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ASCP Hematology MLT Exam 1 & 2 Questions and Verified Solutions Latest Update This Year

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ASCP Hematology MLT Exam 1 & 2 Questions and Verified Solutions Latest Update This Year

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ASCP Hematology MLT
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Subido en
19 de septiembre de 2025
Número de páginas
86
Escrito en
2025/2026
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Examen
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Page 1 of 86



ASCP Hematology MLT Exam 1 & 2 Questions and

Verified Solutions Latest Update This Year



ANSWER STARTS THEN QUESTION


ANSWER- A;

One of the key characteristics to the identification of Nocardia asteroides is its inability to

hydrolyze casein, tyrosine or xanthine, as shown in this photograph. Nitrates are reduced to

nitrites. Both Nocardia brasiliensis and Actinomadura madurae hydrolyze both casein and

tyrosine; Streptomyces griseus hydrolyzes all three of the substrates.


Illustrated in this photograph is an agar quadrant plate containing casein (A), tyrosine (B),

nitrate (C) and xanthine (D). None of the substrates have been hydrolyzed and nitrate has

been reduced. The most likely identification is:



A. Nocardia asteroides

B. Nocardia brasiliensis

C. Streptomyces griseus

D. Actinomadura madurae

, Page 2 of 86


A;

Since hemoglobin is measured spectrophotometrically on hematology analzyers, interference

from lipemia or icteric specimens can lead to decreased light detected and measured through

the sample and therefore inaccurate hemoglobin results occur.


On an electronic cell counter, hemoglobin determination may be falsely elevated caused by

the presence of:



A. Lipemic or icteric plasma

B. Leukocytopenia or Leukocytosis

C. Rouleaux or agglutinated RBCs

D. Anemia or Polycythemia


False

A patient who has a primarily vegetarian diet will most likely have an alkaline urine pH. A

low-carbohydrate diet as well as the ingestion of citrus fruits can also lead to a more alkaline

urine sample.


A patient who has a primarily vegetarian diet will most likely have an acid urine pH.


A;

During primary hypothyroidism, where a defect in the thryoid gland is producing low levels of

T3 and T4, the TSH level is increased. TSH is released in elevated quantities in an attempt to

stimulate the thryoid to produce more T3 and T4 as part of a feedback mechanism.

, Page 3 of 86


Serum TSH levels five-times the upper limit of normal in the presence of a low T4 and low T3

uptake could mean which of the following:



A. The thyroid has been established as the cause of hypothyroidism

B. The thyroid is ruled-out as the cause of hypothyroidism

C. The pituitary has been established as the cause of hypothyroidism

D. The diagnosis is consistent with secondary hyperthyroidism


B;

The correct answer for this question is 1300 mg/dL. The laboratorian performed a 1:4 dilution

by adding 0.25 mL (or 250 microliters) of patient sample to 750 microliters of diluent. This

creates a total volume of 1000 microliters. So, the patient sample is 250 microliters of the

1000 microliter mixed sample, or a ratio of 1:4. Therefore, the result given by the chemistry

analyzer must be multiplied by a dilution factor of 4. 325 mg/dL x 4 = 1300 mg/dL.


After experiencing extreme fatigue and polyuria, a patient's basic metabolic panel is analyzed in

the laboratory. The result of the glucose is too high for the instrument to read. The laboratorian

performs a dilution using 0.25 mL of patient sample to 750 microliters of diluent. The result

now reads 325 mg/dL. How should the techologist report this patient's glucose result?



A. 325 mg/dL

B. 1300 mg/dL

, Page 4 of 86


C. 975 mg/dL

D. 1625 mg/dL


A;

Conversion of only the slant to a pink color in a Christensen's urea agar slant is produced by

bacterial species that have weak urease activity. The reaction in the slant to the right is often

produced by Klebsiella species, as an example. Strong urease activity is indicated by

conversion of the slant and the butt of the tube to a pink color, as seen in the tube to the left.

The slant only reaction in the right tube may be seen early on if only the slant had been

inoculated; however, with a strong urease producer, both the slant and the butt would turn.

Therefore, the reaction is dependent on the strength of urease activity. If the media had

outdated for a prolonged period, either there would be no reaction or the appearance of only

a faint pink tinge, either in the slant, the butt or both, again depending on the strength of

urease production by the unknown organism.


The urease reaction seen in the Christensen's urea agar slant on the far right indicates:



A. Weak activity

B. Strong activity

C. Slant only inoculated

D. Use of outdated medium


D;

The steps in the PCR process are:
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