ENGINEERING CIRCUIT ANALYSIS 9TH EDITION HAYT SOLUTION MANUAL

ENGINEERING CIRCUIT ANALYSIS 9TH
EDITION HAYT SOLUTION MANUAL

,1. Convert the following to engineering notation:

(a) 0.045 W = 45 10−3 W = 45 mW

(b) 2000 pJ = 2000 10−12 = 2 10−9 J = 2 nJ

(c) 0.1 ns = 0.110−9 = 100 10−12 s = 100 ps

(d) 39,212 as = 3.9212×104×10-18 = 39.212×10-15 s = 39.212 fs

(e) 3 Ω

(f) 18,000 m = 18 103m= 18 km

(g) 2,500,000,000,000 bits = 2.5 1012 bits = 2.5 terabits
3
 1015 atoms  102 cm 
(h)    = 1021 atoms/m3 (it’s unclear what a “zeta atom” is)
 cm  1 m 
3

,2. Convert the following to engineering notation:

(a) 1230 fs = 1.23103 10−15 = 1.2310−12 s = 1.23 ps

(b) 0.0001 decimeter = 110−4 10−1 = 10 10−6 m = 10 m

(c) 1400 mK = 1.4 103 10−3 = 1.4 K

(d) 32 nm = 32 10−9 m = 32 nm

(e) 13,560 kHz = 1.356 104 103 = 13.56 106 Hz = 13.56 MHz

(f) 2021 micromoles = 2.021103 10−6 = 2.02110−3moles = 2.021 millimoles

(g) 13 deciliters = 1310−1 = 1.3 liters

(h) 1 hectometer = 100 meters

, 3. Express the following in engineering units:

(a) 1212 mV = 1.121 V

(b) 1011 pA = 1011×10-12= 100 mA

(c) 1000 yoctoseconds = 1103 10−24 = 110−21 seconds = 1 zs

(d) 33.9997 zeptoseconds

(e) 13,100 attoseconds =1.3110−15 s = 1.31 fs

(f) 10−14 zettasecond=10-14×1021=107=10×106 s = 10 Ms

(g) 10−5 second = 10 10−6 seconds = 10 s

(h) 10−9 Gs = 10−9 109 = 1 second