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HESI A2 Math Practice Test 2025: 50 Essential Questions with Step-by-Step Answers

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Prepare for the HESI A2 Math exam with our 2025 practice test. Features 50 questions covering fractions, decimals, ratios, unit conversions, and algebra with detailed step-by-step solutions. Boost your nursing school admission score! hesi a2 math, nursing entrance exam, hesi practice test, math for nurses, hesi a2 2025, nursing school prep, admission test, fractions decimals, unit conversion, ratios proportions, algebra problems, study guide

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HESI A2 Math
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HESI A2 Math

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Subido en
22 de noviembre de 2025
Número de páginas
39
Escrito en
2025/2026
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Examen
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HESI A2 Math Practice Test – 50 Essential
Questions with Step-by-Step Answers &
Explanations (2025 Edition)


1. 1. QUESTION


Solve for x:

5(4x+3)–4(2x+1)=47

o x=3
o x = 20
o x = 12
o x = 36

Correct
Answer: x=3

Step 1: Apply the distributive law
The first step is to expand the terms 5(4x+3) and 4(2x+1) by distribution
so 5(4x+3)–4(2x+1)=47 becomes
20x+15–8x–4=47
Step 2: Combine like terms
We can then collect like terms in:
20x–8x+15–4=47
12x+11=47
Step 3: Subtract 11 on both sides
We then have to subtract 11 on both sides to isolate the term with x.
12x+11–11=47–11
12x=36
Step 4: Divide by 12 on both sides
We then divide both sides of the equation by 12 to isolate x.
12x12=3612

, 1x=3
We can drop the 1 on the left-hand side to x=3
x=3 is the solution of the equation.
2. 2. QUESTION


Solve for x:

4x2–61=135

o x=7

o x=14
o x=14 or −14
o x=−7 or 7
Incorrect
Answer: x=7 or −7

Step 1: Add 61 on both sides
The first step in solving this problem is to add 61 from both sides of the equation.
4x2–61+61=135+61
You should then carry out the addition of the numbers on both sides of the
equation.
4x2=196
Step 2: Divide by 4 on both sides
We then divide both sides of the equation by 4.

4x24=1964
x2=49
Step 3: Take the square root on both sides
The final step is to take the square root on both sides to solve for x.
x2=49
x2−−√=49−−√
x=7 or –7
If you are asking WHY the -7 gets included as well, it’s because any negative
number squared, is positive.
7×7=49
But so does:
−7×−7=49

, Since both options work, we have to include both.
3. 3. QUESTION


Jordy buys 5 lottery tickets for $17.50.

How much would Jordy pay if he wanted to buy 7 lottery tickets?


o $28
o $24.50
o $25
o $32.50

Correct
Answer: $24.50


This is a proportion problem and the given information allows us to formulate the
equation below:

5tickets$17.50=7ticketsx
where x is the cost of 7 lottery tickets. We can solve this equation by first cross-
multiplying.
5tickets×x=7tickets×17.50$
Carrying out the product on the right-hand side, we get;
5tickets×x=122.5tickets∙$
We can solve for x by dividing both sides of the equation by 5 tickets.
5tickets×x5tickets=122.5tickets∙$5tickets
Carrying out the division, we get a 1 on the left-hand side and a 24.5 on the right-
hand side.
1x=24.5$
We can drop the 1 next to x, to get x=24.5$. It would cost Jordy $24.50 to buy 7
lottery tickets.
4. 4. QUESTION


In 18 hours, 42 trains pass near Emma’s house.

How many trains pass near her house in 12 hours?

, o 28 trains
o 56 trains
o 14 trains
o 2 trains

Correct
Answer: 28 trains


This is a proportion problem and the given information allows us to formulate the
equation below:

42trains18hours=x12hours
where x is the number of trains that pass near Emma’s house in 12 hours. We
can solve this equation by first cross-multiplying.
18hours×x=42trains×12hours
Carrying out the product on the right-hand side, we get:
18hours×x=504trains∙hours
We can solve for x by dividing both sides of the equation by 18 hours.
18hours×x18hours=504trains∙hours18hours
Carrying out the division, we get a 1 on the left-hand side and a 28 on the right-
hand side.
1x=28trains
We can drop the 1 next to x, to get x=28 trains. In 12 hours, 28 trains pass near
Emma’s house.
5. 5. QUESTION


5:12=x:36

What is the value of x?


o x=3
o x=15
o x=12
o x=7.2
Correct
Answer: x=15
$13.49
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