Week 5 Test - Results
Attempt 1 of 2
Written Oct 5, 2025 11:05 PM - Oct 5, 2025 11:57 PM
Attempt Score 17. - 87.5 %
Overall Grade (Highest Attempt) 17. - 87.5 %
Question 1 point
There is no prior information about the proportion of Americans who support
gun control in 2019. If we want to estimate 97% confidence interval for the
true proportion of Americans who support gun control in 2019 with a 0.27
margin of error, how many randomly selected Americans must be surveyed?
Answer: (Round up your answer to nearest whole number, do not include any
decimals) ___17___
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Z-Critical Value = NORM.S.INV(.985) = 2.17009
n=
2
.5 ∗ .5 ∗ 2.17009
2
.27
, Question 2 point
There is no prior information about the proportion of Americans who support
Medicare-for-all in 2019. If we want to estimate 95% confidence interval for
the true proportion of Americans who support Medicare-for-all in 2019 with a
0.175 margin of error, how many randomly selected Americans must be
surveyed? Answer: (Round up your answer to nearest whole number, do not
include any decimals) ___32___
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Z-Critical Value = NORM.S.INV(.975) = 1.96
n=
2
.5 ∗ .5 ∗ 1.96
2
.175
Question 3 point
The population standard deviation for the height of college basketball players
is 2.4 inches. If we want to estimate 97% confidence interval for the
population mean height of these players with a 0.35 margin of error, how
many randomly selected players must be surveyed? (Round up your answer to
nearest whole number, do not include any decimals.) Answer: ___222___
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Attempt 1 of 2
Written Oct 5, 2025 11:05 PM - Oct 5, 2025 11:57 PM
Attempt Score 17. - 87.5 %
Overall Grade (Highest Attempt) 17. - 87.5 %
Question 1 point
There is no prior information about the proportion of Americans who support
gun control in 2019. If we want to estimate 97% confidence interval for the
true proportion of Americans who support gun control in 2019 with a 0.27
margin of error, how many randomly selected Americans must be surveyed?
Answer: (Round up your answer to nearest whole number, do not include any
decimals) ___17___
Hide question 1 feedback
Feedback
Z-Critical Value = NORM.S.INV(.985) = 2.17009
n=
2
.5 ∗ .5 ∗ 2.17009
2
.27
, Question 2 point
There is no prior information about the proportion of Americans who support
Medicare-for-all in 2019. If we want to estimate 95% confidence interval for
the true proportion of Americans who support Medicare-for-all in 2019 with a
0.175 margin of error, how many randomly selected Americans must be
surveyed? Answer: (Round up your answer to nearest whole number, do not
include any decimals) ___32___
Hide question 2 feedback
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Z-Critical Value = NORM.S.INV(.975) = 1.96
n=
2
.5 ∗ .5 ∗ 1.96
2
.175
Question 3 point
The population standard deviation for the height of college basketball players
is 2.4 inches. If we want to estimate 97% confidence interval for the
population mean height of these players with a 0.35 margin of error, how
many randomly selected players must be surveyed? (Round up your answer to
nearest whole number, do not include any decimals.) Answer: ___222___
Hide question 3 feedback
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