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Examen

BISC 101 Lab Exam 2 QUESTIONS WITH COMPLETE SOLUTIONS.

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BISC 101 Lab Exam 2 QUESTIONS WITH COMPLETE SOLUTIONS.

Institución
BISC 101
Grado
BISC 101











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Institución
BISC 101
Grado
BISC 101

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Subido en
29 de octubre de 2025
Número de páginas
75
Escrito en
2025/2026
Tipo
Examen
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BISC 101 Lab Exam 2 QUESTIONS WITH
COMPLETE SOLUTIONS.
What is tonicity? Define the three possible types of tonicity.

Tonicity: the capability of a solution to modify the volume of cells by altering their water content



1. Hypotonic



A solution will be hypotonic to a cell if its solute concentration is lower than that inside the cell



2. Hypertonic



A solution will be hypertonic to a cell if its solute concentration is higher than that inside the cell



3. Isotonic



A solution will be isotonic to a cell if its solute concentration is the same as inside the cell

If a cell is placed into hypertonic solution, the net diffusion of water will go where?

The net diffusion of water will be out of the cell

If a cell is placed into hypotonic solution, the net diffusion of water will go where?

The net diffusion of water will be into the cell

If a cell is placed into isotonic solution, the net diffusion of water will go where?

,There will be no net diffusion of water

What is the difference between diffusion and osmosis?

Diffusion is the movement of solutes and solvents to achieve equilibrium throughout the solution



Osmosis is the movement of only solvents (water) over a semipermeable membrane to achieve

equilibrium (membrane impermeable to solutes)

You place a cell in a solution that is very slightly hypertonic. The membrane is

impermeable to all solutes present. You wait a few minutes. After this time, how might you

describe the tonicity? Explain your reasoning.

Because the membrane is impermeable to all solutes, only water will be able to move via

osmosis



Therefore, water will flow out of the cell from an area of lower solute concentration to an area of

higher solute concentration to achieve equilibrium

Consider a hypothetical and fictional solute, Barkamide. The RBC is somewhat permeable

to Barkamide, and the RBC cytoplasm doesn’t normally contain any Barkamide. The RBC

cytoplasm has a total solute concentration of 0.3M. If you place a cell in a 0.3M solution of

Barkmide, what happens?

Solute Movement:

There is a relatively higher concentration of Barkamide outside than Barkamide inside the cell,

but the total solution is initially isotonic (0.3 M inside and outside the cell)

,Because there is more barkamide outside the cell relative to the inside, barkamide will diffuse

into the cell

Water Movement:

Now that barkamide has moved into the cell, there is a higher solute concentration inside the cell

relative to the outside

Water will then diffuse from outside the cell (lower solute concentration) to inside the cell

(higher solute concentration)

Therefore, the influx of water causes the cell to swell, then lyse

Consider a hypothetical and fictional solute, Wrinklamide. The cell is very permeable to

this solute, much more so than another fictional solute, Barkamide. The normal RBC

cytoplasm doesn’t contain any Wrinklamide or Barkamide.

Make a prediction, and give your reasoning. Which would make the cell lyse faster: 0.3M

Barkamide or 0.3M Wrinklamide?

There is no wrinklamide or barkamide in the RBC, so they will both diffuse into the cell.



Because the cell is much more permeable to wrinklamide than barkamide, there should be faster

net diffusion of wrinklamide. Water will then follow wrinklamide at a faster rate, and cause the

cell to lyse faster

Experiment

, We will place RBCs in various solutes (always at 0.3M), and measure the lysis time. This

will allow us to determine whether red blood cells (RBCs) are permeable to the solute, and

if so, to what extent.

Hypothesis:

Solutes that are more nonpolar will cause a faster lysis time, because the membrane is more

permeable to them.

What is the independent variable in this experiment?

What is the dependent variable?

Why is it important that the concentration of each solute be standardized to 0.3M?

Independent Variable:

The solute (because they have different polarities)

Dependent Variable:

Lysis Time

Why is it important that the concentration of each solute be standardized to 0.3M?

If each solute is not standardized to 0.3 M, it will be a confounding variable. If they are not

standardized, both the polarity and concentration of the solutes will be affecting the lysis time,

and we will not be able to conclude anything about the relationship between (only) polarity and

lysis time

Predict which experimental group should have the fastest lysis time. Explain.

(Note: None of these are initially present inside the cell)
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