
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E
DEVELOPMENTAL MATHEMATICS:
D
COLLEGE MATHEMATICS AND
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INTRODUCTORY ALGEBRA
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TENTH EDITION
N
N
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S
Marvin L. Bittinger
E
Indiana University Purdue University Indianapolis
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Judith A. Beecher
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, Contents
Chapter 1 . . . . . . . . . . . . . . . . . . . . . . . . . . . 1
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Chapter 2 . . . . . . . . . . . . . . . . . . . . . . . . . . 29
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Chapter 3 . . . . . . . . . . . . . . . . . . . . . . . . . . 53
Chapter 4 . . . . . . . . . . . . . . . . . . . . . . . . . . 73
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Chapter 5 . . . . . . . . . . . . . . . . . . . . . . . . . . 101
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Chapter 6 . . . . . . . . . . . . . . . . . . . . . . . . . . 115
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Chapter 7 . . . . . . . . . . . . . . . . . . . . . . . . . . 133
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Chapter 8 . . . . . . . . . . . . . . . . . . . . . . . . . . 149
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Chapter 9 . . . . . . . . . . . . . . . . . . . . . . . . . . 175
Chapter 10 . . . . . . . . . . . . . . . . . . . . . . . . . . 209
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Chapter 11 . . . . . . . . . . . . . . . . . . . . . . . . . . 231
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Chapter 12 . . . . . . . . . . . . . . . . . . . . . . . . . . 257
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Chapter 13 . . . . . . . . . . . . . . . . . . . . . . . . . . 291
Chapter 14 . . . . . . . . . . . . . . . . . . . . . . . . . . 319
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Chapter 15 . . . . . . . . . . . . . . . . . . . . . . . . . . 335
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Copyright © 2020 Pearson Education, Inc.
,Chapter 1
Whole Numbers
44. 200,017
Exercise Set 1.1 46. 2,793,000,000
RC2. In 615,702, the number 615 is in the thousands period. 48. 32 > 0
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RC4. The number 721 is written in standard notation. 50. 28 > 18
CC2. A word name for 42,000,000 is forty-two million. 52. 77 < 117
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CC4. A word name for 18,000,000,000 is eighteen billion. 54. 999 > 997
D
CC6. A word name for 40,000,000,000,000 is forty trillion. 56. 345 < 456
2. 5 ten thousands 58. 12 < 32
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4. 5 hundred thousands 60. 1, 014, 023 > 758, 708, or 758, 708 < 1, 014, 023
62. 843, 393 > 842, 583, or 842, 583 < 843, 393
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6. 9
8. 3 64. All digits are 9’s. Answers may vary. For an 8-digit read-
out, for example, it would be 99,999,999. This number has
10. 6 thousands + 6 hundreds + 8 tens + 8 ones
N three periods.
12. 1 thousand + 7 hundreds + 8 tens + 6 ones
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14. 3 ten thousands + 8 thousands + 4 hundreds + 5 tens + Exercise Set 1.2
3 ones
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RC2. In the subtraction 18 − 5 = 13, the number 5 is the
16. 1 hundred thousand + 3 ten thousands + 5 thousands + subtrahend.
0 hundreds + 8 tens + 0 ones, or 1 hundred thousand +
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3 ten thousands + 5 thousands + 8 tens RC4. The distance around an object is its perimeter.
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18. 1 billion + 2 hundred millions + 6 ten millions + 6 9 10
millions + 8 hundred thousands + 8 ten thousands + 3 CC2. ✥1✥
0 /0
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thousands + 5 hundreds + 9 tens + 8 ones − 7
9 3
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20. 3 hundred millions + 2 ten millions + 3 millions + 9 hun-
dred thousands + 9 ten thousands + 5 thousands + 5
10
hundreds + 2 tens + 8 ones CC4. / /
1 0 00
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22. Forty-eight − 4 00
6 00
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24. Forty-five thousand, nine hundred eighty-seven
9 9 10
✥
26. One hundred eleven thousand, thirteen CC6. 1✥
✥ 0 0 /0
− 9 9 9
28. Forty-three billion, five hundred fifty million, six hundred
1
fifty-one thousand, eight hundred eight
2. 1521
30. Ninety-nine thousand, eight hundred fifty-three
+ 348
32. Two hundred twenty-six million, one thousand, two hun- 1869
dred eighty-eight 1
4. 73
34. 354,702 +69
36. 17,112 1 42
1
38. 19,610,439 6. 7 503
+ 2 683
40. 700,000,000
1 0, 1 8 6
42. 26,000,000,000
Copyright
c 2020 Pearson Education, Inc.
, 2 Chapter 1: Whole Numbers
1
8. 3654 28. 526
+2700 −323
6354 203
1
18
10. 271 6 /
8 15
+3338 30. / /
7 9 5/
3609 −3 9 8
1 3 9 7
12. 280
10
+ 3 4, 9 0 2 2 /
0 16
3 5, 1 8 2 32. / /
3 1 6/
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1 1 1 −2 4 7
14. 4 5, 8 7 9 6 9
+ 2 1, 7 8 6
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17
6 7, 6 6 5 7 /
7 17
1 1 1 1 34. / /
8 8 7/
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16. 9 9, 9 9 9 −6 9 8
+ 112 1 8 9
1 0 0, 1 1 1
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3 12
1 1 1 1
18. 4 2, 4 8 7 36. 3/
4 2/
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8 3, 1 4 1 −21 7
+3 6, 7 1 2 12 5
1 6 2, 3 4 0
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38.
13 12
5 /
11
2 2 / /
6 4 3/ 1
/
20. 9 8 9 −2 8 9 6
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5 6 6 3 5 3 5
8 3 4
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9 2 0 12 15
7 /
14
+7 0 3 40. / /
8 3 6/ 4
/
4 0 1 2 −5 3 7 5
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2 9 8 9
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22. Perimeter = 14 mi + 13 mi + 8 mi + 10 mi + 47 mi +
22 mi 11 13
8 /
11
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We carry out the addition.
42. / /
9 2 4/ 1
/
2 −5 6 4 3
14
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3 5 9 8
13
6 15
8
7 /
/ 5 83
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10 44. −3 6 41
47
3 9 42
+22
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1 14 11 11
5 1 /
/ 1 12
The perimeter of the figure is 114 mi. 46. 1/6, /
2 2
/ 2/
24. 90 ft + 90 ft + 90 ft + 90 ft = Perimeter − 5, 8 8 8
1 0, 3 3 4
We carry out the addition.
11
9 0 2 /
1 11 8 14
9 0 48. //
3 2, 1
/ /
9 4
/
9 0 − 2 9, 2 3 6
+9 0 2 9 5 8
3 6 0
The batter travels 360 ft when a home run is hit. 8 10
50. 9 0
/ /
26. 87
−34 −7 8
53 1 2
Copyright
c 2020 Pearson Education, Inc.
