Orange Coast College MATH A115: Final Exam

1) :7)x+43 -0 (a) “Tha Phom
- 5\3_’_ 5‘-‘4_9)( F”@i E(am



:> (j = _% _ 6)< (lo)
o


A)m/v‘;/; a )53 (’0> . 3) (5,1-‘){‘
' | s' :
conjugade
= g x {0
vz 3 ,/g/X_ CLV\J“‘%O'R:
.
be“lc)


Ox: 4 (3-0 (300 » ) pptr
X = 100 Soluio . 9 e 24 M: 49TA
E - 3_49'(—4)

. Isx]
o?> X+ :1‘(‘1)
NS/ N q)/i,&o -ll:j+v2 o)

Zxt 1O 3~‘b+\“’ -Hoac
XL—,S (ID) o s
x -+ (5 Y= U2 VEWE 4000
2 (14)
From a % b, W= 1t (i ~9g
__:> X”;aj":q‘ 2 Y
5+t 7 1= Uiz 125
y“: 9 e ol
-+ {2 Y= M4+5 o | )é
e Tz S
X<O’3<O (s x:'\r‘S_, ld:—r A ! =
<0,
y >0 s X:-@,lfl 12 (3251‘;“5:—6—41
x>0, 90 s X2 qm Y- -7 o2
‘X>°,‘d>0‘3 b g J?, Y= vz

, 5)444”{@7{_@“3)1 ~1Y
7,><’Z.
X+d5: x?eGx+9 5

X +6x-x-25+9. 0O
XE4Sx -y = O
(x+D(x-2):0
Xt+1:=0 X-A2=-0

Cx =1 lx =9


6) 2p*+ Bp - 020 0= Ax Yy § 9lx): 5t
3:_ -b* \‘ b"",;{c:c:
(£o 9 Y(x) = F(g(x))
LA
= £(5x <+ Sx)
y=-S2 J(s)l— 4(2)(-10) z /-((Sx‘vtgx)}&f
2(2) -
2 [2ox 4 2 +fl
Y= - 31 | 980 J'-'Bt Wj
A 4