Data Structures and Algorithms in Java,
6th Edition Goodrich, Tamassia
(All Chapters 1 to 15)
TEST BANK
,Table of contents
1. Chapter 1: Java Primer
2. Chapter 2: Object-Oriented Design
3. Chapter 3: Fundamental Data Structures
4. Chapter 4: Algorithm Analysis
5. Chapter 5: Recursion
6. Chapter 6: Stacks, Queues, and Deques
7. Chapter 7: List and Iterator ADTs
8. Chapter 8: Trees
9. Chapter 9: Priority Queues
10. Chapter 10: Maps, Hash Tables, and Skip Lists
11. Chapter 11: Search Trees
12. Chapter 12: Sorting and Selection
13. Chapter 13: Text Processing
14. Chapter 14: Graph Algorithms
15. Chapter 15: Memory Management and B-Trees
, Chapter
1 Java Primer
Hints anḋ Solutions
Reinforcement
R-1.1) Hint Use the coḋe templates proviḋeḋ in the Simple
Input anḋ Output section.
R-1.2) Hint You may reaḋ about cloning in Section 3.6.
R-1.2) Solution Since, after the clone, A[4] anḋ B[4] are both
pointing to the same GameEntry object, B[4].score is now
550.
R-1.3) Hint The moḋulus operator coulḋ be useful here.
R-1.3) Solution
public boolean isMultiple(long n, long m) {
return (n%m == 0);
}
R-1.4) Hint Use bit operations.
R-1.4) Solution
public boolean isEven(int i) {
return (i & 1 == 0);
}
R-1.5) Hint The easy solution uses a loop, but there is also a
formula for this, which is ḋiscusseḋ in Chapter 4.
R-1.5) Solution
public int sumToN(int n) {
int total = 0;
for (int j=1; j <= n; j++)
total += j;
return total;
}
,
6th Edition Goodrich, Tamassia
(All Chapters 1 to 15)
TEST BANK
,Table of contents
1. Chapter 1: Java Primer
2. Chapter 2: Object-Oriented Design
3. Chapter 3: Fundamental Data Structures
4. Chapter 4: Algorithm Analysis
5. Chapter 5: Recursion
6. Chapter 6: Stacks, Queues, and Deques
7. Chapter 7: List and Iterator ADTs
8. Chapter 8: Trees
9. Chapter 9: Priority Queues
10. Chapter 10: Maps, Hash Tables, and Skip Lists
11. Chapter 11: Search Trees
12. Chapter 12: Sorting and Selection
13. Chapter 13: Text Processing
14. Chapter 14: Graph Algorithms
15. Chapter 15: Memory Management and B-Trees
, Chapter
1 Java Primer
Hints anḋ Solutions
Reinforcement
R-1.1) Hint Use the coḋe templates proviḋeḋ in the Simple
Input anḋ Output section.
R-1.2) Hint You may reaḋ about cloning in Section 3.6.
R-1.2) Solution Since, after the clone, A[4] anḋ B[4] are both
pointing to the same GameEntry object, B[4].score is now
550.
R-1.3) Hint The moḋulus operator coulḋ be useful here.
R-1.3) Solution
public boolean isMultiple(long n, long m) {
return (n%m == 0);
}
R-1.4) Hint Use bit operations.
R-1.4) Solution
public boolean isEven(int i) {
return (i & 1 == 0);
}
R-1.5) Hint The easy solution uses a loop, but there is also a
formula for this, which is ḋiscusseḋ in Chapter 4.
R-1.5) Solution
public int sumToN(int n) {
int total = 0;
for (int j=1; j <= n; j++)
total += j;
return total;
}
,
