Calculus in Higher Dimensions

University of South Africa

Aquí están los mejores recursos para pasar Calculus in Higher Dimensions. Encuentra Calculus in Higher Dimensions guías de estudio, notas, tareas, y mucho más.

All 32 resultados

Ordenador por

MAT2615 Assignment 4 (COMPLETE ANSWERS) 2025 - DUE 2025
  • MAT2615 Assignment 4 (COMPLETE ANSWERS) 2025 - DUE 2025

  • Examen • 13 páginas • 2025
  • 1. (Section 14.6, Chapter 17) Let V be a region in R3 bounded above by the hemisphere z = p1 − x2 ��� y2 and below by the cone z = px2 + y2 − 1. Let S be the surface of V (consisting of the hemisphere on top and the paraboloid below). (a) Compute the volume of V using spherical coordinates. (10) (b) Sketch S and the XY-projection of S. (3) (c) Use a surface integral to evaluate the area of S. (8) [21] 2. (Chapter 17,Section 19.1) Consider the intersection R between the two circles x2 +...
    (0)
  • $2.50
  • + aprende más y mejor
MAT2615 Assignment 3 2025 (Correct Answers) Due 2025 MAT2615 Assignment 3 2025 (Correct Answers) Due 2025
  • MAT2615 Assignment 3 2025 (Correct Answers) Due 2025

  • Examen • 12 páginas • 2025
  • Unlock your academic potential with the ultimate study resource for MAT2615 Assignment 3 2025 (Correct Answers) Due 2025 This 100% exam-ready assignment come with expert-verified answers, in-depth explanations, and reliable references, meticulously crafted to ensure you grasp every concept with ease. Designed for clarity and precision, these fully solved material is your key to mastering any subject and acing your exams. Don’t just study—study smart. Grab your path to academic success tod...
    (0)
  • $2.79
  • + aprende más y mejor
MAT2615 Assignment 03 2025 (Accurately Solved) Due 2025 MAT2615 Assignment 03 2025 (Accurately Solved) Due 2025
  • MAT2615 Assignment 03 2025 (Accurately Solved) Due 2025

  • Examen • 12 páginas • 2025
  • Unlock Your Academic Potential with the Ultimate Study Companion with MAT2615 Assignment 03 2025 (Accurately Solved) Due 2025 This 100% exam-ready assignment offers expertly verified answers, comprehensive explanations, and credible academic references—meticulously developed to ensure a clear understanding of every concept. Designed with clarity, precision, and academic integrity, this fully solved resource is your key to mastering the subject and excelling in your assessments. Don’t just s...
    (0)
  • $3.91
  • + aprende más y mejor
MAT2615 EXAM PACK 2025 (QUESTIONS & ANSWERS)
  • MAT2615 EXAM PACK 2025 (QUESTIONS & ANSWERS)

  • Examen • 75 páginas • 2025
  • MAT2615 EXAM PACK 2025 QUESTIONS WITH COMPLETE ANSWERS
    (0)
  • $3.00
  • 1x vendido
  • + aprende más y mejor
MAT2615 Assignment 1 (COMPLETE ANSWERS) 2025 - DUE 15 May 2025
  • MAT2615 Assignment 1 (COMPLETE ANSWERS) 2025 - DUE 15 May 2025

  • Examen • 9 páginas • 2025
  • (Sections 2.11,2.12) The parametric equations of two lines are given below: ℓ1 : (x, y, z) = (1, 0, 0) + t(1, 0, 1), t ∈ R ℓ2 : (x, y, z) = (1, 0,−1) + t(0, 1, 1), t ∈ R Calculate the equation of the plane containing these two lines. [5] 2. (Sections 2.11,2.12) MAT2601 Given the two planes 3x + 2y − z − 4 = 0 and −x − 2y + 2z = 0. Find a parametric equation for the intersection. [5] 3. (Sections 2.11,2.12) MAT2611 Find the point of intersection of the line ℓ : (x, y, z) = (5,...
    (2)
  • $2.50
  • 3x vendido
  • + aprende más y mejor
MAT2615 Assignment 4 (COMPLETE ANSWERS) 2025
  • MAT2615 Assignment 4 (COMPLETE ANSWERS) 2025

  • Examen • 8 páginas • 2025
  • 100% TRUSTED WORKINGS, EXPLANATIONS & SOLUTIONS
    (1)
  • $2.50
  • 2x vendido
  • + aprende más y mejor
MAT2615 Assignment 4 (100% COMPLETE ANSWERS) 2025
  • MAT2615 Assignment 4 (100% COMPLETE ANSWERS) 2025

  • Examen • 31 páginas • 2025
  • Calculus in Higher Dimensions - MAT2615 Assignment 4 2025 ;100 % TRUSTED workings, Expert Solved, Explanations and Solutions. For assistance call or W.h.a.t.s.a.p.p us on ...(.+.2.5.4.7.7.9.5.4.0.1.3.2)........... Problem Statement (Section 14.6, Chapter 17) Let VVV be a region in R3mathbb{R}^3R3 bounded above by the hemisphere z=1−x2−y2z = sqrt{1 - x^2 - y^2}z=1−x2−y2 and below by the cone z=x2+y2−1z = sqrt{x^2 + y^2 - 1}z=x2+y2−1. Let SSS be the surface of VVV (cons...
    (0)
  • $2.71
  • 1x vendido
  • + aprende más y mejor
MAT2615 Assignment 4 2025
  • MAT2615 Assignment 4 2025

  • Examen • 17 páginas • 2025
  • MAT2615 Assignment 4 2025 QUESTIONS WITH DETAILED ANSWERS
    (0)
  • $3.00
  • + aprende más y mejor
MAT2615 Assignment 3 (COMPLETE ANSWERS) 2025 - DUE 2025; 100% TRUSTED Complete, trusted solutions and explanations
  • MAT2615 Assignment 3 (COMPLETE ANSWERS) 2025 - DUE 2025; 100% TRUSTED Complete, trusted solutions and explanations

  • Examen • 17 páginas • 2025
  • MAT2615 Assignment 3 (COMPLETE ANSWERS) 2025 - DUE 2025; 100% TRUSTED Complete, trusted solutions and explanations
    (0)
  • $2.50
  • + aprende más y mejor
MAT2615 Assignment 4 (COMPLETE ANSWERS) 2025 - DUE 2025; 100% TRUSTED Complete, trusted solutions and explanations.
  • MAT2615 Assignment 4 (COMPLETE ANSWERS) 2025 - DUE 2025; 100% TRUSTED Complete, trusted solutions and explanations.

  • Examen • 22 páginas • 2025
  • MAT2615 Assignment 4 (COMPLETE ANSWERS) 2025 - DUE 2025; 100% TRUSTED Complete, trusted solutions and explanations.
    (0)
  • $2.50
  • + aprende más y mejor