ALL 12 CHAPTERS COVERED
SOLUTIONS MANUAL
,Solutions Manual for
Understanding Digital
Signal Processing
Third Edition
Richard G. Lyons
Antoine Trux
Upper Saddle River, NJ • Boston • Indianapolis • San Francisco
New York • Toronto • Montreal • London • Munich • Paris • Madrid
Capetown • Sydney • Tokyo • Singapore • Mexico City
Property of Pearson Education. Not permissible for redistribution.
,The author and publisher have taken care in the preparation of this book, but make no
expressed or implied warranty of any kind and assume no responsibility for errors or
omissions. No liability is assumed for incidental or consequential damages in connection
with or arising out of the use of the information or programs contained herein.
Visit us on the Web: informit.com
Copyright © 2011 Pearson Education, Inc.
This work is protected by United States copyright laws and is provided solely for the use
of instructors in teaching their courses and assessing student learning. Dissemination or
sale of any part of this work (including the World Wide Web) will destroy the integrity of
the work and is not permitted. The work and materials from it should never be made
available to students except by instructors using the accompanying text in their classes.
All recipients of this work are expected to abide by these restrictions and to honor the
intended pedagogical purposes and the needs of their instructors who rely on these
materials.
ISBN-13: 978-0-13-218106-8
ISBN-10: 0-13-218106-1
Text printed in the United States at OPM in Laflin, Pennsylvania.
First printing, December 2010
Property of Pearson Education. Not permissible for redistribution.
, CHAPTER 1 PROBLEMS
Solution: 1.1
The solution is:
100
π ≈ 4 ⋅ ∑ ( −1) ⋅ 1 .
n
2n + 1
n =0
Solution: 1.2
There are many correct solutions to this problem. An example of a continuous
time-domain signal that has a finite number of amplitude values is a
squarewave, such as the x1(t) shown in Figure S1–2(a). Signal x1(t) has only two
possible amplitude values. Of course, any bi-level pulsed signal, like the x2(t)
shown in Figure S1–2(b) is also a correct solution to this problem. Figure S1–
2(c) shows a continuous signal having only three possible amplitude values.
Solution:
Three possible solutions:
x1(t)
1 ...
(a)
0
0 t
x2(t)
1 ...
(b)
0
0 t
x3(t)
2
(c) 1 ...
0
0 t
Figure S1–2
Solution: 1.3
The code: PI = 2*asin(1.0) correctly defines π
under the assumption that the arcsin's angle argument, "(1.0)",
is measured in radians.
Solution: 1.4
Property of Pearson Education. Not permissible for redistribution.
SOLUTIONS MANUAL
,Solutions Manual for
Understanding Digital
Signal Processing
Third Edition
Richard G. Lyons
Antoine Trux
Upper Saddle River, NJ • Boston • Indianapolis • San Francisco
New York • Toronto • Montreal • London • Munich • Paris • Madrid
Capetown • Sydney • Tokyo • Singapore • Mexico City
Property of Pearson Education. Not permissible for redistribution.
,The author and publisher have taken care in the preparation of this book, but make no
expressed or implied warranty of any kind and assume no responsibility for errors or
omissions. No liability is assumed for incidental or consequential damages in connection
with or arising out of the use of the information or programs contained herein.
Visit us on the Web: informit.com
Copyright © 2011 Pearson Education, Inc.
This work is protected by United States copyright laws and is provided solely for the use
of instructors in teaching their courses and assessing student learning. Dissemination or
sale of any part of this work (including the World Wide Web) will destroy the integrity of
the work and is not permitted. The work and materials from it should never be made
available to students except by instructors using the accompanying text in their classes.
All recipients of this work are expected to abide by these restrictions and to honor the
intended pedagogical purposes and the needs of their instructors who rely on these
materials.
ISBN-13: 978-0-13-218106-8
ISBN-10: 0-13-218106-1
Text printed in the United States at OPM in Laflin, Pennsylvania.
First printing, December 2010
Property of Pearson Education. Not permissible for redistribution.
, CHAPTER 1 PROBLEMS
Solution: 1.1
The solution is:
100
π ≈ 4 ⋅ ∑ ( −1) ⋅ 1 .
n
2n + 1
n =0
Solution: 1.2
There are many correct solutions to this problem. An example of a continuous
time-domain signal that has a finite number of amplitude values is a
squarewave, such as the x1(t) shown in Figure S1–2(a). Signal x1(t) has only two
possible amplitude values. Of course, any bi-level pulsed signal, like the x2(t)
shown in Figure S1–2(b) is also a correct solution to this problem. Figure S1–
2(c) shows a continuous signal having only three possible amplitude values.
Solution:
Three possible solutions:
x1(t)
1 ...
(a)
0
0 t
x2(t)
1 ...
(b)
0
0 t
x3(t)
2
(c) 1 ...
0
0 t
Figure S1–2
Solution: 1.3
The code: PI = 2*asin(1.0) correctly defines π
under the assumption that the arcsin's angle argument, "(1.0)",
is measured in radians.
Solution: 1.4
Property of Pearson Education. Not permissible for redistribution.
