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TEAS MATHEMATICS EXAM PRACTICE QUESTIONS WITH VERIFIED SOLUTIONS | 2025 UPDATE

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TEAS MATHEMATICS EXAM PRACTICE QUESTIONS WITH VERIFIED SOLUTIONS | 2025 UPDATE

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Subido en
26 de noviembre de 2025
Número de páginas
16
Escrito en
2025/2026
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TEAS MATHEMATICS EXAM PRACTICE
QUESTIONS WITH VERIFIED SOLUTIONS | 2025
UPDATE

◉ A school bake sale sells 4% of its cookies to the first customer.
There are 24 cookies left. How many cookies did the bake sale have
to start? Answer: 25
If x is the total # of cookies then:
x-0.004x=24
(1-0.04)x=24
0.96x=24
x=24/0.96
x=25


◉ A rancher increased her herd of cattle to 360 head from 288 head.
What was the percent increase in cattle? Answer: 25%
To find the percent increase the previous number of cattle, 288 must
be subtracted from the new , higher number, 360. The result should
then be divided by the original number.


(360-288)/288 = x
72/288 =x

,0.25=x
25%


◉ Two trees in Abby's backyards. One tree is 20 feet tall and casts a
shadow 8 feet long. If the second tree shadow at the same time of
the day is 32 feet long, how tall is the 2nd tree? Answer: 80 ft
Let x be the height of the tree then:
x/32 = 20/8 cross multiply
8x/8=640/8 x=80


◉ If sound travels 6,160 feet in. 5.5 feet, how far does in travel in
16.5 seconds? Answer: 18,480
If x is the distance sound travels then:
x/16.5 = 6,160/5.5 cross multiply
5.5x/5.5 101,640/5.5
x=18,480


◉ If $1 US is equivalent to about 6.56 Chinese yuan. A two-bedroom
presidental suite on the top floor of a high-end hotel in Shanghai,
China was listed at 25,000 yuan per night. What is the cost of this
suite per night in US dollars? Answer: 3,810.98
Given x equals the prices per night in US dollars:
25,000/25,000=1/6.56

, 25,000/6.56
x=3,810.98


◉ Sarah wants to put a 1.5 foot-wide painting in the middle of a 12-
foot wide wall. She wants the painting to be exactly horizontally
centered on a wall. What should the distance be, in feet, from either
side of the wall to the edge of the painting? Answer: 5.25
Note that the distance from either side of the painting will be the
same, so let x equal that distance. Then the distance from the left
side of the wall to the paintings x feet, the distance across the
painting horizontally is 1.5 feet, and the distance from the painting
from the right side of the wall is x feet. Altogether, they add up to the
width of the wall, 12 feet. We put this in mathematical form and
solve:
x+1.5+x=12
2x+1.5=12
2x=10.5
x=5.25


◉ The perimeter of a soccer field is 238m. The length is 36m greater
than the width. What are the lengths and width of the soccer field?
Answer: length: 100m; width:64m
2l+2w=238
2(w+36)+2w=238
2w+72+2w=238
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